Rosella | Portable , light-weight ircd written in Go | TLS library

by eXeC64 Go Version: Current License: AGPL-3.0

X-Ray Key Features Code Snippets Community Discussions(5)Vulnerabilities Install Support

kandi X-RAY | Rosella Summary

Rosella is a Go library typically used in Security, TLS applications. Rosella has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

Rosella is a small ircd (Internet Relay Chat Daemon). It partially implements RFC1459, but will never be fully compliant. Rosella is intended to provide a portable, light-weight, near-zero-conf ircd capable of handling many simultaneous connections, whilst providing as much privacy for its users as possible. Rosella only communicates with clients over SSL/TLS connections, therefore an x.509 certificate and private key are required for operation. Proper key handling and certificate checking is the responsibility of the users. Rosella cannot protect you from stupidity or untrustworthy CA’s.

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Quality

Security

License

Reuse

Support

Rosella has a low active ecosystem.

It has 57 star(s) with 3 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

There are 0 open issues and 1 have been closed. On average issues are closed in 106 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of Rosella is current.

Quality

Rosella has no bugs reported.

Security

Rosella has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

Rosella is licensed under the AGPL-3.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

Rosella releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

Top functions reviewed by kandi - BETA

kandi has reviewed Rosella and discovered the below as its top functions. This is intended to give you an instant insight into Rosella implemented functionality, and help decide if they suit your requirements.

Open the rosella server
reply is used to send a reply message
NewServer returns a new Server .

Get all kandi verified functions for this library.

Rosella Key Features

No Key Features are available at this moment for Rosella.

Rosella Examples and Code Snippets

No Code Snippets are available at this moment for Rosella.

Community Discussions

Trending Discussions on Rosella

How can I convert a list of character strings to unique single characters?

Creating and returning a set in java then use toString in main to print to print the new set out

Python: separating strings using pipes as delimiter

gulp-image doesn't compress JPGs

How to filter strings from an array of objects

QUESTION

How can I convert a list of character strings to unique single characters?

Asked 2020-May-11 at 02:32

I have a variable which is a list of different bird calls in sequence. I would like to give each different call a unique, single character. I have found a way to give them unique numbers, but once I reach 10 that is no good as I would need to then turn this list into a string of letters and/or numbers.

For example, some of my dataframe looks like this:

...

ANSWER

Answered 2020-May-11 at 02:32

We can use upper and lower case alphabets with numbers 0-9 which comes out to be of size 62.

Source https://stackoverflow.com/questions/61721372

QUESTION

Creating and returning a set in java then use toString in main to print to print the new set out

Asked 2019-Dec-05 at 01:38

This is a question which needs to be answered using the methods shown here and no other way (its a exam question).

I have a Personand Friends(TreeSet to hold Person) class

The Person class just creates a instance of person with a sName and fName.

In friends I have a method getSurname() which finds the surname of the object Person and adds it to a new set with all matching surnames:

...

ANSWER

Answered 2019-Dec-05 at 01:12

Without seeing the implementation of the Person class, I can't debug your exact issue, but likely your problem lies in your implementation of the compareTo(Person p) method from the Comparable interface.

If you have something like this in your compareTo function:

Source https://stackoverflow.com/questions/59186652

QUESTION

Python: separating strings using pipes as delimiter

Asked 2018-May-07 at 07:46

I have a list of strings with data separated by pipes, I want to split these strings using pipes as the delimiter. I have tried using x.split('|'), however it is not working. here is my current code:

...

ANSWER

Answered 2018-May-07 at 07:35

x[0].split('|') doesn't achieve anything since you do not do anything with its result. Maybe you want to do this instead?

Source https://stackoverflow.com/questions/50209145

QUESTION

gulp-image doesn't compress JPGs

Asked 2018-Jan-04 at 16:16

gulp-image is compressing png files without any flaw but when it comes to the jpg format, it leaves them as they are. If it is of any help, here it is my configuration:

...

ANSWER

Answered 2018-Jan-04 at 16:16

I don't think there is anything wrong. The various jpeg compression algorithms have various settings where you can adjust how much to compress. The default settings for jpeg-recompress are:

Source https://stackoverflow.com/questions/48095109

QUESTION

How to filter strings from an array of objects

Asked 2017-Feb-09 at 09:46

I have an array of objects like this:

...

ANSWER

Answered 2017-Feb-08 at 23:54

You can do this:

Source https://stackoverflow.com/questions/42125748

Community Discussions, Code Snippets contain sources that include Stack Exchange Network