sup | Super simple deployment tool - think of it like 'make | Runtime Evironment library
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kandi X-RAY | sup Summary
Stack Up is a simple deployment tool that performs given set of commands on multiple hosts in parallel. It reads Supfile, a YAML configuration file, which defines networks (groups of hosts), commands and targets.
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QUESTION
I am a computer science student; I am studying the Algorithms course independently.
During the course, I saw this question:
Given an n-bit integer N, find a polynomial (in n) time algorithm that decides whether N is a power (that is, there are integers a and k > 1 so that a^k = N).
I thought of a first option that is exponential in n: For all k , 1
For example, if N = 27, I will start with k = 2 , because 2 doesn't divide 27, I will go to next k =3. I will divide 27 / 3 to get 9, and divide it again until I will get 1. This is not a good solution because it is exponential in n.
My second option is using Modular arithmetic, using ak ≡ 1 mod (k+1) if gcd(a, k+1 ) = 1 (Euler's theorem). I don't know if a and k are relatively prime.
I am trying to write an algorithm, but I am struggling to do it:
...ANSWER
Answered 2022-Mar-15 at 10:07Ignoring the cases when N is 0 or 1, you want to know if N is representable as a^b for a>1, b>1.
If you knew b, you could find a in O(log(N)) arithmetic operations (using binary search). Each arithmetic operation including exponentiation runs in polynomial time in log(N), so that would be polynomial too.
It's possible to bound b: it can be at most log_2(N)+1, otherwise a will be less than 2.
So simply try each b from 2 to floor(log_2(N)+1). Each try is polynomial in n (n ~= log_2(N)), and there's O(n) trials, so the resulting time is polynomial in n.
QUESTION
Given a lower case string. Ex:
...ANSWER
Answered 2022-Jan-02 at 07:57It's not a one-liner, but:
QUESTION
The standard defines several 'happens before' relations that extend the good old 'sequenced before' over multiple threads:
[intro.races]
11 An evaluation A simply happens before an evaluation B if either
(11.1) — A is sequenced before B, or
(11.2) — A synchronizes with B, or
(11.3) — A simply happens before X and X simply happens before B.[Note 10: In the absence of consume operations, the happens before and simply happens before relations are identical. — end note]
12 An evaluation A strongly happens before an evaluation D if, either
(12.1) — A is sequenced before D, or
(12.2) — A synchronizes with D, and both A and D are sequentially consistent atomic operations ([atomics.order]), or
(12.3) — there are evaluations B and C such that A is sequenced before B, B simply happens before C, and C is sequenced before D, or
(12.4) — there is an evaluation B such that A strongly happens before B, and B strongly happens before D.[Note 11: Informally, if A strongly happens before B, then A appears to be evaluated before B in all contexts. Strongly happens before excludes consume operations. — end note]
(bold mine)
The difference between the two seems very subtle. 'Strongly happens before' is never true for matching pairs or release-acquire operations (unless both are seq-cst), but it still respects release-acquire syncronization in a way, since operations sequenced before a release 'strongly happen before' the operations sequenced after the matching acquire.
Why does this difference matter?
'Strongly happens before' was introduced in C++20, and pre-C++20, 'simply happens before' used to be called 'strongly happens before'. Why was it introduced?
[atomics.order]/4
says that the total order of all seq-cst operations is consistent with 'strongly happens before'.
Does it mean that it's not consistent with 'simply happens before'? If so, why not?
I'm ignoring the plain 'happens before', because it differs from 'simply happens before' only in its handling of memory_order_consume
, the use of which is temporarily discouraged, since apparently most (all?) major compilers treat it as memory_order_acquire
.
I've already seen this Q&A, but it doesn't explain why 'strongly happens before' exists, and doesn't fully address what it means (it just states that it doesn't respect release-acquire syncronization, which isn't completely the case).
Found the proposal that introduced 'simply happens before'.
I don't fully understand it, but it explains following:
- 'Strongly happens before' is a weakened version of 'simply happens before'.
- The difference is only observable when seq-cst is mixed with aqc-rel on the same variable (I think, it means when an acquire load reads a value from a seq-cst store, or when an seq-cst load reads a value from a release store). But the exact effects of mixing the two are still unclear to me.
ANSWER
Answered 2022-Jan-02 at 18:21Here's my current understanding, which could be incomplete or incorrect. A verification would be appreciated.
C++20 renamed strongly happens before
to simply happens before
, and introduced a new, more relaxed definition for strongly happens before
, which imposes less ordering.
Simply happens before
is used to reason about the presence of data races in your code. (Actually that would be the plain 'happens before', but the two are equivalent in absence of consume operations, the use of which is discouraged by the standard, since most (all?) major compilers treat them as acquires.)
The weaker strongly happens before
is used to reason about the global order of seq-cst operations.
This change was introduced in proposal P0668R5: Revising the C++ memory model, which is based on the paper Repairing Sequential Consistency in C/C++11 by Lahav et al (which I didn't fully read).
The proposal explains why the change was made. Long story short, the way most compilers implement atomics on Power and ARM architectures turned out to be non-conformant in rare edge cases, and fixing the compilers had a performance cost, so they fixed the standard instead.
The change only affects you if you mix seq-cst operations with acquire-release operations on the same atomic variable (i.e. if an acquire operation reads a value from a seq-cst store, or a seq-cst operation reads a value from a release store).
If you don't mix operations in this manner, then you're not affected (i.e. can treat simply happens before
and strongly happens before
as equivalent).
The gist of the change is that the synchronization between a seq-cst operation and the corresponding acquire/release operation no longer affects the position of this specific seq-cst operation in the global seq-cst order, but the synchronization itself is still there.
This makes the seq-cst order for such seq-cst operations very moot, see below.
The proposal presents following example, and I'll try to explain my understanding of it:
QUESTION
I have two data frames that look like this:
...ANSWER
Answered 2021-Dec-29 at 20:16It may be faster with a join
QUESTION
I am looking for an easy, concise way to use dplyr::select
without rearranging columns.
Consider this dataset:
...ANSWER
Answered 2021-Dec-22 at 21:28We could use match
with sort
QUESTION
I'm trying to find ex without using math.h. My code gives wrong anwsers when x is bigger or lower than ~±20. I tried to change all double types to long double types, but it gave some trash on input.
My code is:
...ANSWER
Answered 2021-Dec-22 at 13:15When x
is negative, the sign of each term alternates. This means each successive sum switches widely in value rather than increasing more gradually when a positive power is used. This means that the loss in precision with successive terms has a large effect on the result.
To handle this, check the sign of x
at the start. If it is negative, switch the sign of x
to perform the calculation, then when you reach the end of the loop invert the result.
Also, you can reduce the number of iterations by using the following counterintuitive condtion:
QUESTION
In this programming problem, the input is an n
×m
integer matrix. Typically, n
≈ 105 and m
≈ 10. The official solution (1606D, Tutorial) is quite imperative: it involves some matrix manipulation, precomputation and aggregation. For fun, I took it as an STUArray implementation exercise.
I have managed to implement it using STUArray, but still the program takes way more memory than permitted (256MB). Even when run locally, the maximum resident set size is >400 MB. On profiling, reading from stdin seems to be dominating the memory footprint:
Functions readv
and readv.readInt
, responsible for parsing integers and saving them into a 2D list, are taking around 50-70 MB, as opposed to around 16 MB = (106 integers) × (8 bytes per integer + 8 bytes per link).
Is there a hope I can get the total memory below 256 MB? I'm already using Text
package for input. Maybe I should avoid lists altogether and directly read integers from stdin to the array. How can we do that? Or, is the issue elsewhere?
ANSWER
Answered 2021-Dec-05 at 11:40Contrary to common belief Haskell is quite friendly with respect to problems like that. The real issue is that the array
library that comes with GHC is total garbage. Another big problem is that everyone is taught in Haskell to use lists where arrays should be used instead, which is usually one of the major sources of slow code and memory bloated programs. So, it is not surprising that GC takes a long time, it is because there is way too much stuff being allocation. Here is a run on the supplied input for the solution provided below:
QUESTION
I'm still trying to understand Rust ownership and lifetimes, and I'm confused by this piece of code:
...ANSWER
Answered 2021-Nov-15 at 22:21I don't think it's correct to assume that bar
is assigned lifetime 'a
based on the initial assignment.
Rather, bar
is assigned lifetime 'b
based on the return type. That's why it doesn't complain about assigning something from b
, but it does complain about assigning something from a
.
There's a few things you can do to verify a bit more what's going on here.
First, if you promise that a
lives at least as long as b
, via
fn get_x<'a: 'b, 'b>
, the whole program compiles without problem.
Second, to see that the issue is based on type, check out this version of your code: Playground
QUESTION
My two submissions for a programming problem differ in just one expression (where anchors
is a nonempty list and (getIntegrals n)
is a state monad):
Submission 1. replicateM (length anchors - 1) (getIntegrals n)
Submission 2. sequenceA $ const (getIntegrals n) <$> tail anchors
The two expressions' equivalence should be easy to see at compile time itself, I guess. And yet, comparatively the sequenceA
one is slower, and more importantly, takes up >10x memory:
(with "Memory limit exceeded on test 4" error for the second entry, so it might be even worse).
Why is it so?
It is becoming quite hard to predict which optimizations are automatic and which are not!
EDIT: As suggested, pasting Submission 1 code below. In this interactive problem, the 'server' has a hidden tree of size n
. Our code's job is to find out that tree, with minimal number of queries of the form ? k
. Loosely speaking, the server's response to ? k
is the row corresponding to node k
in the adjacency distance matrix of the tree. Our choices of k
are: initially 1
, and then a bunch of nodes obtained from getAnchors
.
ANSWER
Answered 2021-Nov-09 at 22:52The problem here is related to inlining. I do not understand it completly, but here is what I understand.
InliningFirst we find that copy&pasting the definition of replicateM
into the Submission 1 yields the same bad performance as Submission 2 (submission). However if we replace the INLINABLE
pragma of replicateM
with a NOINLINE
pragma things work again (submission).
The INLINABLE
pragma on replicateM
is different from an INLINE
pragma, the latter leading to more inlining than the former. Specifically here if we define replicateM
in the same file Haskells heuristic for inlining decides to inline, but with replicateM
from base it decides against inlining in this case even in the presence of the INLINABLE
pragma.
sequenceA
and traverse
on the other hand both have INLINE
pragmas leading to inlining. Taking a hint from the above experiment we can define a non-inlinable sequenceA
and indead this makes Solution 2 work (submission).
QUESTION
I recently upgraded my project to TypeScript 4.4.3 from 3.9.9.
My project's using "strictNullChecks": true,
in its tsconfig.json
, and runs in the browser, not server-side on Node.
In TypeScript 4.4.3, it seems like the type declarations for top
has changed to WindowProxy | null
(node_modules/typescript/lib/lib.dom.d.ts
)
This means that I get the following error1 wherever I try to access properties of top
2: TS Playground
ANSWER
Answered 2021-Oct-06 at 12:09instead that you shoud use !
, that typescript ignores the fact that the value could be null which in your case it is not
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