bitset | Go package implementing bitsets

by bits-and-blooms Go Version: v1.8.0 License: BSD-3-Clause

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kandi X-RAY | bitset Summary

bitset is a Go library. bitset has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

Package bitset implements bitsets, a mapping between non-negative integers and boolean values. It should be more efficient than map[uint] bool. It provides methods for setting, clearing, flipping, and testing individual integers. But it also provides set intersection, union, difference, complement, and symmetric operations, as well as tests to check whether any, all, or no bits are set, and querying a bitset's current length and number of positive bits. BitSets are expanded to the size of the largest set bit; the memory allocation is approximately Max bits, where Max is the largest set bit. BitSets are never shrunk. On creation, a hint can be given for the number of bits that will be used. Many of the methods, including Set, Clear, and Flip, return a BitSet pointer, which allows for chaining.

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Quality

Security

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Support

bitset has a medium active ecosystem.

It has 1111 star(s) with 159 fork(s). There are 30 watchers for this library.

There were 1 major release(s) in the last 12 months.

There are 2 open issues and 48 have been closed. On average issues are closed in 136 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of bitset is v1.8.0

Quality

bitset has no bugs reported.

Security

bitset has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

bitset is licensed under the BSD-3-Clause License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

bitset releases are available to install and integrate.

Installation instructions are not available. Examples and code snippets are available.

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bitset Key Features

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bitset Examples and Code Snippets

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Community Discussions

Trending Discussions on bitset

C++ ValueError bitset::_M_copy_from_ptr when string and bitset are correct size

Handling Long data with BitSet in Java

How to split bitset of any size into list of 64 bits bitsets?

Initializing very large C++ std::bitset at compile time

Class to calculate performance of a function

std::bitset constexpr >64bit value

Adding a letterhead to an RMarkdown PDF

Why is bitset throwing out_of_range error?

Declaring an array of std::bitset using std::string

Reverse order of boost::dynamic_bitset

QUESTION

C++ ValueError bitset::_M_copy_from_ptr when string and bitset are correct size

Asked 2021-Jun-03 at 23:38

I have a string which should represent a 32 bit integer, so i'm creating a bitset to print the bits:

...

ANSWER

Answered 2021-Jun-03 at 23:38

Constructor of std::bitset with string argument expects the string to contain only 0s and 1s. Probably your string contains values like a instead of 1100001. So if you want the 32 bits of 4 bytes of your input string to be put into a bitset, you have to convert the string to a sequence of 32 ones and zeros first.

Source https://stackoverflow.com/questions/67826257

QUESTION

Handling Long data with BitSet in Java

Asked 2021-May-13 at 15:20

I have a large data set with range 0 to Long.MAX_VALUE,
and would like to search for any duplication using BitSet.

While Java BitSet doesn't allow long for its functions.
Is it possible to achieve with BitSet?

...

ANSWER

Answered 2021-May-13 at 15:20

BitSet could be used by seeing which bits were previously set. That would then constitute a duplicate value. However, you can't set a bit position greater than Integer.MAX_VALUE (and it would be infeasible to handle such a large range for longs). So it would not work for the range you suggested. And I presume you would still want to record the duplicates.

I would use a Map to do a frequency count. Then you can just determine the exact count of each value provided. And locating the next Key of a map is comparable to calculating which internal long value holds the desired bit. So I don't believe performance is a factor here.

If you simply want to eliminate duplicates, then just put them in a Set

Based on your comment, check out this simple test for holding one large value in a BitSet.

Source https://stackoverflow.com/questions/67519974

QUESTION

How to split bitset of any size into list of 64 bits bitsets?

Asked 2021-May-04 at 20:59

I have a bitset of any size and I would like to know the fastest way to get a list of 64 bits bitsets from my original bitset ?

For example, from bitset<10000> b('010001110 ...'), I would like to get a list of 64 bits bitsets containing the 1st 64th bits, then the next 64th bits from my original bitset, and so on.

...

ANSWER

Answered 2021-May-04 at 20:59

Sadly, there isn't any functionality to efficiently do this operation straight from the STL. You'd have to go bit by bit or you can shift and mask, as explained in this answer.

However, giving credit to this

You can use boost::dynamic_bitset, which can be converted to a range of "blocks" using boost::to_block_range.

Source https://stackoverflow.com/questions/67391891

QUESTION

Initializing very large C++ std::bitset at compile time

Asked 2021-Apr-30 at 09:43

I want to store a static constant bitset of 2¹⁶ bits, with a specific sequence of 1s and 0s that never changes.

I thought of using an initializer string as proposed by this post :

...

ANSWER

Answered 2021-Apr-28 at 16:58

You didn't really split the literal. It gets concatenated for compilation anyways. You are getting limited by the compiler. I don't think there's a way to increase this limit in MSVC.

You can split it into two literals, initialize two bitsets, shift 1st part and OR with the other.

Something like:

Source https://stackoverflow.com/questions/67298395

QUESTION

Class to calculate performance of a function

Asked 2021-Apr-18 at 23:41

I'm writing a class as follows:

...

ANSWER

Answered 2021-Apr-18 at 23:41

NOW you have made the problem clear! By writing this:

Source https://stackoverflow.com/questions/67153959

QUESTION

std::bitset constexpr >64bit value

Asked 2021-Apr-12 at 12:46

I want to have a bitset constexpr variable in my program. bitset can have unsigned long long value as a constructor which is 64bit value, I need 100 bit value. As per this Q&A, we can use constructor that takes a string as an argument and initialize it that way, but it won't be constexpr value. Is there any possible way?

...

ANSWER

Answered 2021-Apr-12 at 12:36

Unfortunately, constexpr std::bitset's constructors are limited to

default one,
and the one taking unsigned long long.

In addition, its mutators (set, operator[], ...) are not constexpr neither, so you cannot create a constexpr "factory".

You have to create your own bitset (or use one from another library).

Source https://stackoverflow.com/questions/67058057

QUESTION

Adding a letterhead to an RMarkdown PDF

Asked 2021-Apr-10 at 18:42

I'm trying to replicate a report using RMarkdown/LaTeX. Is it possible to add a letterhead to the top of a page in a similar way to the image I've attached? Hoping to find a solution where I can have a letterhead with a logo in it (and where I can easily customise the text and color of the letterhead too).

TIA

I'm using the standard article document class. Here is my YAML in RMarkdown

...

ANSWER

Answered 2021-Apr-08 at 08:56

To give you something to start with, you can use fancyhdr and tikz to design your own header:

Source https://stackoverflow.com/questions/66877489

QUESTION

Why is bitset throwing out_of_range error?

Asked 2021-Apr-10 at 15:22

I am implementing a bloom filter with help of bitsets in c++ for finding out malicious URLs. I have a bitset of 100 bits and a simple hash function. But still I get this error.

...

ANSWER

Answered 2021-Apr-10 at 15:22

After reading carefully I thought the reason could be signed characters. If signed characters are involved,

Source https://stackoverflow.com/questions/67021846

QUESTION

Declaring an array of std::bitset using std::string

Asked 2021-Apr-06 at 01:12

Im currently trying to declare an array of 17 std::bitsets, each 32 bits long. I'm doing it like this:

...

ANSWER

Answered 2021-Apr-06 at 01:12

You need to call the constructor of std::bitset like:

Source https://stackoverflow.com/questions/66959037

QUESTION

Reverse order of boost::dynamic_bitset

Asked 2021-Mar-30 at 22:20

Is there a clean way to return the reverse ordering of a boost::dynamic_bitset object?

For example: 01001100 becomes 00110010. The simplest solution I can think of is to convert the bitset to a string, reverse the string and convert it back to a bitset, but this seems a rather slow method that nullifies the speed of bitstring operations.

Thank you in advance!

...

ANSWER

Answered 2021-Mar-30 at 13:41

boost::dynamic_bitset doesn't have iterators, so a long range of comfy STL solutions like, off the top of my head, std::reverse or std::swap or their boost counterparts are not available, I reckon that a good way would be to make your own trivial reverse method:

Source https://stackoverflow.com/questions/66868386

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