bun | DC/OS diagnostics bundle analysis tool | Job Orchestrator library

I think this may be what you are looking for... Though you mention not parsing ingredients that are listed twice, though each food, only has an ingredient listed in your object once. Correct me if I am wrong I will refine answer.

You can use for/in loops to get the nested ingredients and their foods. Then use the obj.name to get the name. Through the first for/in loop the key -> i will be the name of the food, then use the second key along witht he first to get the actual .name => obj[i][k].name this will give you the ingredient name.

I also created a couple of divs to palce the food and its buttons wrapped in divs for styling, etc...

You can use conditionals to filter by food if you want to only show a certain type of foods ingredients as buttons.

NOTE: your obj key for the first value is uppercase, this will cause issues when parsing obj[index][key].name, likely that is just a typo...

Use a Service here. Something like this.

HeaderDataService

Rules for memory allocation.

• Do not allocate so much RAM that swapping will occur. Swapping is terrible for MySQL/MariaDB performance.
• Do adjust innodb_buffer_pool_size such that most of RAM is in use during normal time and even for spikes in activity. (I often say "set it to 70% of available RAM", but you are asking for more details.)
• Do not bother changing other settings; they add to the complexity of "getting it right".

There are 3 situations (based on innodb_buffer_pool_size and dataset size):

• Tiny dataset -- buffer_pool is bigger than necessary --> wasting some of RAM, but so what; it is not useful for anything else. And it give you some room for growth.
• Medium-sized dataset -- Most activity is done in RAM; the system will run nicely.
• Big dataset -- The system may be I/O-bound. Adding RAM is a costly and brute force solution. However, some software techniques (eg, better indexes) may help, such as this for WordPress and WooCommerce.

Remove the "%" from the format and append it to the value afterwards. Here is the relevant change:

So I believe the reason that the values don't change is because it is being done in a for loop.

e.g.

I don't think you can use __timeShift() function for getting the date in the different timezone, it will return you the current (default) one

So if you need to add 392 minutes to the current time in the time zone different from yours - you will have to go for __groovy() function and use TimeCategory class

Example code:

considering your data is:

What does your title have to do with your question? (I will come back to that in a moment.)

Your pivot question is trivial. To the list of pivoted columns, add

Did some more digging inside other SO posts and found a fix.
Instead of using a for loop and searching through the whole list and trying to stop it from running on each value; I can use a indexOf search in a splice function.