commando | An easy-to-use command-line application builder | Command Line Interface library

 by   thatisuday Go Version: v1.0.4 License: MIT

kandi X-RAY | commando Summary

kandi X-RAY | commando Summary

commando is a Go library typically used in Utilities, Command Line Interface applications. commando has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Commando helps you create beautiful CLI applications with ease. It parses "getopt(3)" style command-line arguments, supports sub-command architecture, allows a short-name alias for flags and captures required & optional arguments. The motivation behind creating this library is to provide easy-to-use APIs to create simple command-line tools. This library uses clapper package to parse command-line arguments. Visit the documentation of this package to understand supported arguments and flag patterns.
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            kandi-support Support

              commando has a low active ecosystem.
              It has 126 star(s) with 14 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 11 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of commando is v1.0.4

            kandi-Quality Quality

              commando has 0 bugs and 0 code smells.

            kandi-Security Security

              commando has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              commando code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              commando is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              commando releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.
              It has 899 lines of code, 44 functions and 8 files.
              It has high code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed commando and discovered the below as its top functions. This is intended to give you an instant insight into commando implemented functionality, and help decide if they suit your requirements.
            • Parse parses the command - line arguments into the registry
            • main is the main run command
            • NewCommandRegistry creates a new CommandRegistry .
            • SetExecutableName sets the executable name
            • Parse parses the command registry .
            • Register registers a new Command .
            • isRootCommand returns true if the given command is root command .
            • removeWhitespaces removes whitespaces from value
            • trimWhitespaces removes whitespaces from value
            Get all kandi verified functions for this library.

            commando Key Features

            No Key Features are available at this moment for commando.

            commando Examples and Code Snippets

            No Code Snippets are available at this moment for commando.

            Community Discussions

            QUESTION

            How can I make the division of my flexbox for a certain size: 3 at row 1 and 2 at row 2?
            Asked 2022-Apr-11 at 21:46

            I am making a website. I have a flexbox with some items on it. They are responsive to the screen size. See the picture below. Now I am going to make my screen smaller and it becomes this: When I make my screen again smaller it becomes this: I think picture 1 and 3 look great, but picture 2 doesn't, because of the division. So I want that if the screensize is as big as picture 2, one picture of the first row will go to the second row, so the division is better. So I don't want to have 4 pictures in row 1 and 1 in row 2, instead I want first 5 in row 1 and when I make my screen smaller, 3 in row 1 and 2 in row 2. In this way it looks more attractive, I think. Does anyone how I can do this?

            ...

            ANSWER

            Answered 2022-Apr-11 at 21:40

            Use media query and a margin:

            Source https://stackoverflow.com/questions/71833626

            QUESTION

            discord.js-commando enabling and working with mongodb
            Asked 2022-Apr-01 at 17:52

            I'm trying to create a discord bot, specifically the wedding team.

            I am using a MongoDB database. Now everything works and is saved, but there is one problem, the data is saved for the second and third rounds, etc.

            That is, the checks that I added do not work. I am trying to find data through const exists = Marry.findOne({ message.author.id });, everything finds, I checked with console log.

            But when I try to validate it just doesn't work. if (exists == message.author.id) { return message.channel.send("You are already married!"); }

            What could be the problem? Help me please!

            Maybe instead userID: message.author.id i just need to find for the value message.author.id. Is it possible?

            ...

            ANSWER

            Answered 2022-Mar-31 at 16:07

            So I think you're having an async issue in your code. The query itself should work just fined. However, I suggest you move exists and married outside of run. Maybe paste them under the MongoDB connection and find a way to pass the message.

            Source https://stackoverflow.com/questions/71619299

            QUESTION

            MongoDB declare model and delete data
            Asked 2022-Apr-01 at 14:04

            I'm trying to create a discord bot, specifically the married.

            In the last topic, I implemented the marry command MongoDB findOne() Cannot read property of null

            Now, using the same logic, I'm trying to make a divorce command that will delete data from the database.

            I do everything the same as there, but I get an error:

            OverwriteModelError: Cannot overwrite Marry model once compiled.

            How do I correctly declare a model in order to find and delete data from the database?

            ...

            ANSWER

            Answered 2022-Apr-01 at 13:40

            I think you have already created Marry model and trying again either in multiple files or may be calling file more than once.

            You may prevent by putting into if condition like

            Source https://stackoverflow.com/questions/71706610

            QUESTION

            MongoDB findOne() Cannot read property of null
            Asked 2022-Apr-01 at 13:31

            I'm trying to create a discord bot, specifically the married.

            I am using a MongoDB database. There is only one problem right now, when the database is empty, I get this error

            An error occurred while running the command: TypeError: Cannot read property 'userID' of null

            What can be done about it? Help me please!

            ...

            ANSWER

            Answered 2022-Apr-01 at 11:02

            It's obvious that you are taking the key of userID from the exist and married variables when there is no data.

            I prefer to use optional chaining i.e exist?.userId and married?.userId

            Source https://stackoverflow.com/questions/71705470

            QUESTION

            Validation does not work and data save for the second round in MongoDB
            Asked 2022-Apr-01 at 09:41

            I'm trying to create a discord bot, specifically the married.

            I am using a MongoDB database. Now everything works and is saved, but there is one problem, the data is saved for the second and third rounds, etc.

            That is, the checks that I added do not work. I am trying to find data through const exists = Marry.findOne({ userID: message.author.id });, everything finds, I checked with console log. But I get text for 100 lines, one of the lines contains userID: 9573697251580611109.

            But I need to get only numbers 9573697251580611109 and nothing more as I try to validate it just doesn't work. if (exists == message.author.id) { return message.channel.send("You are already married!"); }

            How can i do this? Help me please!

            ...

            ANSWER

            Answered 2022-Apr-01 at 09:00

            you need to use await

            for example

            Source https://stackoverflow.com/questions/71704319

            QUESTION

            disable automatic error - discord.js-commando
            Asked 2022-Mar-28 at 10:35

            I'm trying to write a discord bot.

            Now there is one command in which another user is selected. So far, all commands work except for one, checking for the existence of a user.

            That's how I do it:

            ...

            ANSWER

            Answered 2022-Mar-27 at 15:33

            It looks like you are running the database query before checking if userToMarry exists. You might want to change it as seen below. Additionally you may want to wrap query in a try/catch in case userToMarry exists but is invalid.

            Source https://stackoverflow.com/questions/71473932

            QUESTION

            catch not working - The promise rejected with the reason "#"
            Asked 2022-Mar-25 at 22:05

            I'm trying to write a discord bot, right now it's a command to get married.

            Everything works as it should, except for one thing. In the awaitReactions function, I have a time of 10 seconds, and after this time I get this error:

            node:internal/process/promises:246 triggerUncaughtException(err, true /* fromPromise */); [UnhandledPromiseRejection: This error originated either by throwing inside of a n async function without a catch block, or by rejecting a promise which was not handled with .catch(). The promise rejected with the reason "#".] { code: 'ERR_UNHANDLED_REJECTION' }

            I can't understand why this is happening, I have .catch() at the end of the function and in theory everything should work as it should.

            Why doesn't .catch() work in my case? What could be the problem?

            ...

            ANSWER

            Answered 2022-Mar-25 at 22:05

            The mistake here is that every then chain should have a catch block. You have missed two catch blocks. The solution is to either add the catch blocks to all the then chains or you can connect all then chains into one big chain and finally use one catch block

            Method 1

            Source https://stackoverflow.com/questions/71622817

            QUESTION

            Reply to a suggestion with a reaction
            Asked 2022-Mar-25 at 20:36

            I'm trying to create a bot for a discord server. I added the "marry" command to it.

            When a user makes an offer, an announcement message appears. I've added two reactions to this post.

            Now you can answer the offer by writing yes or no.

            But I want to make it possible to answer the offer by clicking on the reaction, the first reaction is yes, the second is no. Will it be hard to do?

            I did everything as in the documentation https://discordjs.guide/popular-topics/reactions.html#awaiting-reactions

            But my bot does not react in any way to clicking reactions, please help..

            ...

            ANSWER

            Answered 2022-Mar-25 at 20:36

            QUESTION

            Tenor Gifs not loading in Discord.Js embeds
            Asked 2022-Feb-22 at 20:28

            I am trying to create a system where a alert command is used and a message along with a random gif is send as an embed. This is working for gifs in the format https://media.discordapp.net/attachments/ but not in the format https://tenor.com/view/. The tenor ones just load and load and then show the little discord poop symbol (failed to load).

            Is there a way to make the tenor gifs work or will I have to download and make them all discord attachments

            ...

            ANSWER

            Answered 2022-Feb-22 at 20:28

            As @Elitezen said, you must have the URL's ending, .gif, for discord to recognize and display it. So, for example, https://tenor.com/view/clone-commando-shadow-of-the-republic-gif-20193389 would become https://tenor.com/view/clone-commando-shadow-of-the-republic-gif-20193389.gif.

            Your code would look like this:

            Source https://stackoverflow.com/questions/71116291

            QUESTION

            setInterval Not Repeating Function using Discord.js
            Asked 2022-Jan-19 at 08:51

            I'm trying to make a discord bot that gives you weekly reminders. Im using momentjs to get the time. As well as using discord.js-commando. I found the best way to call a function multiple times is to use setInterval.

            ...

            ANSWER

            Answered 2022-Jan-19 at 08:51

            Well executing a function every 100ms is not quite optimal. I don't know what is the reason to run just once (it should run infinitely) but there is a better way to do what you need.

            You will need the package called "node-schedule". It's really useful for such things.

            Here's an example:

            Source https://stackoverflow.com/questions/70763735

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install commando

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/thatisuday/commando.git

          • CLI

            gh repo clone thatisuday/commando

          • sshUrl

            git@github.com:thatisuday/commando.git

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