wordfilter | 提供基于HTTP的敏感词过滤服务 -

 by   lisijie Go Version: Current License: No License

kandi X-RAY | wordfilter Summary

kandi X-RAY | wordfilter Summary

wordfilter is a Go library. wordfilter has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

wordfilter
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            kandi-support Support

              wordfilter has a low active ecosystem.
              It has 53 star(s) with 14 fork(s). There are 7 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              wordfilter has no issues reported. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of wordfilter is current.

            kandi-Quality Quality

              wordfilter has no bugs reported.

            kandi-Security Security

              wordfilter has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              wordfilter does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              wordfilter releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed wordfilter and discovered the below as its top functions. This is intended to give you an instant insight into wordfilter implemented functionality, and help decide if they suit your requirements.
            • import words from a file
            • Main handler
            • Main entry point
            • Add a string to the trie
            • NewTrieNode creates a new TrieNode .
            • NewTrie returns a new trie .
            Get all kandi verified functions for this library.

            wordfilter Key Features

            No Key Features are available at this moment for wordfilter.

            wordfilter Examples and Code Snippets

            No Code Snippets are available at this moment for wordfilter.

            Community Discussions

            QUESTION

            Is this how I can read from a txt file for my Discord bot language filter?
            Asked 2020-Dec-06 at 11:21
            @client.listen('on_message')
            async def msgfilter(message, member: discord.Member = None):
            
                wordfilter = open("filter.txt", "r")
            
                words = set(message.content.split())
                if not words.isdisjoint(wordfilter.read):
                    await ctx.send("No")
            
            ...

            ANSWER

            Answered 2020-Dec-06 at 11:21
            wordfilter = open("filter.txt", "r")
            
            words = set(message.content.split())
            filter_words = [w[1:-1] for w in wordfilter.read().strip().split(", ")]
            
            if not words.isdisjoint(filter_words):
                await ctx.send("No")
            
            wordfilter.close()
            

            Source https://stackoverflow.com/questions/65166690

            QUESTION

            How can I get Python to read a list from a .txt document for my Discord bot
            Asked 2020-Dec-06 at 07:57
            wordfilter = ["badword", "badword", "badword", "badword", "badword", "badword", "badword"]```
            
            
            ...

            ANSWER

            Answered 2020-Dec-06 at 07:40

            QUESTION

            discord.py using Lists in message.content?
            Asked 2020-Oct-20 at 18:09
            @bot.event
            async def on_message(message):
                wordfilter = ['badword', 'anotherone', 'and the last one']
                if wordfilter in message.content:
                    await message.delete()
            
            ...

            ANSWER

            Answered 2020-Oct-20 at 18:09

            You can't check if a list is in a string, you did it wrong. What you're trying to do is if message.content in wordfilter but this also won't work. You need to get every word in the message then check if one of them is in the wordfilter and also you need to create the wordfilter list out of the event so it won't create a new list for everytime and it makes your code more optimized. So you can simply do it in one line:

            Source https://stackoverflow.com/questions/64450470

            QUESTION

            Django - compare user objects by field
            Asked 2020-Jun-13 at 06:42

            I have a Dictionary view that shows the list of words created by a specific (special) user:

            ...

            ANSWER

            Answered 2020-Jun-12 at 06:22

            Obviously they won't be same, because the Word objects are totally different as they are created differently for each user inside custom_create_word. Also, user_word won't work for all the words, you need provide it for each word. You can override the get_queryset method like this(using conditional expression):

            Source https://stackoverflow.com/questions/62338235

            QUESTION

            Designing a filter interface with a template method pattern
            Asked 2020-Apr-24 at 16:54

            I have done a filter interface that filters out all the strings that have more than 3 letters without any particular pattern. How do i now define a abstract class Filter with a public method filter that calls the method acept that can be implemented in different ways? All of this using Template method pattern?

            ...

            ANSWER

            Answered 2020-Apr-24 at 16:54

            The Template Method Pattern defines the skeleton of an algorithm in a method, deferring some steps to subclasses. But in the problem that you have given, i see that there is only one step( finding Strings of size n). i.e there is no step before or after finding string of size n.

            If Something was there(multiple tasks), i would have done it like below. Which would implement the Template pattern.

            Source https://stackoverflow.com/questions/61410051

            QUESTION

            Why my Java program works perfectly in windows but it's a disaster in linux?
            Asked 2020-Mar-26 at 11:18

            I wrote a program that reads a text file, deletes the requested string and rewrites it without the string. This program takes three arguments from the terminal: 1) the input file 2) the string 3) the output file.

            ...

            ANSWER

            Answered 2020-Mar-26 at 11:05

            The input file ends in a newline on Linux. Therefore, there's another line, but it's empty. If you remove the final newline from the input, the program will start working normally.

            Or, import the exception

            Source https://stackoverflow.com/questions/60865333

            QUESTION

            How to use ML Algoritms with feature vector data from bag of words?
            Asked 2019-May-09 at 08:56

            I'm making a program that can predict the corresponding Business unit according to the data in text. I've set up a vocabulary to find word occurances in the text that correspond to a certain unit but I'm unsure on how to use that data with Machine Learning models for predictions.

            There are four units that it can possibly predict which are: MicrosoftTech, JavaTech, Pythoneers and JavascriptRoots. In the vocabulary I have put words that indicate to certain units. For example JavaTech: Java, Spring, Android; MicrosoftTech: .Net, csharp; and so on. Now I'm using the bag of words model with my custom vocabulary to find how often those words occur.

            This is my code for getting the word count data:

            ...

            ANSWER

            Answered 2019-May-09 at 08:56

            You knew already how to prepare data set for training.

            It's an example what I make to explain:

            Source https://stackoverflow.com/questions/55848136

            QUESTION

            removing word from array string using .split() and .filter() methods
            Asked 2018-Nov-24 at 19:01

            I am attempting to build a small app that allows the user to input a string into an array, split the string into individual array items, and then (in a separate field) input the specific word from the string desired to be filtered. The current setup enables the user to input one long string such as "this is a new string", while clicking "add string" results in the string being split ("this,is,a,new,string"). However, upon inputting one of these words into the filtering field (ex. "new"), the filter function appears to still return the enter post-split array, without filtering out the desired word. Any thoughts on how to fix this so that an inputted word chosen from the original string is filtered? Thanks!

            JS:

            ...

            ANSWER

            Answered 2018-Nov-24 at 18:51

            When you push an array into an array you end up with an array with one element, which is the array you pushed. For example:

            Source https://stackoverflow.com/questions/53461261

            QUESTION

            JQuery: Change the class of a dynamically-created
          • element when clicked
          • Asked 2017-Feb-06 at 17:15

            When a user types, the text is turned into an array, separated by " ". A

              element is created and occupied by one
            • for each member of the array, each containing its respective word. These are given the class list-group-item-danger by default, as in Bootstrap. When clicked, this class should be removed and replaced with list-group-item-success.

              There is a default

                element. The
              • members within it respond as expected, with the colour changing when clicked. However, once those are removed and the dynamically created
              • elements are inserted, they no longer function and remain with the list-group-item-danger class which they already had.

                HTML: ...

            ANSWER

            Answered 2017-Feb-06 at 17:15

            Consider using the on() function to handle wiring up events for dynamically created elements :

            Source https://stackoverflow.com/questions/42071093

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install wordfilter

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/lisijie/wordfilter.git

          • CLI

            gh repo clone lisijie/wordfilter

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            git@github.com:lisijie/wordfilter.git

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