blt | Run BOSH | Cloud library
kandi X-RAY | blt Summary
kandi X-RAY | blt Summary
blt stands for BOSH Lit. It is a command line utility for standing up a local BOSH environment on your workstation. The provisioning process should never take longer than 5 minutes.
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Top functions reviewed by kandi - BETA
- performUp runs the virtual machine .
- fetch fetches and returns the path to the given URL .
- getStartingStartedInstructions returns the instructions to execute the GetStartedInstructions command .
- Check for dependencies
- fetchVMProcess retrieves the VM process from the homedir
- configureBoshDirector configures the Bosh director
- DownloadAssets downloads assets for a given version
- do runs the given task with the given delay .
- Show progress animation animation
- Stop stops the running VM
blt Key Features
blt Examples and Code Snippets
Lines of Code : 19License : Permissive (Apache-2.0)
Copy$ sudo ifconfig lo0 alias 10.0.0.4 # Allow connections to BOSH Director
$ blt up
...
Updating instance 'bosh/0'... Finished (00:00:19)
Waiting for instance 'bosh/0' to be running... Finished (00:00:11)
Running the post-start scripts 'bosh/0'... # make sure docker-for-mac is installed
# https://www.docker.com/products/docker-desktop
$ brew tap aemengo/tap
$ brew install blt
# blt expose -L host_address:port:container_address:container_port
$ blt expose -L 10.0.0.5:80:10.0.0.5:80 -L 10.0.0.5:443:10.0.0.5:443
Community Discussions
Trending Discussions on blt
QUESTION
.data
input: .asciiz "Enter limit for the sum of natural number = "
show: .asciiz " \n sum of natural numbers are = "
.text
main:
#get the integer input from user
li $v0, 4
la $a0, input
syscall
li $v0, 5
syscall
move $s5, $v0
li $v0, 1
move $a0, $s5
syscall
addi $t5, $t5, 0
iteration:
blt $t5, $s5, increment
j end
increment:
add $s2, $s2, $t5
addi $t5, $t5, 1
j iteration
end:
li $v0, 4
la $a0, show
syscall
li $v0, 1
move $a0, $s2
syscall
ANSWER
Answered 2021-Jun-12 at 16:09The sum of 1..n equals (n*(n+1))/2
In pseudocode:
QUESTION
I am trying to replicate this Java function in MIPS:
...ANSWER
Answered 2021-May-14 at 22:52Found it. The trick in MIPS is that the print out command li $v0, 1 can override the value that you may want to print in $v0, that was my mistake. The work around is to store the data in another register first:
QUESTION
I am writing a tool for tracking jumps(JAL/JALR) instructions on riscv instructions. I am using https://github.com/illumine/disk-benchmark/blob/master/src/disk-benchmark.c disk benchmark to test my tool. The tool is tracking jumps on binary files when virtual functions and pthreads are not used but have difficulties to track when pthreads are used. Here is the objdump of binary file on riscv:
ANSWER
Answered 2021-May-11 at 02:44We can trace the jumps on binary file only if we don't have any indirect jumps and if the trace is not involved in library functions. In my case I couldn't trace since the program had a lot of pthreads and indirect jumps.
QUESTION
I Have Fetch Methord Like This.
...ANSWER
Answered 2021-Apr-26 at 14:52I think what you need from the API are the recipes, so the API returns them in the hits property. The hits property is an array of recipes
The properties in the recipe object are; SO you can pick what you need,
QUESTION
I am new to MIPS and writing a program of stack which reverses the elements in array.. i have tried everything to see if anything is wrong.. If anyone who can guide me?
...ANSWER
Answered 2021-Mar-31 at 20:20There are two issues in this program:
while you push something on satack you have to subtract the $sp by 4 bytes and then copy the operand to that location (in that order)
I don't know how can you forget that since you correctly added $sp while popping ... anyway
So you need to add
subu $sp, $sp, 4. (Oraddiu $sp, $sp, -4if your assembler doesn't turn sub into add for you.)in loop the
add $t2,$t1,0is wrong .. you should do$t1,$t1,1(because you seem to increment by one like i = i + 1) .. this mistake indirectly causes your loop to work incorrectly which compares t1 and t2 registers (and you updated t2 register wrongly)Adding 0 is just a copy, so that's not what you want either.
Here is the corrected code.
QUESTION
I just received some help with a problem I had with some MIPS code in this question (Trouble with MIPS array) and the code they gave me works fine. Now I'm trying to add a sorting algorithm to sort the integers stored in the array, but the output I get is just a 0 followed by the string I put as input (the correct output should be the date followed by the string). That's the code I'm working on:
...ANSWER
Answered 2021-Mar-31 at 18:18One approach would be to sort numeric array and keep track of corresponding entries in the string array (as you shuffle around the value in numeric array do the same thing in the string array). I suggest you start implementing a simple sorting algorithm and sort numbers first. For example, consider implementing bubble sort. For this you might consider implementing swap procedure to swap 2 values.
Here is he mips version of the program. It implements bubble sort procedure. I have hardcoded numeric and string arrays at the top of the file (so you have to do some adjustments to make it work with your code). The idea is the following: when I swap numbers in the numeric array I also swap corresponding strings in the string array.
QUESTION
I'm trying to get a subset of a pandas dataframe based on unique values.
My overall dataframe has around 5k rows, where each row has an ID and text, each ID can have multiple text entries. The dataframe something looks like this:
...ANSWER
Answered 2021-Mar-31 at 09:22If it doesn't matter which 3 IDs, you could just get the first 3 with
unique_3 = df['ID'].unique[:3] and then select the rows with df_id = df[df["ID"].isin(unique_3)].
QUESTION
I have the following code already written and everything should be good. It suppose to find biggest and smallest values in array of size 4 using loop.
I got the loops setup and everything except my output is not correct. I have a bug in line 46 that when load the array the value into register X11 I get big weird number and causes the whole calculations to be wrong.
Please see if you can suggests a fix in this code.
...ANSWER
Answered 2021-Mar-19 at 23:12LDR X11,[X0],#3
Reading 64bit values (Xregister), and post-incrementing by #3?
I have a great suspicions that 3Bytes != 64bit.
QUESTION
The prompt is:
Convert the following if-else-if statement into a switch statement. Don’t rewrite the constants or variable definitions, just the if statement.
...
ANSWER
Answered 2021-Mar-17 at 22:41The cases should be options
QUESTION
I am trying to using inline integration in Dymola to do real-time simulation, I take the Modelica.Fluid.Examples.HeatingSystem as an example, but no matter which inline integration method I choose, the simulation always fails.
- When I choose an explicit method, Dymola is unable to start the integration.
- When I choose an implicit method, Dymola got stuck.
- The special one is the Rosenbrock method, the error shows Dymola fails to differentiate some equations.
In my understandings, inline integration means adding the discretization equations to the model equations, then Dymola could do more symbolic manipulations and get a new BLT form. I understand this method could cause more algebraic loops and make it hard for Newton Method to solve these algebraic loops.
My questions are:
- Compared to the normal method in Dymola, what kind of model is more suitable for the inline integration method?
- Inline integration is designed to increase the simulation speed, but it could hard when the nonlinear algebraic loops are hard to solve, so is there a limitation or rule of using the inline integration method?
- Take the
Modelica.Fluid.Examples.HeatingSystemas the case, how could I adjust the model to use inline integration? - I know that Dymola only supports using the inline integration method with the Euler integrator(fixed step size integration algorithms), so why does the inline integration method only support fixed step size? Is it unnecessary to use variable step size? If not limited to real-time simulation, I just want to use inline integration to increase the simulation speed, is it possible to combine the inline integration method with DASSl?
ANSWER
Answered 2021-Feb-18 at 08:02It seems stuck for most implicit solvers because:
- It is a reasonable sized model that you integrate with milli-second timestep for 6 000 second; that means 6 million steps (each involving systems of equations).
- There is less feedback during inline integration (since giving that feedback takes too much time).
But implicit Euler isn't stuck - it just takes a couple of minutes to complete.
However, you can can increase the step-size for implicit Euler a lot for this model, it actually works fine with 1 s; and then completes in less than second.
Inline explicit Euler fails unless you use a lot smaller step-size (same as non-inline explicit Euler).
Note: The inline solvers in Dymola are all fixed-step-size solvers and thus setting a too short step-size will slow down the simulation and a too long step-size will cause the simulation to fail, whereas dassl, lsodar, radau, esdirk* all adjust the step-size during the integration to avoid both of those problems.
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