fgh | Automate the lifecycle and organization | REST library
kandi X-RAY | fgh Summary
kandi X-RAY | fgh Summary
Automate the lifecycle and organization of your cloned GitHub repositories
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QUESTION
I have a df that have columns with str, int and timestamp columns. However, when I ask for dtypes, I get everything other than timestamp as objects, like below:
...ANSWER
Answered 2022-Mar-12 at 07:46You can use select_dtypes
to exclude all object (string) dtype:
QUESTION
I have the following array:
...ANSWER
Answered 2022-Feb-25 at 10:46If you can ensure your nested arrays will always have two elements then it's quite simple:
QUESTION
I have a list of dicts Where one dict may have more keys than other e.g.
...ANSWER
Answered 2022-Feb-24 at 06:04First convert to DataFrame:
QUESTION
I have a pandas dataframe that has combinations of two id columns such as this:
ID1 ID2 A B A C A D A E B C B D B E C D C E D E F H I K K J G F G H I JHere we have the choose 2 combinations for ABCD, FGH, IJK.
I would like to only keep the rows for the value with the most ID1's for a particular set. For ABCD this would be A, for FGH this would be G, and for IJK this would be I. Resulting in the following:
ID1 ID2 A B A C A D A E I K G F G H I J ...ANSWER
Answered 2022-Feb-16 at 14:41Calculate the count of unqiue values in ID1
, then inside a list comprehension for each set calculate the index of maximum value, finally use these indices to filter the rows in dataframe
QUESTION
i have a problem for the response, i want to change the response API because i need for my mobile APP, the feature have filter object based on date. So i hope you all can help me to solve the problem
i wanna change the response for my API
before:
...ANSWER
Answered 2022-Feb-09 at 07:20$task = Task::where('user_id', auth()->user()->id)->where('date','>',NOW())->orderBy('date','asc')->get();
foreach($task as $item){
$date[] = item->date;
$result = Task::where('user_id', auth()->user()->id)->where('date','=', $date)->get();
}
return response([
'tasks' =>
['date' => $date,
'task' => $task]
],200);
QUESTION
I am reading PDF's and getting data into Dataframe.
EmpID Team_Name Cost No_Emps AA1 Sam 25,689 2 AA2 Tom 78,368 3 AA3 Dick 125,369 5 AA4 Harry 32,658 2 AA5 Joan 22,685 2 Grand Total: 284,769 17 xxx yyy dfg nnn fgh xxx vhg ttt ppp dddThere will be n number of rows after Grand Total, I need to exclude All rows after the EmpID = 'Grand Total'
.
ANSWER
Answered 2022-Jan-26 at 15:03if you have pandas df :
QUESTION
I've come across a problem that similar to the Longest Common Substring problem but with a modification. It's as follows:
A list of strings lst
and a string text
are provided. The string may or may not contain substrings that are present in the list. I need the first longest substring of text
that is inside lst
, considering that you start checking text
from the back. What I mean by first and from the back is that you start iterating over text
from the last word, match the longest substring, and return after you encounter a character that breaks the substring match.
For example, if
...ANSWER
Answered 2022-Jan-26 at 07:52def findstem(arr):
# Determine size of the array
n = len(arr)
# Take first word from array
# as reference
s = arr[0]
l = len(s)
res = ""
for i in range(l):
for j in range(i + 1, l + 1):
# generating all possible substrings
# of our reference string arr[0] i.e s
stem = s[i:j]
k = 1
for k in range(1, n):
# Check if the generated stem is
# common to all words
if stem not in arr[k]:
break
# If current substring is present in
# all strings and its length is greater
# than current result
if (k + 1 == n and len(res) < len(stem)):
res = stem
return res
QUESTION
I am wondering what is the most efficient way to update an object property that is stored in an array with 10k+ items.
For example if I have an array that holds objects like this {name:"", price:"")
I want to replace or more like update the price values if the array contains that element already.
Check if Array contains object with name = x, if so replace the price with the newest price.
I dont want to have duplicate elements in that array so its not getting to big, i figured I should update it if a property value already exists in it.
So far I have tried several ways like with using indexOf, splice, or just for loops. I am wondering what is the best way performance wise to deal with big arrays.
...ANSWER
Answered 2022-Jan-17 at 08:47You've said your starting point is an array, but the most efficient way to do this is with a Map
, not an array, where the key is the name and the value is either the price or an object containing the price (depending on whether you need other information).
But if you're doing this with an array, unless we can build / maintain the array in sorted order (see "With a Sorted Array" below), there's nothing more efficient than just looping through it looking for a previous element with the given name
. filter
isn't the right tool for that (you don't need the array it creates). You'd either write your own loop:
QUESTION
I have the following JSON:
...ANSWER
Answered 2021-Nov-18 at 15:42Don't need to use _entries function, a simple key/value lookup and string interpolation should suffice
QUESTION
I have a table in psql db like below.
...ANSWER
Answered 2021-Nov-09 at 22:05sql
solution could be something like :
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