rconn | multiplatform program for creating generic reverse | Firewall library

by jafarlihi Go Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(4)Vulnerabilities Install Support

kandi X-RAY | rconn Summary

rconn is a Go library typically used in Security, Firewall applications. rconn has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

rconn (r[everse] conn[ection]) is a multiplatform program for creating reverse connections. It lets you consume services that are behind NAT and/or firewall without adding firewall rules or port-forwarding. This is achieved by creating a connection from the node behind the firewall/NAT to a port on your local machine, and then a port is exposed in your machine through which you can connect to the service that is behind firewall/NAT. All traffic is routed through the initial connection that was opened by the machine behind firewall/NAT.

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Support

rconn has a low active ecosystem.

It has 98 star(s) with 14 fork(s). There are 3 watchers for this library.

It had no major release in the last 6 months.

rconn has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of rconn is current.

Quality

rconn has no bugs reported.

Security

rconn has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

rconn is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

rconn releases are not available. You will need to build from source code and install.

Top functions reviewed by kandi - BETA

kandi has reviewed rconn and discovered the below as its top functions. This is intended to give you an instant insight into rconn implemented functionality, and help decide if they suit your requirements.

Basic example
pipe socket
initLogger initializes the default logger .

Get all kandi verified functions for this library.

rconn Key Features

No Key Features are available at this moment for rconn.

rconn Examples and Code Snippets

No Code Snippets are available at this moment for rconn.

Community Discussions

Trending Discussions on rconn

Rserve: pyServe not able to call basic R functions

Local directory shadowing 3rd party package

How to pass __init__ arguments to class registered with qmlRegisterType?

create template with regular expression

QUESTION

Rserve: pyServe not able to call basic R functions

Asked 2020-Jul-02 at 09:40

I'm calling Rserve from python and it runs for basic operations, but not if I call basic functions as min

...

ANSWER

Answered 2020-Jul-02 at 09:40

You should try min(unlist(x)).

If the list is simple, you may just try as.data.frame(x).

For some more complicate list, StackOverFlow has many other answers.

Source https://stackoverflow.com/questions/62681155

QUESTION

Local directory shadowing 3rd party package

Asked 2019-Dec-22 at 12:10

I'm trying to figure out if this is an error in my design, or an error in the redis-py library. Essentially, my understanding of namespace in Python is that packages should be designed such that all components are under the package namespace namespace. Meaning, if I have a queue in packageA and a queue in packageB, there should be no collision since they are namespaced (packageA.queue and packageB.queue). However, I'm running into an error in a package I am building.

This is the directory structure for the package I am building:

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ANSWER

Answered 2019-Dec-22 at 12:10

It's not the Redis package that should adjust here, because it cannot know or cannot handle the different ways users could integrate the Redis package into their own applications, like how you have a similarly named queue package. Furthermore, there is no redis.queue because that queue, is not part of redis, but the built-in Python queue package. You can go to /usr/local/lib/python3.7/site-packages/redis/_compat.py and print out the queue.__file__, which would give you the path to Python's queue. It expects importing the built-in queue package.

Unfortunately for you, when Python builds the module search paths for resolving imports, it builds it in the following order:

The directory containing the input script (or the current directory when no file is specified).

PYTHONPATH (a list of directory names, with the same syntax as the shell variable PATH).

The installation-dependent default.

...which puts your own queue at the start of the list and that's what gets imported. So, yes, getting an ImportError because you shadowed the built-in queue is more of an error in your own design.

You could probably do some tricks here with sys.path or PYTHONPATH, but why bother when you can just rename your queue to something else. Or, what I usually do is to group my own packages into a parent folder, named after the acronym for the project ("abcdlibs") or some app identier or something like "mylibs":

Source https://stackoverflow.com/questions/59443488

QUESTION

How to pass __init__ arguments to class registered with qmlRegisterType?

Asked 2019-Jul-23 at 23:12

Is it possible to pass init arguments to a python class registered to QML using the qmlRegisterType function? If so, would they be passed when the class is instantiated within QML?

I've registered the class with qmlRegisterType, but don't see a way to pass in another class instance as an object. I do see there is a way to register extension objects, but per the documentation, those can only be properties. I'd like to pass in another instantiated class so that I can access its methods and properties within the class I am registering to QML.

How the class would be instantiated in Python:

...

ANSWER

Answered 2019-Jul-22 at 21:25

TL; DR; No, it is not possible.

QML expects that the QObjects registered through qmlRegisterType only have a constructor that receives a QObject as parent (qmlRegisterType does not build the object, only makes it available in QML):

Source https://stackoverflow.com/questions/57153525

QUESTION

create template with regular expression

Asked 2017-May-21 at 13:48

I want to create a template on openvswitch.log with regular expression. I have openvswitch.log like follow text ;

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ANSWER

Answered 2017-May-21 at 13:14

Where do you need to use that regex? You can detect your lines (and group the individual s1/s1-eth2/0 results) with:

Source https://stackoverflow.com/questions/44096796

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install rconn

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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