open-account | 一个面向C端应用的通用账号系统

 by   iGeeky Go Version: Current License: MIT

kandi X-RAY | open-account Summary

kandi X-RAY | open-account Summary

open-account is a Go library. open-account has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

一个面向C端应用的通用账号系统. 支持用户名密码登录, 手机验证码登,第三方登录. 支持OAuth2.0协议.
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            kandi-support Support

              open-account has a low active ecosystem.
              It has 8 star(s) with 0 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              open-account has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of open-account is current.

            kandi-Quality Quality

              open-account has no bugs reported.

            kandi-Security Security

              open-account has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              open-account is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              open-account releases are not available. You will need to build from source code and install.

            Top functions reviewed by kandi - BETA

            kandi has reviewed open-account and discovered the below as its top functions. This is intended to give you an instant insight into open-account implemented functionality, and help decide if they suit your requirements.
            • LoadConfig initializes the server configuration .
            • UserRegister handles a request for user registration
            • InitLogger initializes a new logger
            • httpReqInternal is a wrapper around http . Request .
            • apiSignCheck checks if the request is valid
            • ReqDebug responds with request
            • clientTokenCheck check if client token is valid
            • TokenDecrypt decrypts and returns user type and userID .
            • SmsLogin handles the login request
            • UserLogin handles a user login request
            Get all kandi verified functions for this library.

            open-account Key Features

            No Key Features are available at this moment for open-account.

            open-account Examples and Code Snippets

            open account
            javadot img1Lines of Code : 25dot img1no licencesLicense : No License
            copy iconCopy
            public static void openAccount(){
            			System.out.println("\nEnter customer name");
            			String cname=s1.next();	
            			System.out.println("\nEnter ac type");
            			String actype=s1.next();	
            			int balance=5000;
            			try{
            				con=giveConnection();
            				String qry  

            Community Discussions

            QUESTION

            How can I conditionally render particular html sections depending on the Route
            Asked 2019-Apr-15 at 10:09

            I'm using React for this project.

            I have got a Help section on my website, This help section has about 50+ articles. If you go to /help-open-account I want to render some html and if I go to /fraud I want to display different html it is all dynamic content so its using the same js file hence why I want to render depending on the link.

            I know how to use the conditional statements but how can I use the current url as a statement so like path="/(?!help--lostMyCard)" if its currently on that url then render the content this content instead of x content.

            The app.js file has this following code ->

            ...

            ANSWER

            Answered 2019-Apr-15 at 10:07

            I see that you want to access route information in component.

            It seems that what you are looking for has already been solved here How to get current route in react-router 2.0.0-rc5

            For more information - Someone can club understanding with link here https://reactjs.org/docs/conditional-rendering.html in addition to above stackoverflow link i have mentioned in this comment to completely solve such problem.

            Source https://stackoverflow.com/questions/55686462

            QUESTION

            Angular 2 - How do I conditionally add styles to my component?
            Asked 2017-Feb-28 at 19:17

            I have a component with a stylesheet that loads correctly like this:

            ...

            ANSWER

            Answered 2017-Feb-28 at 06:28
             import { Component, Inject } from '@angular/core';
             import { DOCUMENT } from '@angular/platform-browser';
            
             @Component({
             })
            
             export class SomeComponent {
            
                constructor (@Inject(DOCUMENT) private document) { }
            
                    LightTheme() {
                        this.document.getElementById('theme').setAttribute('href', 'light-theme.css');
            
            
                    DarkTheme() {
                        this.document.getElementById('theme').setAttribute('href', 'dark-theme.css');
                }
            }
            

            Source https://stackoverflow.com/questions/42496999

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install open-account

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/iGeeky/open-account.git

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            gh repo clone iGeeky/open-account

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            git@github.com:iGeeky/open-account.git

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