babble | Hashgraph Consensus

 by   mpitid Go Version: Current License: Apache-2.0

kandi X-RAY | babble Summary

kandi X-RAY | babble Summary

babble is a Go library. babble has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

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            kandi-support Support

              babble has a low active ecosystem.
              It has 19 star(s) with 5 fork(s). There are 6 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              babble has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of babble is current.

            kandi-Quality Quality

              babble has no bugs reported.

            kandi-Security Security

              babble has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              babble is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              babble releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed babble and discovered the below as its top functions. This is intended to give you an instant insight into babble implemented functionality, and help decide if they suit your requirements.
            • run is the main entrypoint function .
            • NewNode returns a new Node .
            • newTCPTransport creates a new TCPTransport .
            • main is the entry point for testing .
            • NewCore returns a new Core instance .
            • NewHashgraph creates a new Hashgraph .
            • GeneratePemKey generates a PEM - encoded private key
            • NewNetworkTransport creates a new NetworkTransport
            • NewSocketAppProxy creates a socket app proxy
            • sendRPC is used to send a request
            Get all kandi verified functions for this library.

            babble Key Features

            No Key Features are available at this moment for babble.

            babble Examples and Code Snippets

            No Code Snippets are available at this moment for babble.

            Community Discussions

            QUESTION

            Enable global method security leads to 404
            Asked 2020-Oct-02 at 01:53

            When I enable Global Method Security, I get 404/NotFound when I call my endpoint that belongs to a class annotated with @Preauthorized

            This is my configuration:

            ...

            ANSWER

            Answered 2020-Oct-02 at 01:53

            I guess you got 404 because you have @PreAuthorize and missing proxyTargetClass = true for @EnableGlobalMethodSecurity annotation. Spring loses your controller because it's a JDK proxy instead of CGLIB and doesn't have @RestController anymore.

            Try to replace it with:

            Source https://stackoverflow.com/questions/64164299

            QUESTION

            Can an Alexa skill keep the microphone always on?
            Asked 2020-Feb-10 at 14:59

            I have been a C/C# developer for many years but haven't written any Alexa apps. I would like to write a skill to listen for baby babble (NOT WORDS) and respond in different ways. I would like my Alexa skill to keep the microphone ALWAYS on (similar to how "Alexa, Guard" works) because babies speak randomly.

            Is there some sample code I can look at?

            ...

            ANSWER

            Answered 2020-Feb-10 at 14:59

            You can't do this.

            There is no way to keep the microphone open with a custom skill.

            When you activate the skill "open my skill", Alexa starts talking and then, when she stops, you have only 8 + 8 seconds to speak, otherwise, the session will be closed.

            So you have 8 seconds, then if you don't speak there is a re-prompt phrase asking you to tell something, and another 8 seconds where you can speak.

            If you don't, the session will be closed.

            There is a way to keep the session open more than 8 seconds (playing some mute music for example), but the problem remains because you can only speak after that "music" is finished.

            Source https://stackoverflow.com/questions/60152598

            QUESTION

            a flip-card class is not transforming in javascript
            Asked 2020-Feb-01 at 09:31

            this code is throwing an Uncaught TypeError. i am trying to flip a flip-card by clicking on it. But the code is giving this error: "Uncaught TypeError: Cannot set property 'transform' of undefined" what is the problem? Here i have used named the div i am trying to rotate as "flip-card" i have also commented the hover attribute in the css property.

            CODE:

            ...

            ANSWER

            Answered 2020-Feb-01 at 09:31

            document.getElementsByClassName("flip-card") will return an DOM Array elements, just add [0] to select the first element of the array, like this:

            Source https://stackoverflow.com/questions/60015243

            QUESTION

            Excel formula to get max length of delimited value in a cell
            Asked 2020-Jan-23 at 21:30

            I have a single cell which contains multiple lines of text delimited by carriage return CHAR(10).

            ...

            ANSWER

            Answered 2020-Jan-15 at 16:19

            Use MID to parse the string breaking on the Char(10) and return the max

            Source https://stackoverflow.com/questions/59755446

            QUESTION

            How to unmarshal nested unknown fields
            Asked 2019-Nov-03 at 16:08

            I forked a great project here, and have just been having a mess around with it learning some go. My issue I can't figure out is some things about custom unmarshaling, if you see here you can see this unmarshals the Thing struct which holds a Data interface{} field that is then unmarshalled using the Kind string field. This all works great except the nested situations. So the best thing is an example:

            Just say you have Thing struct that's kind is a listing, thus the Thing.Data this is unmarshalled to type listing. Then listing has 3 Children of type link that is held in the Children []Thing field. These Children end up being of type map[string]interface {} which is my issue. How can I have this unmarshall down through nested data? So that the Children.Data is also unmarshalled. Is there a way to do this in go or will I have to write a big loop or recursion algorithm? Please let me know what you think or if I am looking at this situation all wrong. Thank you

            UPDATE Here is a json sample

            ...

            ANSWER

            Answered 2018-Feb-21 at 14:39

            In your case you needs to create a recursive function which will get the nested value of underlying interface{} till last depth. There is no way we can get nested value from interface{} with unknown underlying type. Here is an example of what you can do in your code

            Source https://stackoverflow.com/questions/48907574

            QUESTION

            s.replace string method, looping through a string
            Asked 2019-Sep-24 at 17:44

            I am attempting to write a method that replaces every occurrence of a letter after the first as a "*" instead of the letter. Examples: "babble" yields "ba**le" "that" yields "tha*"

            My code seems to be having an issue with the replace function while looping and I can't quite figure out why.

            ...

            ANSWER

            Answered 2019-Sep-24 at 17:34

            The str.replace method returns a copy of the original string with all occurrences of the given substring replaced with the given new string, so you can simply slice the input string from the second character and replace all occurrences of the first character with '*', and concatenate it after the first character of the orignal string:

            Source https://stackoverflow.com/questions/58085282

            QUESTION

            Function that takes a 2d list and finds the max of the columns
            Asked 2019-Sep-15 at 05:14

            I'm trying to write a function that takes a 2d list, finds the part of the list that has the highest value in its column, and returns that part of the list including the row and the column.

            This is a homework problem that simulates Scrabble. Essentially, you give the function a list of characters and it returns a list of the best word you could make out of characters based on that word's value and the value itself.

            There's some global variables in this problem: scrabbleScores (a list of that characters and their values) and Dictionary (all the words you could possibly make).

            For example, if you gave it the list, ['a', 's', 'm', 't', 'p'], it would first call another function that returns all of the words you could make from that list and their values, then it would use that list and return a list with the best word and its value.

            So, I already have a function that I've been working on, but whenever I run it my IDE gives me a "int object is not subscriptable" error:

            ...

            ANSWER

            Answered 2019-Sep-15 at 05:14

            Code is complicated but I found few mistakes which resolved problem with error.

            bestWordHelper() needs 2D list but problem is [] in some places and + between list's elements so sometimes it creates 1D list instead of 2D list and then it can't get second dimention when you use L[0][1] - and finally you get integer[0] instead of list[0] so you get your error message "int object is not subscriptable"

            First: you forgot [1] in

            Source https://stackoverflow.com/questions/57941145

            QUESTION

            Video is much faster than audio when muxed in GStreamer
            Asked 2019-May-28 at 09:10

            I am trying to learn to record X11 windows' contents to do game screencasts for Youtube. This should be a fairly trivial task, but it already ate a full evening. Now I have learned a bit about muxing and queueing (using gst-launch), but the problem remains: When I mux an audio and video into an avi, video plays several times faster than audio in the resultant file. This means that video ends soon and comes to still, while audio continues to babble in the background.

            This is my filter chain that causes the issue:

            ...

            ANSWER

            Answered 2019-May-28 at 09:10

            gst-launch-1.0 ximagesrc xid=$XID ! video/x-raw,framerate=30/1 ! queue ! videoconvert ! videorate ! queue ! x264enc ! queue ! avimux name=mux ! queue ! filesink location=out.avi pulsesrc device=$DEV ! queue ! audioconvert ! queue ! lamemp3enc bitrate=192 ! queue ! mux.

            The above pipeline should play the audio video at proper speed.

            I would also appreciate if you correct me on the usage of ! queue !. Where is it needed? In the current setup I almost never get warnings that samples were dropped.

            queue are just buffers, these need to be used in places where one element is slower and one is faster, so for example video generating (ximagesrc) is much faster compared with x264enc (software encoding), so you would add a queue in between them so as to buffers aren’t dropped.

            gst-launch-1.0 ximagesrc ! video/x-raw,framerate=30/1 ! queue ! videoconvert ! queue ! x264enc key-int-max=5 ! queue ! mp4mux name=mux reserved-bytes-per-sec=100 reserved-max-duration=20184000000000 reserved-moov-update-period=100000000 ! queue ! filesink location=out.mp4 audiotestsrc ! queue ! audioconvert ! queue ! lamemp3enc bitrate=192 ! queue ! mux.

            The above pipeline would create a mp4 file mp4mux, but the moov atom will be at end itself also note make sure you change mp4mux properties as per your need.

            Source https://stackoverflow.com/questions/56329968

            QUESTION

            Python - Parse text file to json
            Asked 2019-Jan-03 at 15:07

            I have txt file and want to parse content to Json format.

            My code is something like:

            ...

            ANSWER

            Answered 2019-Jan-03 at 15:07

            Check your data for lines that are empty ... you got empty lines in it (maybe the last line has got a \n at its end?) resulting in raise JSONDecodeError("Expecting value", s, err.value) from None.

            This fixes that error:

            Source https://stackoverflow.com/questions/54024344

            QUESTION

            For loop in python indexing string and searching string, can anyone pls explain the output
            Asked 2018-Aug-08 at 00:36
            #usr/bin/python 3.6.1
            import sys
            
            def fix_start(s):
                a = s[0]
            
                i=1
                for i in s:
                    if a in s :
                        print("found")
                        s=s.replace(a,'*')
                    else: print (" not found")
            
                return (s)
            
            def main():
                c = fix_start(sys.argv[1])
                print (c)
            
            if __name__=='__main__':
                main()
            
            ...

            ANSWER

            Answered 2018-Aug-07 at 11:59

            In python strings are iterables. So, your line for i in s will run n times, one for every letter in the string, and will print "not found". The first time the loop runs, it replaces a with*. So, for all subsequent runs, it will print "not found".

            If I understand what you are trying to do, it would be something like

            Source https://stackoverflow.com/questions/51700876

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

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            You can download it from GitHub.

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