tail | Go package for reading from continously updated files
kandi X-RAY | tail Summary
kandi X-RAY | tail Summary
A Go package striving to emulate the features of the BSD tail program.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of tail
tail Key Features
tail Examples and Code Snippets
private void addNodeWithUpdatedFrequency(Node node) {
if(tail != null && head != null) {
Node temp = this.head;
while(temp != null) {
if(temp.frequency > node.frequency) {
if(temp==head) {
node.next = temp;
tem
private void moveNodeToLast(Entry entry) {
if (tail == entry) {
return;
}
final Entry preEntry = entry.getPreEntry();
final Entry nextEntry = entry.getNextEntry();
if (preEntry != null) {
private void moveEntryToLast(Entry entry) {
if (tail == entry) {
return;
}
final Entry preEntry = entry.getPreEntry();
final Entry nextEntry = entry.getNextEntry();
if (preEntry != null) {
Community Discussions
Trending Discussions on tail
QUESTION
I have updated IntelliJ Idea Ultimate and scala plugin, it's working ok so far with sbt to build some projects.
Using a scala worksheet in REPL Interactive mode, I put in some code from a course lecture,
...ANSWER
Answered 2021-Jun-15 at 18:10Put everything in an object
.
This way the 2 def
s that depends on each other will be available at the same time.
IntelliJ worksheets do not like such definitions as they are "evaluated" one by one. You cannot define 2 depending on one the other at the top-level, they need to be encapsulated.
QUESTION
When a divide-and-conquer recursive function doesn't yield runtimes low enough, which other improvements could be done?
Let's say, for example, this power
function taken from here:
ANSWER
Answered 2021-Jun-15 at 17:36The primary optimization you should use here is common subexpression elimination. Consider your first piece of code:
QUESTION
I have written the code to sum up elements of an array with
Recursion
...ANSWER
Answered 2021-Jun-15 at 15:27As I understood, in the tail recursion the base method shouldn't be waiting for the recursive method to finish executing and shouldn't be dependent on its output
That is not quite correct. Tail recursion mostly enables the compiler to apply tail call optimization (if supported), i.e. to rewrite the recursion to a regular loop instead. This has the advantage not reduced memory usage in the stack. It has nothing to do with 'not waiting'.
In the first example it has to keep one stack frame for each item in the list, and if you have a long list there is a chance you will run out of stack memory and get a stackoverflow.
In the tail recursive case the current stack frame is no longer needed when it reaches the tail-call, so the same stack frame can be re-used for each call, and that should result in code sort of equivalent to a regular loop.
Is this implementation the right way to achieve that?
It looks fine to me. But that does not necessarily mean that the optimization will be applied, it seem to depend on the compiler version, and may have other requirements. See Why doesn't .NET/C# optimize for tail-call recursion? In general I would recommend relying on the language specification and not compiler optimization for correct function of your program.
Note that recursion is often not the ideal approach in c#. For something simple as a sum it is easier, faster, and more readable to use a regular loop. For more complicated cases, like iterating over trees, recursion can be appropriate, but then tail-call optimization will not help very much in that case.
QUESTION
I am just learning basics of Javascript but know Java a good amount, I KNOW I AM DOING THIS WRONG, just looking for the correct way to do this. I am trying to have a number entered into a text field and generate as many random numbers between 1-2 as the text field number specifies. Then store those numbers (A bunch of 1's and 2's) in an array and then cycle through the array with a for loop to count how many Heads or Tails there was, and print it.
Expected output: //Number inputted is 10.
Number of heads = 7 and number of tails = 3
ANSWER
Answered 2021-Jun-14 at 21:46I've commented where I've made changes and why.
The key points are that since you are counting 2 values, you can just store the count of each value in an index of an array, rather than fill an array with a new value each time one of 2 options happen.
This lets you cut out the counting loop, making your program much more efficient, always try to count as you add rather than add then count at the end.
Also, you need to refresh the rng
value each time the method is called, so I moved it into the top of the function.
Give it ago!
QUESTION
Given the list [1, 2, 3, 4]
, display the last element. I am using only one parameter and using recursion.
This is what I tried. But the output is always true
.
ANSWER
Answered 2021-May-25 at 09:20I think you over thought this.
The predicate lastElement(Stack).
will match on everything. You just want the last element of the list.
Try this:
QUESTION
I am currently trying to create a program that finds the maximum flow through a network under the constraint that edges with a common source node must have the same flow. It is that constraint that I am having trouble with.
Currently, I have the code to get all flow augmenting routes, but I am hesitant to code the augmentation because I can't figure out how to add in the constraint. I am thinking about maybe a backtracking algorithm that tries to assign flow using the Ford-Fulkerson method and then tries to adjust to fit the constraint.
So my code:
There is a graph class that has as attributes all the vertices and edges as well as methods to get the incident edges to a vertex and the preceding edges to a vertex:
ANSWER
Answered 2021-Jun-14 at 15:28I would guess that you have an input that specifies the maximum flow through each edge.
The algorithm is then:
Because edges with a common source must have same actual, final flow the first step must be a little pre-processing to reduce the max flow at each edge to the minimum flow from the common source.
apply the standard maximum flow algorithm.
do a depth first search from the flow origin ( I assume there is just one ) until you find a node with unequal outflows. Reduce the max flows on all edges from this node to the minimum flow assigned by the algorithm. Re-apply the algorithm.
Repeat step 3 until no uneven flows remain.
=====================
Second algorithm:
Adjust capacity of every out edge to be equal to the minimum capacity of all out edges from the common vertex
Perform breadth first search through graph. When an edge is added, set the flow through the edge the minimum of
- the flow into the source node divided by the number of exiting edges
- the edge capacity
- When search is complete sum flows into destination node.
For reference, here is the C++ code I use for depth first searching using recursion
QUESTION
I get this most common error message in shiny app. I am well aware of this error and have resolved it dozens of time. But this time I am stumped.
...ANSWER
Answered 2021-Apr-23 at 03:30The problem seems to be in this line
QUESTION
I'm using gitlab runner on a mac mini server. While using user named "runner" I manage to use this command:
...ANSWER
Answered 2021-Jun-14 at 14:49I managed to solve this issue by using this solution:
gcloud-command-not-found-while-installing-google-cloud-sdk
I included this 2 line into my gitlab-ci.yml before using the gsutil command.
QUESTION
def list(A):
head=0
tail=1
new_list=[]
for i in A:
if i==1:
new_list.append(i)
if i==1:
new_list.append(i)
print(new_list)
...ANSWER
Answered 2021-Jun-14 at 13:22You can refer to this simple program.
QUESTION
I have a task to create different subsets of the same data table as following:
...ANSWER
Answered 2021-Jun-14 at 02:37You can store the output in a list -
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