wordfilter | dirty words filter for game | Widget library

by gonet2 Go Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(7)Vulnerabilities Install Support

kandi X-RAY | wordfilter Summary

wordfilter is a Go library typically used in User Interface, Widget applications. wordfilter has no bugs, it has a Permissive License and it has low support. However wordfilter has 1 vulnerabilities. You can download it from GitHub.

dirty words filter for game

Support

Quality

Security

License

Reuse

Support

wordfilter has a low active ecosystem.

It has 53 star(s) with 20 fork(s). There are 8 watchers for this library.

It had no major release in the last 6 months.

There are 1 open issues and 0 have been closed. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of wordfilter is current.

Quality

wordfilter has 0 bugs and 0 code smells.

Security

wordfilter has 1 vulnerability issues reported (0 critical, 0 high, 0 medium, 1 low).

wordfilter code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

wordfilter is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

wordfilter releases are not available. You will need to build from source code and install.

Top functions reviewed by kandi - BETA

kandi has reviewed wordfilter and discovered the below as its top functions. This is intended to give you an instant insight into wordfilter implemented functionality, and help decide if they suit your requirements.

The main entry point .
Initialize the server
_WordFilterService_Filter_Handler is an implementation of ServiceFilterService .
Define types .
RegisterWordFilterServiceServer registers a word filter service for word filter service .
NewWordFilterServiceClient returns a new word filter service client .

Get all kandi verified functions for this library.

wordfilter Key Features

No Key Features are available at this moment for wordfilter.

wordfilter Examples and Code Snippets

No Code Snippets are available at this moment for wordfilter.

Community Discussions

Trending Discussions on wordfilter

Parameter 0 of constructor in '.service ' required a bean of type '.model ' that could not be found

Is this how I can read from a txt file for my Discord bot language filter?

How can I get Python to read a list from a .txt document for my Discord bot

discord.py using Lists in message.content?

Django - compare user objects by field

Designing a filter interface with a template method pattern

Why my Java program works perfectly in windows but it's a disaster in linux?

QUESTION

Parameter 0 of constructor in '.service ' required a bean of type '.model ' that could not be found

Asked 2022-Mar-11 at 14:55

I am creating a spring boot application, it' used to filting bad word. Where in any client can submit the request, these request can be GET,POST

But while creating this application, I am getting the following errors:

The structure of my application is:

Model.WordFilter

...

ANSWER

Answered 2022-Mar-11 at 14:55

Problem is solved. I just copyed all the WordFilter to another folder and deleted all the WordFilter.And i pasted it again. And it working.

Source https://stackoverflow.com/questions/71437046

QUESTION

Is this how I can read from a txt file for my Discord bot language filter?

Asked 2020-Dec-06 at 11:21

@client.listen('on_message')
async def msgfilter(message, member: discord.Member = None):

    wordfilter = open("filter.txt", "r")

    words = set(message.content.split())
    if not words.isdisjoint(wordfilter.read):
        await ctx.send("No")

...

ANSWER

Answered 2020-Dec-06 at 11:21

wordfilter = open("filter.txt", "r")

words = set(message.content.split())
filter_words = [w[1:-1] for w in wordfilter.read().strip().split(", ")]

if not words.isdisjoint(filter_words):
    await ctx.send("No")

wordfilter.close()

Source https://stackoverflow.com/questions/65166690

QUESTION

How can I get Python to read a list from a .txt document for my Discord bot

Asked 2020-Dec-06 at 07:57

wordfilter = ["badword", "badword", "badword", "badword", "badword", "badword", "badword"]```

...

ANSWER

Answered 2020-Dec-06 at 07:40

Sample.txt

Source https://stackoverflow.com/questions/65165759

QUESTION

discord.py using Lists in message.content?

Asked 2020-Oct-20 at 18:09

@bot.event
async def on_message(message):
    wordfilter = ['badword', 'anotherone', 'and the last one']
    if wordfilter in message.content:
        await message.delete()

...

ANSWER

Answered 2020-Oct-20 at 18:09

You can't check if a list is in a string, you did it wrong. What you're trying to do is if message.content in wordfilter but this also won't work. You need to get every word in the message then check if one of them is in the wordfilter and also you need to create the wordfilter list out of the event so it won't create a new list for everytime and it makes your code more optimized. So you can simply do it in one line:

Source https://stackoverflow.com/questions/64450470

QUESTION

Django - compare user objects by field

Asked 2020-Jun-13 at 06:42

I have a Dictionary view that shows the list of words created by a specific (special) user:

...

ANSWER

Answered 2020-Jun-12 at 06:22

Obviously they won't be same, because the Word objects are totally different as they are created differently for each user inside custom_create_word. Also, user_word won't work for all the words, you need provide it for each word. You can override the get_queryset method like this(using conditional expression):

Source https://stackoverflow.com/questions/62338235

QUESTION

Designing a filter interface with a template method pattern

Asked 2020-Apr-24 at 16:54

I have done a filter interface that filters out all the strings that have more than 3 letters without any particular pattern. How do i now define a abstract class Filter with a public method filter that calls the method acept that can be implemented in different ways? All of this using Template method pattern?

...

ANSWER

Answered 2020-Apr-24 at 16:54

The Template Method Pattern defines the skeleton of an algorithm in a method, deferring some steps to subclasses. But in the problem that you have given, i see that there is only one step( finding Strings of size n). i.e there is no step before or after finding string of size n.

If Something was there(multiple tasks), i would have done it like below. Which would implement the Template pattern.

Source https://stackoverflow.com/questions/61410051

QUESTION

Why my Java program works perfectly in windows but it's a disaster in linux?

Asked 2020-Mar-26 at 11:18

I wrote a program that reads a text file, deletes the requested string and rewrites it without the string. This program takes three arguments from the terminal: 1) the input file 2) the string 3) the output file.

...

ANSWER

Answered 2020-Mar-26 at 11:05

The input file ends in a newline on Linux. Therefore, there's another line, but it's empty. If you remove the final newline from the input, the program will start working normally.

Or, import the exception

Source https://stackoverflow.com/questions/60865333

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install wordfilter

You can download it from GitHub.

Support

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