pomodoro | Command line pomodoro timer
kandi X-RAY | pomodoro Summary
kandi X-RAY | pomodoro Summary
Command line pomodoro timer, implemented in Go.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of pomodoro
pomodoro Key Features
pomodoro Examples and Code Snippets
Lines of Code : 14License : Permissive (MIT License)
Copyfunction criticalRouters(numRouters, numLinks, links) {
const graph = buildGraph(numRouters, links);
const critical = [];
// console.log({graph});
for (let curr = 1; curr <= numRouters; curr++) {
if (isCritical(graph, curr)) {
Community Discussions
Trending Discussions on pomodoro
QUESTION
I want to make a countdown timer (25 minutes). This is the code in App.js file
...ANSWER
Answered 2021-Apr-26 at 09:26On every rerender, timer is set as 1500. Use closure here, activated on click.
QUESTION
I'm making a studying timer for the Pomodoro technique (25 min studying 5 min breaking). My timer works only when I called it once. If I call it twice or more, it count down to negative minutes and seconds. Moreover, when I called the studying timer first and the breaking timer later, it executes the breaking timer and skips the studying timer.
...ANSWER
Answered 2021-Apr-17 at 05:32That happens because callbacks inside setInterval are running "asynchronously", to solve this you could use Promises along with Async/Await. You could have a sweet code like this:
QUESTION
WORK_MIN = 12
SHORT_BREAK_MIN = 5
LONG_BREAK_MIN = 20
reps = 0
def start_timer():
global reps
work_min = WORK_MIN * 60
long_break = LONG_BREAK_MIN * 60
short_break = SHORT_BREAK_MIN * 60
while True:
reps += 1
if reps % 8 == 0:
countdown(long_break)
elif reps % 2 == 1:
countdown(work_min)
else:
countdown(short_break)
def countdown(second_count):
minute_time = int(second_count / 60)
# minute_time = math.floor(second_count / 60)
if len(str(minute_time)) == 1:
minute_time = f"0{minute_time}"
second_time = second_count % 60
if len(str(second_time)) == 1:
second_time = f"0{second_time}"
if second_count > 0:
window.after(1000, countdown, second_count - 1)
window = Tk()
window.title("Pomodoro Practice")
window.config(padx=100, pady=50, bg=YELLOW)
window.minsize(width=300, height=300)
start_timer()
window.mainloop()
ANSWER
Answered 2021-Mar-14 at 19:50Add break to the end of all your while conditions, and add an else condition to the end of countdown that restarts start_timer.
QUESTION
I always get this error whenever I try to use some fonts in Pygame
I am making a Pomodoro app more info about Pomodoro here
My Code
...ANSWER
Answered 2021-Mar-05 at 06:38Use pygame.font.SysFont() instead of pygame.font.Font() to create a Font object from the system fonts:
Return a new Font object that is loaded from the system fonts. The font will match the requested bold and italic flags. Pygame uses a small set of common font aliases. If the specific font you ask for is not available, a reasonable alternative may be used. If a suitable system font is not found this will fall back on loading the default pygame font.
For instance:
QUESTION
I have wrote this simple program in Python, which consists of 2 buttons (Start and Reset) as well as a canvas for the 00:00 timer, what it does is when you click Start the time counts down from (25 mins) until it reaches 00:00 and changes the label_text from "Work" to "Break" and the count down begins again from (5 mins to 00:00) and change the label_text back to "Work" from "Break", everything works perfectly, however, my problem is: If I click Start more than one time, both count downs work at the same time, what I need is, when I click start, I should not be able to click it again unless I click Reset button.
I can fix it using the button["state"] = DISABLED but it doesn't help, if you know of any other way I would appreciate your help, thank you very much in advance.
Here's my code:
...ANSWER
Answered 2021-Feb-23 at 19:55I don't know why you had trouble with this, but everything you needed is just track if timer is already counting or not. To make this i have created a global variable called "is_counting" which is False by default. When user presses "start" button it sets this variable to True. If user presses this button again, program will see that timer is already counting and it won't start a new timer. This solution is super simple, but it works, and works well.
Your code with applied fixes:
QUESTION
I'm trying to make a nav-tabs by using bootstrap and generate it dynamically with data get from the API.
After i get the data i make all .appends where i create the dom elements, i've set all attributes to tabs correctly but when i click on another nav item which should change tab content it set the "SHOW" to the first tab and the active remains on the last nav, then it just breaks and stop working...
The nav has a first tab which is static and other dynamic, here is my function which append the static and dynamic items to nav and the tab-content:
...ANSWER
Answered 2021-Feb-23 at 14:14I didn't find anything wrong in your code . But , id with numbers i.e : 001,002..etc are not working so i just attach some text with ids when adding attributes i.e : tab_yourmenuid and it started working .
Demo Code:
QUESTION
I've been trying to use tkinter for creating GUI with Python, today I decided to use images in my GUI, but while using Canvas from tkinter I ran into this error:
...ANSWER
Answered 2021-Feb-17 at 05:14You must supply the image as the value of the keyword argument image:
QUESTION
CSS overflow:scroll; property doesn't provide large scrolling depth. Unable to see the hidden data as scrollbar doesn't scroll enough.
My github link for the code is below. https://github.com/krishnasai3cks/portfolio
...ANSWER
Answered 2021-Jan-13 at 07:36Removing the display: flex property from this class will fix it.
QUESTION
I'm trying to code a small pomodoro-timer, it uses a while loop with an if-elif-else statement to check which timer to start.
As expected it starts with the first if-block and then modifies the variable, I would expect it to go the elif-block after that, however it seems to be stuck in the if-block. And doesn't reiterate the entire while loop code.
How to overcome this?
...ANSWER
Answered 2021-Jan-12 at 15:55So what is wrong with this code is that you reset the last value in each repeat of the while loop, so it never persists its state for the next cycle.
You should declare the variable before the while loop to fix this issue
QUESTION
I'm following a beginner's tutorial for the useState and useRef hooks, trying to implement a simple timer in react.
I'm using the interval variable to store the value from setInterval()
On click of start button, I am able to console.log the value of the interval correctly.
However on click of stop button, interval.current is console logged as undefined. The stopTimer() hence does not function as expected.
Why does interval.current print undefined when it is clearly set in startTimer (and logged there)? What am I missing here?
...ANSWER
Answered 2020-Dec-25 at 00:06Considering what your code is doing, I believe interval should be a state variable and not a ref. That is to say, you should use
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install pomodoro
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
