Poodle | beautiful command line tool to build API requests | REST library

 by   Clivern Go Version: 2.2.3 License: MIT

kandi X-RAY | Poodle Summary

kandi X-RAY | Poodle Summary

Poodle is a Go library typically used in Web Services, REST applications. Poodle has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A fast and beautiful command line tool to build API requests. Poodle is an interactive command line tool to build and test web APIs based on a pre-built definitions.
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              Poodle has a low active ecosystem.
              It has 136 star(s) with 3 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 2 open issues and 20 have been closed. On average issues are closed in 3 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of Poodle is 2.2.3

            kandi-Quality Quality

              Poodle has no bugs reported.

            kandi-Security Security

              Poodle has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Poodle is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Poodle releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

            Top functions reviewed by kandi - BETA

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Poodle
            Get all kandi verified functions for this library.

            Poodle Key Features

            No Key Features are available at this moment for Poodle.

            Poodle Examples and Code Snippets

            No Code Snippets are available at this moment for Poodle.

            Community Discussions

            QUESTION

            Filter dictionary values by strings in python
            Asked 2021-Jun-10 at 10:07

            Lets say I have a csv file which looks like this:

            ...

            ANSWER

            Answered 2021-Jun-10 at 10:07

            Sure there is. Hope this helps, I've tried to be liberal with comments.

            Source https://stackoverflow.com/questions/67918902

            QUESTION

            Nginx refuses to read custom nginx.config when dockerized
            Asked 2021-Jun-04 at 12:16

            I have created a custom nginx.conf file with simple proxy and I have put it in the root of my project.

            nginx.conf

            ...

            ANSWER

            Answered 2021-Jun-04 at 12:16

            After A LOT of trial and error I have finally managed to make this work. First of all change image inside Dockerfile from: nginxinc/nginx-unprivileged to nginx:alpine

            Second, give the right privileges to the user inside the openshift. Run :

            Source https://stackoverflow.com/questions/67824017

            QUESTION

            (Java) Static member accessed via instance reference with enumerators
            Asked 2021-May-28 at 18:08

            I just started learning Java. IntelliJ is giving me a warning "Static member accessed via instance reference" on line 4. Is it bad, should I fix it, somehow, or should I just ignore it?

            Here is my code:

            ...

            ANSWER

            Answered 2021-May-28 at 18:08

            One issue (which causes others) is that you're hiding the type breed by also having a field of the same name in the same scope.

            That's a very rare problem to have, because the naming conventions of Java usually prevent this kind of clash: Types (classes, interfaces, enums, annotations) are usually written in CamelCase whereas field names start with a lower case letter (fieldName). While this is not technically a "rule" that the compiler enforces, following this makes your code much more readable to others and also avoids the follow-up problem of hiding the type. Also note that constant fields.

            I also made two changes that are good ideas but not really related to your issue:

            • constant values (i.e. most static final fields an enum constants) use ALL_UPPER casing, so I also changed your Breed values
            • I've moved the nested type definition to the top of your Dog class so as not to hide it within all the instance fields. This is just to keep those things that logically belong together close to each other.

            Source https://stackoverflow.com/questions/67742828

            QUESTION

            How can I return more than two variables while in 'Class'?
            Asked 2021-May-13 at 09:27
            def main() :
                a = Dog('Welsh corgi','Max')
                b = Dog('Poodle','Charlie')
                a.add_trick('Wallowing')
                b.add_trick('Running')
                b.add_trick('Jumping')
                print(a)
                print(b)
            
            class Dog:
                def __init__(self, kind, name):
                    self.__kind = kind
                    self.__name = name
            
                def kind(self):
                    self.__kind = kind
            
                def name(self):
                    self.__name = name
                
                def add_trick(self, tricks):
                    self.__tricks = tricks
                    return self.__tricks
            
                def __str__(self):
                    return "%s %s can do %s" %(self.__kind, self.__name, self.__tricks)
            
            main()
            
            ...

            ANSWER

            Answered 2021-May-13 at 09:27

            Make tricks as list and append new tricks in list like this:

            Source https://stackoverflow.com/questions/67516846

            QUESTION

            NodeJS+Express+Nginx - Can't access to domain name without port in URL (404 error)
            Asked 2021-Apr-29 at 23:37

            I have a NODEJS+EXPRESS on my VPS with my domain name but can't access to it.

            https://mydomain1.com => 404 error

            https://mydomain1.com:8080 => Everything works just fine !

            What I want to do : Access to my website without port at url's end like this : https://mydomain1.com

            App folder:

            ...

            ANSWER

            Answered 2021-Apr-29 at 23:14

            Your nginx.conf is using site-enabled/* and you edited sites-available

            Source https://stackoverflow.com/questions/67326142

            QUESTION

            Remove data from class object
            Asked 2021-Apr-23 at 17:29

            I have two class which is Animal and Zoo. Animal for store the data of the type and its sex

            ...

            ANSWER

            Answered 2021-Apr-23 at 17:29

            The problem is this line:

            Source https://stackoverflow.com/questions/67234334

            QUESTION

            404 on Nginx for non-www
            Asked 2021-Apr-06 at 09:01

            My site is running successfully with www.site.com. I've been reading through similar questions and I'm struggling to get the non-www to load.

            Error that I get when requesting site.com rather than www.site.com; 404 Not Found nginx/1.18.0 (Ubuntu)

            On Linode I have A record for site.com & www.

            This is the output from sudo nginx -t

            ...

            ANSWER

            Answered 2021-Apr-06 at 09:01

            The if block inside the certbot managed server block will just capture the www.example.com server name and redirect that to the https server block.

            To do the same for non-www

            configuration file /etc/nginx/sites-enabled/flaskblog:

            Source https://stackoverflow.com/questions/66957869

            QUESTION

            Django nginx 413 Request Entity Too Large
            Asked 2021-Apr-03 at 09:47

            After logining the admin page it is returning 413 error (Request Entity Too Large). Than I added client_max_body_size to my /etc/nginx/nginx.conf and restarted nginx, but it didnt helped :( I know that this error is a common one, but I had to ask this question because there is no more information that about client_max_body_size.

            ...

            ANSWER

            Answered 2021-Apr-03 at 09:47

            Add this in your settings.py file

            Source https://stackoverflow.com/questions/66929579

            QUESTION

            Jetpack Compose – LazyColumn not recomposing
            Asked 2021-Mar-29 at 12:49

            My LazyColumn is not recomposing but the value is getting updated.

            If I scroll down the list and scroll back up I see correct values for the UI

            MainActivity

            ...

            ANSWER

            Answered 2021-Mar-02 at 23:58

            The Flow pups is producing updated values as you can see in my logcat

            Not exactly.

            The Flow is emitting the same List of the same Puppy objects. I believe that Compose sees that the List is the same List object as before and assumes that there are no changes.

            My suggested changes:

            • Make Puppy be an immutable data class (i.e., no var properties)

            • Get rid of changeFlow and have getPuppies() return a stable MutableStateFlow> (or make that just be a public property)

            • In toggleAdoption(), create a fresh list of Puppy objects and use that to update the MutableStateFlow>:

            Source https://stackoverflow.com/questions/66448722

            QUESTION

            Postgres/SQL - Find records that when joined with another table only have ONE joined record specifically
            Asked 2021-Mar-24 at 19:01

            Say I have two tables, where I represent users that have many dogs:

            USERS

            id name 1 aaaa 2 bbbb 3 cccc 4 dddd

            DOGS

            id user_id breed 1 1 poodle 2 1 lab 3 2 lab 4 3 bulldog 5 4 lab 6 4 lab

            I want to find users who only have one and only one dog of 'lab' breed.

            i.e this being the desired result:

            USERS

            id name 2 bbbb

            So in this case, only the dog id 3 matches the requirement because its user only has one dog and it is a lab.

            SELECT users.* FROM users INNER JOIN dogs ON users.id = dogs.user_id WHERE dogs.breed = 'lab'

            where to go from here? I feel like I'm missing something obvious, and that this would be a common requirement but my google-fu is failing me at this moment. Looking for postgres oriented solutions but any help is welcome!

            ...

            ANSWER

            Answered 2021-Mar-24 at 18:35

            Schema and insert statments:

            Source https://stackoverflow.com/questions/66787044

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Poodle

            To upgrade from version 1.x.x to version 2.x.x, It is recommended to delete the remote github gist and poodle will sync changes in a new proper way.

            Support

            Download the latest poodle binary. Also install fzf for better searching otherwise poodle will use a built-in one. Make it executable from everywhere. To list all commands and options. To configure poodle, You will need to provide your github username and oauth token with a gist scope if you need the backup/sync feature. To sync definitions with backend. for now only github gists supported. To create a new service. by default we use https://httpbin.org as service API for testing so change with your web service API.
            Find more information at:

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            CLONE
          • HTTPS

            https://github.com/Clivern/Poodle.git

          • CLI

            gh repo clone Clivern/Poodle

          • sshUrl

            git@github.com:Clivern/Poodle.git

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