passchecker | Simple password strength checker | Security library
kandi X-RAY | passchecker Summary
kandi X-RAY | passchecker Summary
Simple password strength checker.
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Top functions reviewed by kandi - BETA
- GetStrength computes the strength of a password
- a passchecker
- New returns a new password .
- NewWithParameters creates and initializes a new password
passchecker Key Features
passchecker Examples and Code Snippets
Community Discussions
Trending Discussions on passchecker
QUESTION
I have created a code which was trying to be a password checker, which checks if the inputted password was more than 8 characters, has an upper case and lower case character, and a number. However, when attempting to display an error message telling the user which aspect of the password they're missing (e.g. "Please include at least one lower case letter") it just will not display the error!
...ANSWER
Answered 2020-Jun-26 at 21:55Here is a suggested version that uses the error code as a return value from the function.
When you are checking whether it contains the various types of character, it will need to work regardless of what order they occur in. An easy way (although certainly there are many alternatives) is to have boolean variables that you set when you find a character of the required type. Note that i == i.lower()
is not a correct test for a lower case letter, because it also evalutates True
for non-letters; use i.islower()
-- and similarly for upper.
QUESTION
I have a custom method for validating the user input, but my form doesn't seem to be submitting. Also, the URL changes after my first submission, and the jquery only runs once the URL's changed.
The purpose of this code is to check if the information submitted is in a database. The function runs, but the value for the name field doesn't seem to be stored upon submission, and so I keep getting the error for name.
Here's my code:
...ANSWER
Answered 2019-Nov-22 at 18:25You don't have a () after val
for name like you do on the other variables.
Change var userName = $('#text').val;
to var userName = $('#text').val();
That will fix your name problem.
Also noticed that you don't have a #
in your jquery selector for selection
.
Change var selection = $("list").val();
to var selection = $("#list").val();
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