kandi X-RAY | goplayground Summary
kandi X-RAY | goplayground Summary
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Top functions reviewed by kandi - BETA
- do map .
- Generate a list of unique keys
- unpack a dnsstruct struct
- printStruct returns a string representation of a dnsStruct .
- packStruct packs dnsstruct into msg .
- answer is used to query a DNS response .
- unpackDomainName returns the name of a domain name .
- isDomainName reports whether s is a domain name .
- Run a websocket connection
- packDomainName packs a domain name into msg .
goplayground Key Features
goplayground Examples and Code Snippets
Community Discussions
Trending Discussions on goplayground
QUESTION
I have following piece of go script and I have questions regarding the channels reading data and the execution order of go routine.
...ANSWER
Answered 2020-Sep-10 at 07:46There is no guarantee in the order of execution of goroutines, nor is there a guarantee of when a goroutine is interrupted (I/O, including printing to stdout, will be the most common cause for rescheduling).
For your first question: you can see that 16
is being printed before after publish 4
. This means that the squares
goroutine read from the channel and printed the square before the main goroutine could start printing information. By the time the main goroutine tries to print the length of the channel, 4
is already gone from it.
Similarly, after sending 5
to the channel, the squares
goroutine has received it, but has not yet printed it. It got interrupted before the print. This means that the channel is empty again, but we haven't seen 25
yet.
If you run your example a number of times, you'll see different outputs. Sometimes the squares
goroutine gets all the way up to 64
, sometimes it doesn't. This is perfectly normal. In normal code, you would need to make sure you wait for data to be consumed before exiting, and you wouldn't rely on the execution order or timing of different goroutines.
QUESTION
I am parsing large JSON file and I need parse its sub-object items
.
You can see that items
is in type []interface{}
:
I succeed to parse the first object map[]string]interface{}
but after that I am trying to parse pods["items"]
which is in type []interface{}
and I covnert it to []byte
for the json.Unmarshal
function and it failed with:
interface {} is []interface [], not []uint8
This is the code to reproduce:
...ANSWER
Answered 2020-Sep-02 at 15:48The problem is that you aren't doing a type conversion as you claim. You are instead doing a type assertion.
Since pods["items"]
is a []interface{}
you would first need each interface to have a concrete type of []byte
and do the assertion on each and collect those into a []byte
before you could execute the unmarshal.
Ultimately you should create a struct
that you can simply unmarshal to and that will greatly simplify your code.
As others have said the fact that you are unmarshalling twice should be an indication that there is a better way.
QUESTION
I am doing some exercises in Go, and I have a strange behavior with my code. If someone could explain me the reason it could be really great.
Here is the code : https://play.golang.org/p/4fQYHWpD6Cj
...ANSWER
Answered 2020-Apr-11 at 19:34Actually, your problem has nothing to do with channels, it's related to array/slice usage. You are using slices everywhere, so initially tere's only one copy of data - sort.Ints()
performs operation in place and channel also operates on slices. This means that until you append
, there's only one array in memory.
And now append
does its job. Here's the key information from documentation:
If the capacity of s is not large enough to fit the additional values, append allocates a new, sufficiently large underlying array that fits both the existing slice elements and the additional values. Otherwise, append re-uses the underlying array.
According to that if capacity of slice is sufficient, append
adds items to existing array (there's no reallocation) and overwrites previous data. So, the faulty part of your code is the consolidation part.
QUESTION
I am trying to create a bunch of struct instance and append to a list after setting some values. This was reusing the variable. This was not working as it turns out golang was returning the same object. This is against what I expect. Is there any rationale for the behavior? What is the solution. Below is the code snippet from goplayground.
...ANSWER
Answered 2020-Feb-17 at 23:34On your example, you're printing the address of variable b
, not the value
try this:
QUESTION
After reviewing several questions, I have decided to ask my question. A few things I can say...
- The struct I am inserting json data into is exported, and so are its fields.
- The struct I am inserting json data into was auto-generated by protoc.
- The struct and code I am using works in goplayground https://goplay.space/#WZWs3dsVcR5
The code I have is broken into a few parts.
protofile message defining the QueryParm struct.
...ANSWER
Answered 2019-Nov-11 at 06:25Two working solutions:
- You may use:
QUESTION
I am writing a program in Golang that interfaces with a modified version of the barefoot mapmatching library which returns results in json via netcat.
My in my actual code json.Unmarshal
will only parse the response to the nil value of the struct. But if print the json to console (see code snippet below) and copy paste into goplayground it behaves as expected.
I am wondering if this is an encoding issue that is bypassed when I copy paste from the console as a result.
How do I get my code to process the same string as it is received from barefoot as when it is copy pasted from the console?
Here is the relevant code snippet (structs are identical to goplayground)
...ANSWER
Answered 2019-Oct-30 at 05:45The io_func function creates and discards a bufio.Reader and data the reader may have buffered. If the application calls io_func more than once, then the application may be discarding data read from the network. Fix by creating a single bufio.Reader outside the function and pass that single reader to each invocation of io_func.
Always check and handle errors. The error returned from any of these functions may point you in the right direction for a fix.
QUESTION
I have two numbers for example the numbers are 12 and 16.
factors of 12 are 1, 2, 3, 4, 6, 12
factors of 16 are 1, 2, 4, 8, 16
common factors of these two numbers are 1, 2 and 4.
So the number of common factors are 3. I need to build a Go program for finding the number common factors of two numbers. But the program should be efficient and with minimum number of loops or without loops. I will provide my code and you can also contribute and suggest with another best methods.
...ANSWER
Answered 2019-Mar-12 at 09:46Answer 1, with no loops just recursion
QUESTION
I am trying to parse a time string which is transported on the wire as JSON. In the below code, I am just experimenting the time parsing as part of that:
...ANSWER
Answered 2019-Jan-16 at 07:51First you're omitting the error returned by time.Parse()
. Never omit errors.
If you print the error:
QUESTION
I am looking into golang as my new goto language for my web-backend. My current language there is PHP, where I implemented a datastructure resembling the Backbone Collection/Model structure.
excursus Collection / ModelThis means I have a Collection
containing multiple Models
. Models
have an attributes
dictionary for storing the actual "public data". Collections
have multiple convenience methods operating on the array of Models
(sort, getByIndex, getByMatchingParameter, etc). Models
also have their share of convenience methods.
In daily life there will be 90% of "things" that are represented the same way. For example I can store an Address
the same way I store my User
. Having an AddressesCollection
containing my Addresses
I can simply ask my AddressesCollection
to give me all AddressModels
where city=Berlin
. And implementing this matching in my base class I can do the logically same thing on my UserCollection
giving me all my Users which are deactivated by deactivated=true
.
But sometimes (10%) I need a special method. getGeoData
for Addresses
for example. Now, in my oop-world, I can simply create a new class extending my BaseModel
adding my method and use my extended class everywhere where my base class was used.
How does this work in Go. I read a lot introductions into embedding / composition. But simply do not get my head around this.
This is where I stand, keep in mind this is my playground for learning the "inheritance" concept, not for having a production ready Collection / Model implementation.
What I get is that I haven't "understood" how to write a "generic" method accepting not-quite-inherited types. I have the feeling that I have to use an interface there somewhere to get this "inheritance"/"extended class" feeling. But my current use of this is... well...
But maybe I am completely wrong in my concept of implementing my desired structure that way in go at all? Maybe there is a much more elegant way. Any hints greatly appreciated!
...ANSWER
Answered 2017-Jun-10 at 11:38You are pretty close to getting it right, but you have mixed up multiple different things.
Complete example: https://play.golang.org/p/wpj82QRVUP
- Type embedding
So you have two models User
, Address
and they both share common fields and maybe methods. This is a good reason to create a common struct for both: Model
, as shown in the link above. All three structs are of different types.
- Collections
You can have a collection of interfaces or collection of defined types. So when to use which?
If you have a collection of addresses, defined the type of follows:
type AddrCollection []*Address
. And then implement whatever method you want on AddrCollection
type.
If you have a collection of models, similarly define type ModelCollection []*Model
, but then passing Address
to the ModelCollection
would require to "extract" the embedded type.
If you have a collection of something, then define a collection of interfaces (DescriberCollection
in the example), but then you would not have GetByAddress()
defined on it, and it would only exist in AddrCollection
- Interfaces
They have no fields they only define method signatures to be implemented. In Go interfaces are normally accepted and never returned, that gives u a benefit to have clean and goal-oriented design. Interfaces is a way to allow other users (or other packages) to use your packages/libraries in a way that they do not need to implement your types, but rather a certain methods. They can reuse your defined types, or they can plug-in their own implementations of the interface. So what is an interface, it is a way of saying: here are the set of method signatures, as long as you implement them you can use my package
QUESTION
Here I am trying to create a query string for my API from a slice containing strings.
ie. where={"node_name":"node1","node_name":"node_2"}
ANSWER
Answered 2017-Jan-04 at 18:31Your solution uses way too many allocations due to string
concatenations.
We'll create some alternative, faster and/or more elegant solutions. Note that the below solutions do not check if node values contain the quotation mark "
character. If they would, those would have to be escaped somehow (else the result would be an invalid query string).
The complete, runnable code can be found on the Go Playground. The complete testing / benchmarking code can also be found on the Go Playground, but it is not runnable, save both to your Go workspace (e.g. $GOPATH/src/query/query.go
and $GOPATH/src/query/query_test.go
) and run it with go test -bench .
.
Also be sure to check out this related question: How to efficiently concatenate strings in Go?
Alternatives GenesisYour logic can be captured by the following function:
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