shamir | Shamir 's Secret Sharing in Golang
kandi X-RAY | shamir Summary
kandi X-RAY | shamir Summary
Implementation of the Shamir's Secret Sharing in golang. Based on github.com/hashicorp/vault from HashiCorp.
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Top functions reviewed by kandi - BETA
- Prints the goldenir .
- Combine takes a map of secret and returns a secret
- NewWriter returns a new io . Writer that uses a given number of parts . The returned io . Writer will be used to create a new io . Writer .
- multiplies a and returns the result .
- Div returns the value of b .
- Split splits a secret into parts .
- makePolynomial creates a polynomial .
- interpolate computes the value of the given points .
- evaluate returns the polynomial value .
- NewReader returns a new io . Reader from a map of io . Reader .
shamir Key Features
shamir Examples and Code Snippets
Community Discussions
Trending Discussions on shamir
QUESTION
In this program I am trying to send key shares though UDP broadcast to the client(s). The issue I'm facing is with encoding of strings and bytes into one message, there are number of errors are produced.
I would like to send from the server to the client a random ID and a key share, which include index (integer) and share (16-bytes string). I have added ":" between id, index and share to be able to manage it at the client later (by splitting the message into parts).
I have tried converting everything into string, such as:
message = (str(id) + ":" + str(index) + ":").encode('utf-16') + str(share, 'utf-16'). But this causing issues in key reconstruction at the client, where the key share should be a byte string and it looks like b"b'\xff\xfej\xb9\xdb\x8c&\x7f\x06\x87\x98Ig\xfc\x1eJ\xf6\xb5'".
Then I have tried encoding id and index to utf-16 and sending a message to the client, and then decode it, but this does not let me reconstruct the key and I'm getting an error: ValueError: The encoded value must be an integer or a 16 byte string.
When I decode at the client, the data looks like this: f91f7e52-865d-49bc-bb45-ad80255e9ef9:5:륪賛缦蜆䦘ﱧ䨞뗶. However, some shares after decoding do not contain dilimiter and thus not being able to split.
Is there a way the server can send all the following data in one message (id, index, share), so that it can be separated correctly at the client?
The desired output at server would be (id = string, index = int, share = 16-byte string):
...ANSWER
Answered 2022-Mar-20 at 17:20The UUID can be encoded as 16 bytes value, the integer e.g. as 4 bytes and and share has a length of 16 bytes. Therefore the data can be simply concatenated without delimiter and separated by their lengths, e.g.:
QUESTION
Let's say we have these requirements to implement:
- Display the cursor position as the mouse moves while being held down.
- Next time the mouse is down, log to the console the last cursor position when the mouse was previously released.
Here is my solution and it works fine. But I'm not quite happy with it: https://codesandbox.io/s/funny-orla-kdx19?file=/src/App.js
...ANSWER
Answered 2021-Dec-31 at 18:17I don't see the need of passing cursorPos as dependency, here is my try:
QUESTION
I am to use a Python example of Shamir's Secret Sharing from Wikipedia. When I give it number a larger than 170.141.183.460.469.231.731.687.303.715.884.105.726 it gives completely different output.
Why doesn't it work after that number and is there a way to get around this?
...ANSWER
Answered 2021-Dec-13 at 16:21The reason why is that all calculations are happening modulo 2 ** 127 - 1 which is 170,141,183,460,469,231,731,687,303,715,884,105,727.
Replace the line:
QUESTION
I am following this tutorial but I don't know why I am getting these permissions errors when I run some vault commands
...ANSWER
Answered 2021-Nov-08 at 12:28You must use quotes around the token when exporting it:
QUESTION
Have installed Vault on Azure Kubernetes and have configured the auto unseal with Azure Key vault. Initially post the deployment , Vault status returns with Seal type as "azurekeyvault" and sealed as true. Once I have initiated with below command.
kubectl exec -it hashivault-0 -n vault -- vault operator init -recovery-shares=1 -recovery-threshold=1
Post that Seal type is changed as "shamir" but the Vault is accessible and active.
Is this expected behavior or is it not referring to Azure Key vault certificates for unsealing ?
...ANSWER
Answered 2021-Sep-03 at 09:23As per the Official Document of Hashicorp , It seems to be expected behavior .
When you seal your vault's status will be Recovery Seal Type : azurekeyvault and Sealed : true But after the vault operator is initialized the vault's status will be Recovery Seal Type : shamir and sealed : false as per auto-unseal feature.
Reference:
QUESTION
I was implementing threshold signatures protocol described in this paper and I run into a case where it fails and I don't understand reasons why. In the end, u and x should be the same, but they are not. I would appreciate any advice that will help me to find the bug.
This is JS code, it can be executed in browser console
...ANSWER
Answered 2021-Jul-05 at 20:52Your code is almost correct, just missing the final modulus at the end. Change the last line to
(u - x) % n;
The (u -x) is exactly n.
115792089237316195423570985008687907852837564279074904382605163141518161494337
QUESTION
I am trying to improve my CSS skills by designing few components. Here, I have designed an article preview component in HTML, CSS, and JS. But the card looks small on some devices and has too much margin. But on other devices, it looks good.
How can I remove this inconsistency?
code sandbox link : https://codesandbox.io/s/gallant-shamir-g3zui
attaching few screenshots on different mobile emulators
...ANSWER
Answered 2021-Jul-01 at 07:20you have set your card class attached to the main element to a fixed width in styles.css (width: 327px;). Use percentages for width and height to get a responsive webpage.
QUESTION
I am trying to transform a formula over to a finite-field equivalent of that formula.
The formula can be seen below:
Now I have this implemented and it works correctly, but I need this in a finite-field, which means that I introduce a p, let's say p = 183269 andd take mod p but how exactly does the above formula change? Do I just mod p after i'm done calculating the formula normally?
Example:
I have the polynomial: f(x) = 1234 + 631x + 442x^2
I generated 6 random points: (x, f(x) mod p)
ANSWER
Answered 2021-Jun-17 at 18:32Do I just mod p after i'm done calculating the formula normally?
No. First you have to compute a multiplicative inverse of x[m] - x[j] modulo p. That is a tricky part to implement efficiently. The rest is indeed just multiplications and summation modulo p.
Keep in mind that floating point operations cannot work in the finite field. Everything there is precise in a sense of integers.
PS: to address a concerns about division, this is how division works in a finite field:
y/x is in fact y * z where z is a multiplicative inverse of x, that is x * z = 1 mod p. For example, let's use 7 for p. A multiplicative inverse of, say 2 is 4: 2 * 4 == 8 (== 1 mod 7). This means that 3/2 mod 7 is 3 * 4 mod 7, that is 5.
QUESTION
I have been working with the libsodium library to implement Shamir secret sharing and trying to test the implementation done by dark crystal
https://gitlab.com/dark-crystal-javascript/key-backup-crypto/-/blob/master/example.js
Implementation is something like this
...ANSWER
Answered 2021-Apr-25 at 20:59It's not clear to me why you want to convert a key pair created with encryptionKeypair() with crypto_sign_ed25519_sk_to_curve25519() or crypto_sign_ed25519_pk_to_curve25519().
The latter two methods convert a secret or public Ed25519 key (used in the context of signing) to a secret or public X25519 key (used in the context of key exchange).
encryptionKeypair() applies crypto_box_keypair() and thus already creates an X25519 key pair, so conversion is not necessary (and not possible).
A working use of the conversion methods would be, e.g. using crypto_sign_keypair(), which generates an Ed25519 key pair:
QUESTION
Coding CLI unit tests using expect and would like to abstract following default block as it applies to all expect blocks.
ANSWER
Answered 2021-Apr-18 at 13:58This is exactly what the expect_before and expect_after commands do. In this case it doesn't matter which one you use:
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