bashful | yaml file to stitch together commands | Command Line Interface library
kandi X-RAY | bashful Summary
kandi X-RAY | bashful Summary
This is beta quality! Use at your own risk. Use a yaml file to stitch together commands and bash snippets and run them with a bit of style. Why? Because your bash script should be quiet and shy-like (...and not such a loud mouth). "But why would you make this monstrosity?" you ask... because &>/dev/null and | tee -a some.log and set -e; do something; set +e and other similar things is getting annoying. And besides... why shouldn't your bash script output look pretty?.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of bashful
bashful Key Features
bashful Examples and Code Snippets
data = [('bug', {'careful'}), ('electric', {'hardy'}), ('fairy', {'naughty', 'impish', 'sassy'}), ('fighting', {'adamant', 'serious', 'careful', 'lonely', 'hasty'}), ('fire', {'gentle', 'impish', 'bold', 'rash', 'naughty', 'lax', 'docile',
Intro = lyrics_by_song[lyrics_by_song.index('[Intro]'):lyrics_by_song.index('something_else')]
import re
with open("etext.txt") as f:
for line in f:
match = re.search(r" (\d+)$", line.strip())
if match:
print(match.group(1))
Community Discussions
Trending Discussions on bashful
QUESTION
mapping = defaultdict(list)
betterMap = {}
with open ('pokemonResult.csv') as pokeMon: # Open file
reader = csv.reader(pokeMon)
next(reader)
for num,row in enumerate(reader): # Map personality as value with type as the key
mapping[row[4]].append(row[3])
for key, value in mapping.items(): # Duplicate to other dictionary
betterMap[key] = set(value)
print(sorted(betterMap.items())) # This method will sort the keys in proper order
print(sorted(betterMap.values())) # Tried to test this, but to no avail
f1 = open("pokemon4.txt", "w")
f1.write() # Will be written when the problem is sorted
f1.close()
...ANSWER
Answered 2022-Mar-25 at 01:35To keep order you have to use list
instead of set()
and you have to sort every list separatelly.
But you have to remeber that dictionary
doesn't have to keep order - in newest Python it tries to keep order but in older Puthon it doesn't have to but it has collections.OrderedDict()
for this.
QUESTION
I've looked everywhere for a solution to this problem, even looked at some similar questions posted here, so please don't mark this as a duplicate, because I still can't figure this out.
As you can see here, I’m trying to keep the image above the red container, at an exact position, but when I zoom in or change the size of the screen, the image isn’t at the place I want it to be, it moves to the left of the page. (Try zooming in on the page yourself or sliding the slide all the way to the right in editor mode, to see what I mean).
I’ve tried everything from absolute and relative positioning and making the image an inline-block and block. I don’t know what to do? Please help me understand. The code is here
...ANSWER
Answered 2021-Oct-29 at 12:37You could wrapp your code in a wrapper and define for it margin: 0 auto;
. Furthermore you should replace in the container-margin the auto
with 0
:
QUESTION
I'm working on a freecodecamp project and I can't seem to get any of the content to look normal when I zoom in or view it on my phone.
The "BTS" title is supposed to be on the center of the image but the text moves around and the image doesn't fill up the page all the way whenever I zoom in. Same goes for the circular images on the bottom. I'm trying to create two rows: 4 images on the first and 3 on the second row.
I have no idea what went wrong with my code.
What I included was only the parts that were messing up. The entire page is here
...ANSWER
Answered 2021-Oct-27 at 12:25In your Html code, complete div and a tag. in BTS title to set mobile view use media query CSS so when you show your site in mobile view set as proper. Use this code to set your circular images in a row.
QUESTION
#include
#include
#include "Header1.h"
using namespace std;
static const char * const wordDataBase[] = {"test","eee","office","minor","town","wrap","treatment","determined","blue","acrid","itchy","organic","impartial","frame","parallel","inconclusive","agreeable","stiff","obsequious","lonely","extra","large","crash","grease","tacky","bashful","cheap","island","outgoing","open","quick","general","big","related","rich","stain","cable","many","attract","star","governor","receive","four","best","tap","match","dapper","married","invent","coordinated","\0"};
string c;
//
char guess;
int wordPick;
bool crct = 0;
bool inct = 0;
int fails = 0;
//
int main() {
cout << "Pick a number between 1 & 50: ";
cin >> wordPick;
string pickedWord = wordDataBase[wordPick - 1];
int wordLength = pickedWord.length();
char* pch;
char str[] = " ";
for (string::size_type l = 0; l < 6; ++l) {
string::value_type c = pickedWord[l];
cin >> guess;
crct = 0;
inct = 0;
if (guess == c) {
crct = 1;
}
else if (guess != c) {
inct = 1;
fails + 1;
}
if (crct == 1) {
second();
for (int guessLength = 0; guessLength < wordLength; guessLength++) {
cout << "_ ";
} cout << endl;
cout << endl << "You guessed a correct letter!" << endl << "Guess again! ";
for (int i = 0; i < pickedWord.length(); ++i) {
str[i] = pickedWord[i];
}
pch = (char*)memchr(str, guess, strlen(str));
if (pch != NULL)
printf("%d.\n", pch - str + 1);
else
printf("guess not found.\n");
}
else if (inct == 1 && fails <= 6) {
third();
for (int guessLength = 0; guessLength < wordLength; guessLength++) {
cout << "_ ";
} cout << endl;
cout << endl << "You guessed an incorrect letter!" << endl << "Guess again! ";
}
else if (fails == 6) {
third();
for (int guessLength = 0; guessLength < wordLength; guessLength++) {
cout << "_ ";
} cout << endl;
cout << "Sadly, you've lost." << endl;
}
}
return 0;
};
...ANSWER
Answered 2021-Mar-16 at 15:56Here is a possible solution. I used std::string
s because they're just simpler. I hold the actual word, and the player's progress in two strings. It's simply a matter of going through the solution with the guess, character-by-character.
QUESTION
ANSWER
Answered 2021-Feb-19 at 21:03An invisible node put more space between u1 & v0. Adding weight values to edges caused them to become vertical. Group attributes might have done the same thing.
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There are a ton of examples in the example/ dir, but here are a few:. Run all of the tasks...
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