gobyexample | Example site is built by extracting code
kandi X-RAY | gobyexample Summary
kandi X-RAY | gobyexample Summary
The Go by Example site is built by extracting code and comments from source files in examples and rendering them via the templates into a static public directory. The programs implementing this build process are in tools, along with dependencies specified in the go.modfile. The built public directory can be served by any static content system. The production site uses S3 and CloudFront, for example.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of gobyexample
gobyexample Key Features
gobyexample Examples and Code Snippets
Community Discussions
Trending Discussions on gobyexample
QUESTION
I am learning Go by example. I've just implemented a select to await multiple channels as follows:
...ANSWER
Answered 2022-Mar-09 at 16:46Conceptually you mitigate against this by designing software correctly. If you have two channels, and each channel will receive at most one message, don't try to read from them 3 times. This is no different than trying to put three items in a two element array, or trying to divide two numbers where the divisor is 0. In all these cases languages offer ways of discovering and recovering from the error, but if you're actually producing these errors, it indicates a logic or design flaw.
You need to make sure that your channels have a balanced number of reads and writes, and that the sending end closes the channel when it has nothing else to send so receivers can stop waiting for messages that won't come. Otherwise you'll eventually have something stuck waiting, or messages in a buffer that are ignored.
In this very specific case, if you want to read from both channels but only if a message is ready, you can add a default
case which will be invoked if no channel is ready for reading, but that's for situations where your channels are not ready yet but will eventually become ready. Providing a default
is not a good solution to cover over bugs where channels will never become ready yet you're still trying to read from them; that indicates a logic-level flaw that needs to be fixed.
QUESTION
In Go, how do I get the Unix epoch in seconds for a date without time?
For example, if I want the Unix epoch seconds for the current time, I can use:
...ANSWER
Answered 2021-Dec-31 at 15:51You can use time.Truncate for rounding the time to the full day:
QUESTION
I have a golang function which recursively steps through a json string and replaces custom references with the json document they are referencing. I just noticed that I forgot to handle cyclic references, whose occurrence will lead to endless recursion. Before I fix this, I'd like to write a test for this case (using ginkgo/gomega), so I can verify that my solution works and I will notice if I ever break it and run into this problem again.
But how do I do something like if this function call does not return within , abort it and fail the test
?
Gomega's Eventually
has a timeout, but it doesn't abort the function if it is already running, so it will block forever in this case.
I found this example for how to check for a timeout using select
and channels, but from what I understood, it is not possible to terminate a goroutine from outside - so my function will continue to run in the background, eating up resources?
What is the best way to check for infinite recursion?
...ANSWER
Answered 2022-Jan-11 at 13:15You can't abort a running function. The function has to support abortion, idiomatically through a context.Context
or a channel. If you want to support timeout or abortion, you have to change / refactor your function. And the function itself has to support this, e.g. it has to monitor the context.Context
and return early if cancellation was requested. For details and example, see Terminating function execution if a context is cancelled
See related:
QUESTION
Straight from https://gobyexample.com/variadic-functions
For this part sum(nums...), why can't I do sum(nums) ?? I can't just pass a slice to a func?
...ANSWER
Answered 2021-May-19 at 13:27No you can't, because the types are different. One has to apply the ...
operator to a slice to pass it as a variadic input .
QUESTION
As a part of learning about pointer vs value receivers I referred to:https://gobyexample.com/methods
...ANSWER
Answered 2021-May-12 at 00:39You need to understand what a pointer is in order to understand what's going on here. A pointer contains the address of another variable.
The two types of receiver are different in that one (pointer) expects an address and the other (value) expects not-an-address.
Now, to answer your first question: "Why are the results the same?"
First, rp
is a pointer to r
. Meaning what is contained in rp
is the address of r
. So both r
and rp
eventually refer to the same struct (r
directly contains it and the address in rp
points to it). So in the end it is the same struct.
Also, the reason r
and rp
can both be used with pointer and value receivers is this:
Go is automatically getting what's at the address contained in rp
when calling perim()
(which as a value receiver requires not-an-address) and it is automatically getting the address of r
for passing when calling area()
(which as a pointer receiver requires an address).
To answer your second question: "What does this mean ...?"
To understand this, you need to know that all functions in Go use pass-by-value. That means that when you pass a struct with many fields to a function, the entire struct with all its fields will be copied into a new variable to be used inside the function. However, if you pass a pointer (an address of the struct with many fields) only the address is copied into a variable to be used inside the function - which is a lot less copying.
QUESTION
I can't understand a part of the ResponseWriter
syntax.
ANSWER
Answered 2021-Mar-24 at 09:38fmt.Println(w)
does not write into w
. It writes w
to the standard output. And since nobody writes into w
, an empty response document will be sent back to the HTTP client.
To write into w
, call its Write()
method like this:
QUESTION
i'm trying to implement a pipeline using buffered channel with size one, it will accept incoming message, print it out and wait some time then pass it forward. The main problem is that reading gobyexample tutorial I decided to implement it using select statement, but I cannot figure out how to make channel block until it will pass the message forward.
...ANSWER
Answered 2021-Mar-24 at 18:17You don't need a select
to do the thing you described:
QUESTION
I've recently begun learning C++, previously I programmed in Go.
I was recently informed that I should not be using new
because exceptions thrown may cause the allocated memory not to be free
d and result in a memory leak. One popular solution to this is RAII, and I found a really good explanation of why to use RAII and what it is here.
However, coming from Go this whole RAII thing seemed unnecessarily complicated. Go has something called defer that solves this problem in a very intuitive way. You just wrap what you want to do when the scope ends in defer()
, e.g. defer(free(ptr))
or defer(close_file(f))
and it'll automagically happen at the end of the scope.
I did a search and found two sources that had attempted to implement the defer functionality in C++ here and here. Both ended up with almost exactly the same code, perhaps one of them copied the other. Here they are:
Defer implentation 1:
...ANSWER
Answered 2021-Mar-17 at 15:24A lot of what you're talking about is opinion-based, so I'm going to start with my own opinions.
In the C++ world, we expect RAII. If you want to get along well with other developers, you're both going to encounter it, and you're going to buck the standard if you decide to do something in a different fashion just because it's what you're accustomed to from Go.
Furthermore, C++ developers don't use FOPEN :-). The C++ standard library includes perfectly good RAII-enabled classes, and we use them. So having to implement RAII really means making proper choices of existing standard classes where possible or making sure your objects are RAII-compatible.
I pretty much never have to redesign my code to implement RAII. My choice of classes handles it automatically.
So while the code you've shown is interesting, it's actually more work than RAII. Every time you use FOPEN, you have to also remember to do your defer thing. Isn't it just so much easier to use std::ifstream or std::ofstream? Then it's already handled for you. (And this can be said about other times where your code would have to implement RAII on the spot. It's already done by picking the right classes.)
So, no, it's not neater and more intuitive, because you have to remember to do it. Pick the right classes, and you don't have to remember.
As for the #defines -- they're just there to make sure your variables have unique names and to shortcut the constructor of the defer class.
QUESTION
Can someone please explain what am I doing wrong. So basically I'am trying to make a simple HTTP GET
request. I copied code from https://gobyexample.com/http-clients. When I'm running it locally everything works fine, but in go playground https://play.golang.org/p/-28ykONUD98 it gives:
...panic: Get "http://gobyexample.com": dial tcp: lookup gobyexample.com on 169.254.169.254:53: dial udp 169.254.169.254:53: connect: no route to host
goroutine 1 [running]: main.main() /tmp/sandbox181131075/prog.go:13 +0x345
Program exited: status 2.
ANSWER
Answered 2021-Jan-05 at 01:58From https://blog.golang.org/playground
Like the file system, the playground's network stack is an in-process fake implemented by the syscall package. It permits playground projects to use the loopback interface (127.0.0.1). Requests to other hosts will fail.
So it's normal, your code is good but go playground can only connect to 127.0.0.1
QUESTION
I am reading this lesson https://gobyexample.com/collection-functions and I see next code:
...ANSWER
Answered 2020-Sep-18 at 09:12Any()
expects a function value of type func (string) bool
, but strings.HasPrefix()
has type func (string, string) bool
. It can't be passed directly.
That's why you used a function literal in the first place: to pass a function value that has the proper type.
If you would have a named function with exactly this signature, you could pass it:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install gobyexample
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page