imgr | create Amazon EC2 AMIs from a configuration file | AWS library

 by   aestasit Groovy Version: Current License: Apache-2.0

kandi X-RAY | imgr Summary

kandi X-RAY | imgr Summary

imgr is a Groovy library typically used in Cloud, AWS, Amazon S3 applications. imgr has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Imgr is a tool to create Amazon EC2 AMIs (images) from a configuration file.
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              imgr has a low active ecosystem.
              It has 5 star(s) with 0 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 4 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of imgr is current.

            kandi-Quality Quality

              imgr has no bugs reported.

            kandi-Security Security

              imgr has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              imgr is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              imgr releases are not available. You will need to build from source code and install.
              Installation instructions, examples and code snippets are available.

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            imgr Key Features

            No Key Features are available at this moment for imgr.

            imgr Examples and Code Snippets

            No Code Snippets are available at this moment for imgr.

            Community Discussions

            QUESTION

            Conversion RGB into LAB for multiple values
            Asked 2021-Jun-07 at 12:55

            I wrote a code that gives me the average RGB value of an image. Now I want besides the RGB value, also a LAB value. I found a code to do the conversion, but when I run the code, it only gives me the last value.

            So with this code I receive the average RGB and place it in a dataframe:

            ...

            ANSWER

            Answered 2021-Jun-07 at 12:55

            Short Answer

            Check this question (possible duplicate).

            More details on the official documentation.

            Long Answer

            Use these formula to get your own conversion.

            1. RGB => XYZ
            2. XYZ => Lab

            Please keep in mind that there is not a single Lab (depending on the CIE you use), so you might want to tweak the values if necessary.

            Source https://stackoverflow.com/questions/67869955

            QUESTION

            InvalidArgumentError: required broadcastable shapes at loc(unknown)
            Asked 2021-May-29 at 09:07

            Background

            I am totally new to Python and to machine learning. I just tried to set up a UNet from code I found on the internet and wanted to adapt it to the case I'm working on bit for bit. When trying to .fit the UNet to the training data, I received the following error:

            ...

            ANSWER

            Answered 2021-May-29 at 08:40

            Try to check whether ks.layers.concatenate layers' inputs are of equal dimension. For example ks.layers.concatenate([u7, c3]), here check u7 and c3 tensors are of same shape to be concatenated except the axis input to the function ks.layers.concatenate. Axis = -1 default, that's the last dimension. To illustrate if you are giving ks.layers.concatenate([u7,c3],axis=0), then except the first axis of both u7 and c3 all other axes' dimension should match exactly, example, u7.shape = [3,4,5], c3.shape = [6,4,5].

            Source https://stackoverflow.com/questions/67557515

            QUESTION

            Map an object from one image to another image using openCV and Python
            Asked 2021-Apr-26 at 19:02

            This is a problem concerning stereo calibration and rectification using openCV (vers. 4.5.1.48) and Python (vers. 3.8.5).

            I have two cameras placed on the same axis as shown on the image below:

            The left (upper) camera is taking pictures with 640x480 resolution, while the right (lower) camera is taking pictures with 320x240 resolution. The goal is to find an object on the right image (320x240) and crop out the same object on the left image (640x480). In other words; To transfer the rectangle that makes up the object in the right image, to the left image. This idea is sketched below.

            A red object is found on the right image and I need to transfer it's location to left image and crop it out. The objects is placed on a flat plane 30cm from the camera lenses. In other words; The distance (depth) from the two cameras lenses to the flat plane is constant (30cm).

            This main question is about how transfer a location from one image to another, when two cameras are placed side by side, when the images are of different resolutions and when the depth is (fairly) constant. It's not a question about finding objects.

            To solve this problem, as far as I know, stereo calibration must be used, and I have found the following articles/code, among other things:

            Below are an example of a calibration pattern that I used:

            I have 25 photos of the calibration pattern with the left and right camera. The pattern is 5x9 and the square sizes is 40x40 mm.

            Based on my knowledge, I have written the following code:

            ...

            ANSWER

            Answered 2021-Apr-26 at 19:02

            I solved this problem by using the following openCV functions:

            • cv2.findChessboardCorners()
            • cv2.cornerSubPix()
            • cv2.findHomography()
            • cv2.warpPerspective()

            I used the calibration plate at a distance of 30cm to calculate the perspective transformation matrix, H. Because of this, I can map an object from the right image to the left image. The depth has to be constant (30 cm) though, which is a bit problematic, but it is acceptable in my case.

            Thanks to @Micka for the great answers.

            Source https://stackoverflow.com/questions/67226475

            QUESTION

            How to OCR low quality code picture with pytesseract
            Asked 2021-Mar-15 at 20:01

            I have a set of pictures (sample) of the same formatted code, I've tried every thing but nothing works well. I tried blurring, hsv, threshing, etc. can you help me out?

            ...

            ANSWER

            Answered 2021-Mar-10 at 09:57
            import cv2
            import numpy as np
            import pytesseract
            from PIL import Image, ImageStat
            # Load image
            image = cv2.imread('a.png')
            img=image.copy()
            
            # Remove border
            kernel_vertical = cv2.getStructuringElement(cv2.MORPH_RECT, (1,50))
            temp1 = 255 - cv2.morphologyEx(image, cv2.MORPH_CLOSE, kernel_vertical)
            horizontal_kernel = cv2.getStructuringElement(cv2.MORPH_RECT, (50,1))
            temp2 = 255 - cv2.morphologyEx(image, cv2.MORPH_CLOSE, horizontal_kernel)
            temp3 = cv2.add(temp1, temp2)
            result = cv2.add(temp3, image)
            
            # Convert to grayscale and Otsu's threshold
            gray = cv2.cvtColor(result, cv2.COLOR_BGR2GRAY)
            gray = cv2.GaussianBlur(gray,(5,5),0)
            _,thresh = cv2.threshold(gray, 0, 255, cv2.THRESH_OTSU | cv2.THRESH_BINARY_INV)
            
            kernel = np.ones((3,3), np.uint8)
            dilated  = cv2.dilate(thresh, kernel, iterations = 5)
            
            # Find the biggest Contour (Where the words are)
            contours, hierarchy = cv2.findContours(dilated,cv2.RETR_EXTERNAL,cv2.CHAIN_APPROX_SIMPLE)  
            Reg = []
            for j in range(len(contours)-1):
                for i in range(len(contours)-1):
                    if len(contours[i+1])>len(contours[i]):
                        Reg =  contours[i]
                        contours [i] = contours[i+1]
                        contours [i+1] = Reg
            
            x, y, w, h = cv2.boundingRect(contours[0])
            img_cut = np.zeros(shape=(h,w))
            img_cut = gray[y:y+h, x:x+w]
            img_cut = 255-img_cut
            
            # Tesseract
            pytesseract.pytesseract.tesseract_cmd = r'C:\Program Files\Tesseract-OCR\tesseract.exe'
            print(pytesseract.image_to_string(img_cut, lang = 'eng', config='--psm 7 --oem 3 -c tessedit_char_whitelist=ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789-'))
            
            
            cv2.imwrite('generator.jpg',img_cut)
            cv2.imshow('img', img_cut)
            cv2.waitKey()
            

            Source https://stackoverflow.com/questions/66560743

            QUESTION

            How to access elements of a std::vector and put them in separate matrices cv::Mat
            Asked 2021-Mar-15 at 04:45

            I have a const std::vector containing 3 matrices (3 images), and in order to use each image further in my program I need to save them in separate matrices cv::Mat. I know that I need to iterate over vector elements, since this vector is a list of matrices but somehow I can't manage it. At the end, I also need to push 3 matrices back to a vector. I would appreciate if someone could help me out with this. I am still learning it.

            ...

            ANSWER

            Answered 2021-Mar-15 at 04:45

            In your code, note that imagesRGB is uninitialized, and its size is 0. The for loop is not evaluated. Additionally, the copyTo method copies matrix data into another matrix (like a paste function), it is not used to store a cv::Mat into a std::vector.

            Your description is not clear enough, however here's an example of what I think you might be needing. If you want to split an RGB (3 channels) image into three individual mats, you can do it using the cv::split function. If you want to merge 3 individual channels into an RGB mat, you can do that via the cv::merge function. Let's see the example using this test image:

            Source https://stackoverflow.com/questions/66625728

            QUESTION

            imagecreatefromweb causing FATAL error which cannot be caught
            Asked 2021-Feb-22 at 19:04

            I have a simple block of code that when fed an invalid file should be able to provide some user feedback, but I am finding the call to imagecreatefromweb** simply stops all PHP processing with a "Fatal error: gd-webp cannot get webp info in .." straight away.

            I have tried to place this in a try catch but this doesn't make a difference.

            How do I catch this error?

            ...

            ANSWER

            Answered 2021-Feb-22 at 19:04

            Use exif_imagetype() to ensure the file is in WEBP format:

            Source https://stackoverflow.com/questions/66321746

            QUESTION

            What does the ,_,_ mean in faces,_,_ = detector.run(image = imgR, upsample_num_times = 0, adjust_threshold = 0.0)?
            Asked 2021-Feb-03 at 03:29

            Does ,_,_ have any specific meaning in this?

            faces,_,_ = detector.run(image = imgR, upsample_num_times = 0, adjust_threshold = 0.0)

            Is it possible to code it like this?

            faces = detector.run(image = imgR, upsample_num_times = 0, adjust_threshold = 0.0)

            ...

            ANSWER

            Answered 2021-Feb-03 at 03:26

            detector.run might be returning three values. So you need three placeholders to read them. Since code might not be using the other two return values, them have been read into _ which is a style followed by people.

            Source https://stackoverflow.com/questions/66020807

            QUESTION

            Round button wispform embed button
            Asked 2020-Dec-31 at 18:04

            I have created this form using Wispform, I have fixed it on the bottom right of my webpage but I am not able to get it rounded. Where do I add my border radius? Something like this

            ...

            ANSWER

            Answered 2020-Dec-31 at 18:04

            Create a selector and add this selector to css with the following rules:

            Source https://stackoverflow.com/questions/65524127

            QUESTION

            Can someone explain the following C++ Syntax?
            Asked 2020-Oct-29 at 01:39

            I recently came across a line that I do not quite understand in a C++ computer vision project someone else wrote. The project uses OpenCV library. The line is inside the constructor of a struct called Board.

            ...

            ANSWER

            Answered 2020-Oct-28 at 22:32

            Looking at the documentation for OpenCV, it appears cv::Mat has an overloaded operator= that takes a scalar: see this overload. This overload writes the value on the RHS to all elements of the LHS matrix.

            The other part of the key is that apparently copying a cv::Mat is a shallow copy: that is, no data is copied, just the structure.

            As such, my belief is that your lines can be described as follows:

            Source https://stackoverflow.com/questions/64581638

            QUESTION

            How to resolove ReactJS Background Image not working
            Asked 2020-Aug-12 at 16:56

            Hello so I am working on a Tinder clone like app so I want to add an image to the card using the inline styling with the JSX so that I can have access to the object which has the peoples images however it does not render that image but it renders the names which by my understanding if it can render the name it should be able to render the image can I please get help.

            Code Below: TinderCards component

            ...

            ANSWER

            Answered 2020-Aug-12 at 16:56

            If you want to include local images (as you stated in comments) just use require function.

            Source https://stackoverflow.com/questions/63380649

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install imgr

            Run gradlew distZip (or gradlew.bat distZip on Windows )
            An archive containing the application's runtime and script is generated in the 'build/distributions' folder
            Unzip the archive in any location

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