kandi X-RAY | go-tour Summary
kandi X-RAY | go-tour Summary
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Top functions reviewed by kandi - BETA
- Compare two ints .
- Factory returns a slice of int values .
- runALotOfTasks returns the number of tasks to run .
- loadConfig initializes the client configuration .
- init initializes the API
- Returns the error if badThingsHook
- Init initializes the configuration .
- maybeTimeConsumingCall is a helper function that returns the result of a function call
- format formats int64 and float64 values
- IsEnabled returns true if api is enabled
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Community Discussions
Trending Discussions on go-tour
QUESTION
I completed the suggested go-tour, watched some tutorials and gopher-conferences on YouTube. And that's pretty much it.
I have a project which requires me to send get requests and store the results in files. But amount of URL's is around 80 million.
I'm testing with 1000 URLs only.
Problem: I think I couldn't managed to make it concurrent, although I've followed some guidelines. I don't know what's wrong. But maybe I'm wrong and it's concurrent, just did not seem fast to me, the speed felt like sequential requests.
Here is the code I've written:
...ANSWER
Answered 2020-Nov-01 at 17:22When setting up a concurrent pipeline, a good guideline to follow is to always first set up and instantiate the listeners that will execute concurrently (in your case, crawlers), and then start feeding them data through the pipeline (in your case, the urlChannel
).
In your example, the only thing preventing a deadlock is the fact that you've instantiated a buffered channel with the same number of rows that your test file has (1000 rows). What the code does is it puts URLs inside the urlChannel
. Since there are 1000 rows inside your file, the urlChannel
can take all of them without blocking. If you put more URLs inside the file, the execution will block after filling up the urlChannel
.
Here is the version of the code that should work:
QUESTION
I think I am missing a part of technical background. But I don't get, why I have to use an * to access the value of a simple pointer, but not for accessing values of a struct.
For example with a simple value:
...ANSWER
Answered 2020-Feb-29 at 21:50The official Golang tour where you found that example [here] explicitly says:
To access the field
X
of a struct when we have the struct pointerp
we could write(*p).X
. However, that notation is cumbersome, so the language permits us instead to write justp.X
, without the explicit dereference.
QUESTION
There's an exercise about binary tree in go-tour.
I have solved this question already and some questions came up on the way.
here is the struct of tree
...ANSWER
Answered 2019-Jul-04 at 05:01Because the function is recursive, and as such, every call of Walk
will reach the line to close the channel, and each of them will try to close the channel. Thus any one of them that tries to close the channel after the first one will be trying to close a closed channel.
QUESTION
I'm using versioned Go command to manage my vendors, everything is working but when I run go build
it doesn't find my local packages
I have set the module root inside my go.mod
with I still get an error
build foo: cannot find module for path
The project arch is like
...ANSWER
Answered 2018-Oct-02 at 18:10I assume your local packages imported are wrong, follow my example.
There is my go.mod
(outside of GOPATH
, I've imported mux
for example):
QUESTION
I'm going through the Go-tour and this module has got me thinking, it seems that every-time you modify the view by slicing the lower bound, the capacity and length of the slice is reduced. However as taught earlier, the underlying array created by the slice does not get altered.
I simplified the example code down to this:
...ANSWER
Answered 2018-Jul-28 at 23:46You seem to understand Go slices.
A Go slice is implemented as a struct
:
QUESTION
In the concurrency section of Golang tour there is an exercise as follows. The problem statement wants to verify that two input trees are as the same or not.
The problem here is when we changing the traversal order from in-order to pre/post-order it fails. i.e the bellow code works correctly
...ANSWER
Answered 2018-May-07 at 09:47The answer for this one is rather related to data structures rather than Golang syntax and has to do with Binary Search Tree properties.
As the documentation states tree.New
func returns a random constructed key:
New returns a new, random binary tree holding the values k, 2k, ..., 10k.
An inorder traversal promises the output to be sorted, but it isn't the case for preorder and postorder traversal and therefore the output would not be equal for these traversals.
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