nas | Network Attached Storage library
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QUESTION
I am trying to divide merged information from one cell into separate cells.
one cell:
amount:2 price:253,18 price2:59,24 EU status:WBB NAS MRR OWA PXA min:1 opt:3 category: PNE code z:195750divided data: (I want to export each part into another cell)
amount:2 price:253,18 price2:59,24 EU status:WBB NAS MRR OWA PXA min:1 opt:3 category: PNE code z:195750I can't simply divide by finding empty space, status cell which is case-sensitive | status:WBB NAS MRR OWA PXA| has a different data range with spaces that can't be divided.
Split ( expression [,delimiter] [,limit] [,compare] )
...ANSWER
Answered 2021-May-24 at 11:44As the order is the same one way is to simply search for adjacent key names & parse out whats in-between:
QUESTION
I am using an if else statement to convert the values in column X into bins in a new column Y. Code:
...ANSWER
Answered 2021-Jun-15 at 04:55Please copy and paste this snippet and let us know if it gets the result you want.
QUESTION
First time asking a question on here, so I apologise if I have missed something. I have been looking through existing answers and couldn't find any that address this issue specifically.
I'm trying to split inconsistent strings into two variables using the extract function of the tidyr package.
Reprex of my data with library calls:
...ANSWER
Answered 2021-Jun-14 at 15:07You used lookarounds that are non-consuming patterns, while you need to use consuming pattern to let the regex engine reach minutes after hours.
You can solve the problem using
QUESTION
I am trying to learn data-cleaning with simple code.
My central question is: what is the use of two single square brackets side by side?
Here is df
as an example.
ANSWER
Answered 2021-Jun-14 at 04:36That is a very complex way of replacing NA
's. You can reduce the function to -
QUESTION
I have written a function that draws random variates from a normal distribution with outliers. However I now want to take the mean of this data and append it to an empty vector 1000 times (so essentially a vector with 1000 different means using my function) Here is my attempt so so far.
...ANSWER
Answered 2021-Jun-13 at 15:41There are a few ways of doing this. If you want to use a loop, the trick is to define an empty vector before initiating the loop, and store values in that. Here's an example using rnorm
to generate values from a standard normal, since I don't have the code for your rnormout
function:
QUESTION
Problem
I have a large JSON file (~700.000 lines, 1.2GB filesize) containing twitter data that I need to preprocess for data and network analysis. During the data collection an error happend: Instead of using " as a seperator ' was used. As this does not conform with the JSON standard, the file can not be processed by R or Python.
Information about the dataset: Every about 500 lines start with meta info + meta information for the users, etc. then there are the tweets in json (order of fields not stable) starting with a space, one tweet per line.
This is what I tried so far:
- A simple
data.replace('\'', '\"')
is not possible, as the "text" fields contain tweets which may contain ' or " themselves. - Using regex, I was able to catch some of the instances, but it does not catch everything:
re.compile(r'"[^"]*"(*SKIP)(*FAIL)|\'')
- Using
literal.eval(data)
from theast
package also throws an error.
As the order of the fields and the legth for each field is not stable I am stuck on how to reformat that file in order to conform to JSON.
Normal sample line of the data (for this options one and two would work, but note that the tweets are also in non-english languages, which use " or ' in their tweets):
...ANSWER
Answered 2021-Jun-07 at 13:57if the '
that are causing the problem are only in the tweets and desciption
you could try that
QUESTION
I would like to run this equation based on different variable scores in multiple columns simultaneously:
#1scores/(#1scores+#2scores+#0scores)
If my DF looks like this
...ANSWER
Answered 2021-Jun-10 at 14:17If 0, 1, 2 and NA
are the only values in your dataframe you can do -
QUESTION
I have some NifTi files of brain images where there are lots of zeros that I want to replace with NAs but I'm not sure how to do it. I read in the description of the is.na()
function that: "the generic function is.na<- sets elements to NA" so I thought I could use that, but it didn't work. Here is specifically what I tried:
ANSWER
Answered 2021-Jun-08 at 22:19Here are some possible option to replace 0
by NA
QUESTION
My problem is the following:
I usually backup files (e.g. pictures) on external harddisc drives and the store them away in safe places. In the meantime also on NAS. But I don't want to have them connected and online all the time, for power and security reasons.
If I'm now looking for an old file (e.g. a special jpg from the holiday in April 2004) I would have to connect a few discs and search them for the needed file.
To overcome this problem I usually create a recursive dir-dump into a textfile for the whole disc after backup.
This way I can search the filename in the text-file.
But there still is a problem if I don't exactly know the file name that I am looking for. I know the Year and month and maybe the camera I was using then, but there must be hundreds of files in this month.
Therefore I would like to create a "dummy"-backup-filesystem with all the filesnames on the harddisc but without the actual data behind it. This way I could click through the folders and see the foldernames and filenames and easily find the respective file.
The question is: How do I create such a filesystem copy with the complete folderstructures but only the filenames and not the data?
I'm working on Linux, Opensuse, but I guess this is not a linux specific question.
ANSWER
Answered 2021-Jun-08 at 17:00In the meantime I found the solution I was looking for:
Virtual Volume View: http://vvvapp.sourceforge.net/
Works with Linux, MacOS and Windows!
QUESTION
probably a really basic question but I cannot figure it out. Assume the following test code:
...ANSWER
Answered 2021-Jun-07 at 13:22My solution is as follows:
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