unparam | Find unused parameters in Go | Code Analyzer library

 by   mvdan Go Version: Current License: BSD-3-Clause

kandi X-RAY | unparam Summary

kandi X-RAY | unparam Summary

unparam is a Go library typically used in Code Quality, Code Analyzer applications. unparam has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Find unused parameters in Go
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            kandi-support Support

              unparam has a low active ecosystem.
              It has 416 star(s) with 29 fork(s). There are 10 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 7 open issues and 44 have been closed. On average issues are closed in 63 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of unparam is current.

            kandi-Quality Quality

              unparam has no bugs reported.

            kandi-Security Security

              unparam has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              unparam is licensed under the BSD-3-Clause License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              unparam releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            unparam Key Features

            No Key Features are available at this moment for unparam.

            unparam Examples and Code Snippets

            No Code Snippets are available at this moment for unparam.

            Community Discussions

            QUESTION

            VSCode: Could not import Golang package
            Asked 2020-Apr-20 at 15:31

            I'm writing a Go project inside my GoPath, and i'm using the Redigo package for connecting to a Redis Server. The application runs fine, however in VSCode there is this annoying error on package import, wich is preventing VSCode from giving intellisense suggestions

            ...

            ANSWER

            Answered 2020-Apr-20 at 15:31

            This happens to me in a few specific situations. This is my troubleshooting process :

            1. Did you run go get github.com/gomodule/redigo/redis?

            2. Sometimes I have a similar issue when I open my editor in a root different than my project.

            Source https://stackoverflow.com/questions/58518588

            QUESTION

            golangci-lint - want to "really" ignore a go file not simply analyse it and suppress warnings - my current ignore approach eats memory and is slow
            Asked 2020-Jan-22 at 19:36

            With golangci-lint I know I can use skip-dirs or skip-files settings but these just stop reporting at the end and I think the tool still does the "work", quoting docs :

            ... which files to skip: they will be analyzed, but issues from them won't be reported. ...

            Is there way, say with a variant of //nolint to prevent some files getting analysed by golangci-lint in the first place so we don't waste build-time resources - memory/cpu - on them them ?

            I also tried lines at the top like // Code generated by XXX. DO NOT EDIT. and these like //nolint stop reporting but I think golangci-lint is still doing the analysis - i.e. tool runs slow with high memory when big "ignored" files are present. From https://github.com/golangci/golangci-lint#nolint I can do

            ...

            ANSWER

            Answered 2020-Jan-22 at 19:36

            Using a new build tag to exclude files for golangci-lint actually reduces its memory consumption (by preventing parsing of the files)

            Example below is based on : https://android.googlesource.com/platform/external/syzkaller/+/01d1494471798d6b91af9813d1d6c3e13a55536c

            Go files which will now be "efficiently" skipped

            Source https://stackoverflow.com/questions/59857704

            QUESTION

            Cannot build open-source project
            Asked 2017-Aug-19 at 13:26

            I'd like to contribute to an OSS project built with go, but I'm having hard time compiling it. It looks as if I'm missing something obvious.

            I think the problem is related to how go is installed on my computer, and not to the project itself, thus I'm posting it here on StackOverflow, instead of project's "Issues" section.

            Below is what I'm doing.

            1. I've installed go using homebrew:

              ...

            ANSWER

            Answered 2017-Aug-19 at 13:10

            Your go source should in your gopath - here it is Users/gmile/src. Use go get to fetch the pkg you want to work on instead and it should work.

            Source https://stackoverflow.com/questions/45771734

            QUESTION

            OneupUploaderBundle and jQuery-File-Upload on symfony 2
            Asked 2017-Aug-16 at 14:25

            I've been trying this but I'm confused since I'm new to Symfony Events and stuff.

            This is where I've got so far:

            • composer bundle installation
            • AppKernel.php, routing.yml, services.yml, config.yml, UploadListener.php file modifications

            And it works, the file I put is actually being uploaded to the folder, and I got the status bar filling... but I need something else:

            1. somehow I need to post (and read) an item id (integer) along with the file (or to be able to set the filename when the file is being copied to the output folder)
            2. if something goes wrong with the upload, how do I send an error message back?
            3. In the example (jQuery-File-Uploader), the code returns the filename of the file that was uploaded, my code doesn't do that, I mean the code is there, but it doesn't work

            I'm posting the code I have.

            HTML code (here is the piece where I call the jQuery-File-Upload

            ...

            ANSWER

            Answered 2017-Aug-16 at 14:25

            Your form fields will be posted with the file upload. Or you can use the form_data: {} option in your $('#myFile').fileUploader() constructor. But it will submit your form fields by default and you can handle those in the usual way.

            Source https://stackoverflow.com/questions/44960172

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install unparam

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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          • HTTPS

            https://github.com/mvdan/unparam.git

          • CLI

            gh repo clone mvdan/unparam

          • sshUrl

            git@github.com:mvdan/unparam.git

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