gex | The implementation of `` clarify best practice for tool | Dependency Injection library

by izumin5210 Go Version: v0.6.1 License: MIT

X-Ray Key Features Code Snippets(3)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | gex Summary

gex is a Go library typically used in Programming Style, Dependency Injection applications. gex has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

The implementation of clarify best practice for tool dependencies.

Support

Quality

Security

License

Reuse

Support

gex has a low active ecosystem.

It has 50 star(s) with 5 fork(s). There are 4 watchers for this library.

It had no major release in the last 12 months.

There are 2 open issues and 1 have been closed. On average issues are closed in 1 days. There are 5 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of gex is v0.6.1

Quality

gex has no bugs reported.

Security

gex has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

gex is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

gex releases are available to install and integrate.

Installation instructions are not available. Examples and code snippets are available.

Top functions reviewed by kandi - BETA

kandi has reviewed gex and discovered the below as its top functions. This is intended to give you an instant insight into gex implemented functionality, and help decide if they suit your requirements.

run is the main entry point for testing
NewExecutor returns a new Executor
createDefaultConfig creates the default configuration for the process
Create creates a new Git repository
lookupMod looks up moddir in the working directory
FindRoot returns the root of the manifest
DetectType returns the Type for the given work directory .
NewRepository creates a new Repository
init initializes pkgs
Runs the main process

Get all kandi verified functions for this library.

gex Key Features

No Key Features are available at this moment for gex.

gex Examples and Code Snippets

gex,Usage,gex --add [packages...]

Lines of Code : 20

License : Permissive (MIT)

Copy

$ gex --add github.com/golang/mock/mockgen

$ cat tools.go
// Code generated by github.com/izumin5210/gex. DO NOT EDIT.

// +build tools

package tools

// tool dependencies
import (
        _ "github.com/golang/mock/mockgen"
)

// If you want to use

gex,Usage,gex [command] [args...]

Lines of Code : 2

License : Permissive (MIT)

Copy

$ gex mockgen
# prints mockgen's help text...

gex,Usage,go generate ./tools.go

Lines of Code : 1

License : Permissive (MIT)

Copy

$ go generate ./tools.go

Community Discussions

Trending Discussions on gex

I'm trying to print out 5 random 3 letter strings but every time i try it tells me the int type has no len

spread same value into multiple columns

How to keep track of faulted items in TPL pipeline in (thread)safe way

jquery tablesorter - text extraction with image and div

Output name of named pattern in sed or grep

Getting 'Permission denied (password).' when doing multi-factor authentication (key and password) in SSH.NET

Max and Min Characters

how do add 3 letters from a list to 3 input letters

JavaScript - add character in string whenever another character is found

Connecting to SFTP through domain instead of IP fails

QUESTION

I'm trying to print out 5 random 3 letter strings but every time i try it tells me the int type has no len

Asked 2021-Apr-28 at 08:45

I want to print out a set of 5 random responses from this list but every time I try I get the error message saying that type int has no len.

I've tried everything I can think of but I'm only a student and don't really know what I'm doing.

...

ANSWER

Answered 2021-Apr-28 at 08:45

len(endings) is 5, because it's a dictionary and has many entries.

random.choice(...) will generate a random number between 0 and the length of the dictionary. It will then try to access the dictionary with that number. If there is a result, you'll get the item of the dictionary back.

The item might be "ing", so the length of that item is 3 (as for all other items as well).

However, note that your dictionary does not have numbers from 0 to 4, instead it has numbers from 1 to 5. That means:

if the dictionary is accessed with a value of 0, it will crash due to a KeyError, because there is no definition like 0: "abc"
Item number 5 will never be picked.

What you possibly want:

list(endings.values()): convert the values into a list with indexes from 0 to 4, so that all items could be picked
you don't want to print the length of the student names (3), but their name instead
also, if you want to pick 5 students, you don't want to pick the same student twice. That means you need to remove the chosen student from the dictionary or list.

QUESTION

spread same value into multiple columns

Asked 2020-Dec-02 at 12:50

this is my starting df

...

ANSWER

Answered 2020-Dec-02 at 12:50

I'm not sure if you can call it more efficient, but at least it is one code block:

Source https://stackoverflow.com/questions/65106891

QUESTION

How to keep track of faulted items in TPL pipeline in (thread)safe way

Asked 2020-Jun-08 at 17:16

I am using TPL pipeline design together with Stephen Cleary's Try library In short it wraps value/exception and floats it down the pipeline. So even items that have thrown exceptions inside their processing methods, at the end when I await resultsBlock.Completion; have Status=RunToCompletion. So I need other way how to register faulted items. Here is small sample:

...

ANSWER

Answered 2020-Jun-08 at 17:16

I converted a retry-block implementation from an answer to a similar question, to work with Stephen Cleary's Try types as input and output. The method CreateRetryTransformBlock returns a TransformBlock, Try>, and the method CreateRetryActionBlock returns something that is practically an ActionBlock>.

Three more options are available, the MaxAttemptsPerItem, MinimumRetryDelay and MaxRetriesTotal, on top of the standard execution options.

Source https://stackoverflow.com/questions/62154993

QUESTION

jquery tablesorter - text extraction with image and div

Asked 2020-Apr-25 at 20:35

I'm using jquery tablesorter and I want to sort content. Some of my cells contains images, and others div.

With textExtraction I can sort them by images or div. I add two functions in the js part: the first for images, the second for div.

How can I use both of them ? I want a function to sort my table on images and div.

...

ANSWER

Answered 2018-Sep-07 at 14:24

Please try with this

$(document).ready(function() {
                $("#tableA").tablesorter({
                    sortList: [[0,0]],
                    textExtraction:function(s1){                    
                    if($(s1).children('div').html() === "") return $(s1).children('div').attr('class');else if($(s1).find('img').length == 0) return $(s1).text(); else return $(s1).find('img').attr('alt');}
                    //textExtraction:function(s2){ if($(s2).find('div').length == 0) return $(s2).text(); else return $(s2).find('div').attr('class');}
                });     
            });

Source https://stackoverflow.com/questions/52222886

QUESTION

Output name of named pattern in sed or grep

Asked 2020-Jan-09 at 10:22

I'm looking for a solution to output the name of named pattern in regular expression

Regex - can contain n patterns, each named idn, no duplicates:

...

ANSWER

Answered 2020-Jan-09 at 10:22

Here's a simple Perl script which does what you ask.

Source https://stackoverflow.com/questions/59661510

QUESTION

Getting 'Permission denied (password).' when doing multi-factor authentication (key and password) in SSH.NET

Asked 2019-Dec-13 at 16:59

I know this question has already been asked on other posts, but I couldn't find any satisfying answer.

I'm using the Renci.SSH (SSH.NET version 2016.1.0 in C#) to connect to SFTP. I have an SFTP server which I connect using an SSH key and password.

When I connect through WinSCP on my computer, it works perfectly. I would like to do the same from my C# code but I get:

Renci.SshNet.Common.SshAuthenticationException: 'Permission denied (password).'

My PPP file was generated by PuTTYgen and it seems that Renci.SSH doesn't support PuTTY format. Actually, using the ppk file as it is, I get a:

Renci.SshNet.Common.SshException: 'Invalid private key file.'.

So, I had to convert my .ppk to OpenSSH format using the PuTTY key generator Conversions --> Export OpenSSH Key using RSA.

Here bellow an example of the resulting .ppk file:

...

ANSWER

Answered 2019-Dec-13 at 16:59

As seen in WinSCP log file, you should first authenticate with the private key and only then with the password:

2019-12-10 14:54:58.649 Server offered these authentication methods: password,publickey,keyboard-interactive
2019-12-10 14:54:58.649 Offered public key
2019-12-10 14:54:58.758 Offer of public key accepted
2019-12-10 14:54:58.758 Authenticating with public key "rsa-key-20140520"
2019-12-10 14:54:58.878 Sent public key signature
2019-12-10 14:54:59.007 Further authentication required
2019-12-10 14:54:59.007 Server offered these authentication methods: password,keyboard-interactive
2019-12-10 14:54:59.007 Attempting keyboard-interactive authentication
2019-12-10 14:54:59.110 Prompt (keyboard interactive, "SSH server: Password Authentication", "Using keyboard-interactive authentication.", "Password: ")
2019-12-10 14:54:59.110 Using stored password.

Source https://stackoverflow.com/questions/59254206

QUESTION

Max and Min Characters

Asked 2019-Dec-11 at 13:31

I'm new to python. I am trying to make a generator that requires 3 letters from an input. I need it to only accept 3 letters no more no less. The if len i put does not work

...

ANSWER

Answered 2019-Dec-11 at 13:30

Why is names a list?
You have an empty list, name = [] .
Then you add one item to it .

names.append(input("What ..

This is why it fails, because the len of names is 1.

Either get rid of the list or check the len of the first item .

if len(names[0]) == 3

Source https://stackoverflow.com/questions/59286852

QUESTION

how do add 3 letters from a list to 3 input letters

Asked 2019-Dec-11 at 11:16

this is what i have as of now but it does not work. i want to have 3 letters from the input and then add one of the random 3 letters from the list

...

ANSWER

Answered 2019-Dec-11 at 11:12

I think you are trying something along the following lines:

Source https://stackoverflow.com/questions/59284429

QUESTION

JavaScript - add character in string whenever another character is found

Asked 2019-Oct-11 at 11:04

I have a string that looks like this :

...

ANSWER

Answered 2019-Oct-11 at 11:04

You can try with replace() and regex /\)(?=.*\))/g

Where

\) matches the character ) literally

Positive Lookahead (?=.*\))

.* matches any character (except for line terminators)

Source https://stackoverflow.com/questions/58339128

QUESTION

Connecting to SFTP through domain instead of IP fails

Asked 2019-Oct-09 at 09:10

I'm using Renci SSH.NET to upload files to a server. I can do it easily with SFTP server IP, but when I try to set my server domain I recieve an exception

No connection could be made because the target machine actively refused it.

I am able to use both the IP and the full computer name with FTP and FTPS, but with SFTP I can only do it with IP. Is it possible to connect to SFTP through the full computer name? Here is my code:

...

ANSWER

Answered 2019-Oct-09 at 09:10

You have obfuscated the most important part of WinSCP log.

Though anyway, you can see that there's something wrong:

Source https://stackoverflow.com/questions/58285440

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install gex

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: