Software-Security-Learning | Software-Security-Learning | Encryption library

 by   CHYbeta HTML Version: Current License: No License

kandi X-RAY | Software-Security-Learning Summary

kandi X-RAY | Software-Security-Learning Summary

Software-Security-Learning is a HTML library typically used in Security, Encryption, Nodejs applications. Software-Security-Learning has no bugs, it has no vulnerabilities and it has medium support. You can download it from GitHub.

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              Software-Security-Learning has a medium active ecosystem.
              It has 1240 star(s) with 300 fork(s). There are 83 watchers for this library.
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              It had no major release in the last 6 months.
              There are 2 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Software-Security-Learning is current.

            kandi-Quality Quality

              Software-Security-Learning has no bugs reported.

            kandi-Security Security

              Software-Security-Learning has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Software-Security-Learning does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
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              Without a license, all rights are reserved, and you cannot use the library in your applications.

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              Software-Security-Learning releases are not available. You will need to build from source code and install.

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            Software-Security-Learning Key Features

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            Software-Security-Learning Examples and Code Snippets

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            Community Discussions

            QUESTION

            Crypto-js encryption and Python decryption using HKDF key
            Asked 2022-Mar-28 at 11:29

            Based on the example provided here on how to establish a shared secret and derived key between JS (Crypto-JS) and Python, I can end up with the same shared secret and derived key on both ends.

            However, when I try to encrypt as below, I cannot find a way to properly decrypt from Python. My understanding is that probably I am messing with the padding or salts and hashes.

            ...

            ANSWER

            Answered 2022-Mar-28 at 11:29

            The issue is that the key is not passed correctly in the CryptoJS code.

            The posted Python code generates LefjQ2pEXmiy/nNZvEJ43i8hJuaAnzbA1Cbn1hOuAgA= as Base64-encoded key. This must be imported in the CryptoJS code using the Base64 encoder:

            Source https://stackoverflow.com/questions/71632056

            QUESTION

            Access a .pem public key from .env file
            Asked 2022-Mar-28 at 09:14

            I am storing a public key in a env variable as a string. This public key is from a .pem file. When I try to use it in my code, I get the following error

            ...

            ANSWER

            Answered 2022-Mar-28 at 08:47

            Your key seems to be a PEM encoded public key in X.509/SPKI format. However, the line breaks are missing. These are to be set so that header and footer are each on a single line. In the body there is a line break after every 64 characters.

            A correctly formatted PEM key can be processed directly by createPublicKey(). The key will be accepted even if the line breaks in the body are missing, but header and footer must be in different lines, otherwise the posted error message will be displayed: error:0909006C:PEM routines:get_name:no start line.

            Example:

            Source https://stackoverflow.com/questions/71609959

            QUESTION

            iOS CryptoSwift AES Encryption to Python Decryption works - but not the inverse
            Asked 2022-Jan-28 at 10:30

            I am using CryptoSwift 1.4.1, iOS 15.2, PyCryptodome 3.12.0, and XCode 13.2.1 to encrypt small string messages that I send to a Raspberry Pi Linux Device over BLE. It works when iOS encrypts the message and sends it to the Raspberry Pi. The Pi can successfully decrypt it. Now I want to do the inverse, encrypt a message on the Pi and have the iOS App read and decrypt it. This, however is not working and the decrypted value is the not the message I encrypted on the Pi.

            Working iOS encryption:

            ...

            ANSWER

            Answered 2022-Jan-28 at 10:30

            In the encrypt() method the IV is not considered. As in aesEncrypt(), the IV must be passed and used when creating the AES object.
            Furthermore there are bugs in the encoding: The plaintext must be UTF8 encoded and the ciphertext must be hex encoded:

            Source https://stackoverflow.com/questions/70809612

            QUESTION

            Encrypt data in Javascript, Decrypt data in C# using private/public keys
            Asked 2022-Jan-26 at 13:22

            I want to encrypt data in a web browser that is send to my C# backend and decrypted there.

            That fails because I am unable to decrypt the data generated on the frontend in the backend.

            Here's what I did so far.

            First I created a private/public key pair (in XmlString Format). I took the ExportPublicKey function to generate the public key file from here: https://stackoverflow.com/a/28407693/98491

            ...

            ANSWER

            Answered 2022-Jan-24 at 15:42

            You need to encrypt with the private key and then decrypt with the public key

            Source https://stackoverflow.com/questions/70835886

            QUESTION

            How do I calculate a key check value for AES-128-CBC?
            Asked 2022-Jan-13 at 16:47

            I'm trying to implement a function in Java to calculate the key check value for a 128 bit AES encryption key. The AES128CBCEncryptor class is implementing AES/128/CBC with ISO 9797-1 M2 padding.

            The only information I can find on the key check value algorithm for AES says "the KCV for an AES key is computed by encrypting 16 bytes, each with value '01'.". It does not specify how the IV should be constructed.

            Here is what I have thus far, but it's not generating the expected result:

            ...

            ANSWER

            Answered 2022-Jan-13 at 16:47

            For a Key Check Value (KCV) one generally uses single block encryption, without any mode such as ECB or CBC. As only a constant value of 16 bytes is used, there is no need for padding either.

            If you just have a CBC class that performs ISO 9797-1 M2 padding then you could encrypt the static value of 01010101010101010101010101010101 (hex encoding of 16 bytes), using an all-zero IV and taking the first 16 bytes from the result (removing 16 bytes of ciphertext at the end that is just encryption of the mandatory padding).

            As you can see in the image below, because the IV is all zero, the XOR with the plaintext leaves the input intact, basically making the first ciphertext identical to direct encryption with the block cipher.

            By WhiteTimberwolf (SVG version) - PNG version, Public Domain, https://commons.wikimedia.org/w/index.php?curid=26434096

            However, as you are using Java, it makes more sense to use a Cipher object using algorithm "AES/ECB/NoPadding" and use that to encrypt the value of 01010101010101010101010101010101 directly. ECB doesn't take an IV, so that problem is avoided. Also, no padding needs to be considered when "NoPadding" is specified.

            If you need fewer bytes: those are usually taken from the left (lowest index) of the result.

            Beware that these kinds of KCV's are somewhat dangerous as they show the ciphertext of one particular plaintext block. In the worst instances, this could lead to an adversary decrypting one ciphertext block, or for an authenticated scheme to lose its integrity/authentication properties.

            Commonly KCV's are over an all-zero plaintext block. Using an all one-valued block makes the chance that this happens smaller, but that chance is still significant.

            Source https://stackoverflow.com/questions/70683993

            QUESTION

            C# - How to Decrypt an Encrypted Private Key with Bouncy Castle
            Asked 2021-Dec-30 at 11:17

            I have a private key that was generated by running:

            ...

            ANSWER

            Answered 2021-Dec-30 at 11:17

            Depending on your .NET version, you may not need BouncyCastle at all. As of .NET Core 3.1 there is RSA.ImportEncryptedPkcs8PrivateKey() for DER encoded encrypted private PKCS#8 keys and as of .NET 5.0 there is even RSA.ImportFromEncryptedPem() for PEM encoded encrypted keys.

            Otherwise with C#/BouncyCastle the import of an encrypted private PKCS#8 key is available e.g. with:

            Source https://stackoverflow.com/questions/70526272

            QUESTION

            Problem Updating to .Net 6 - Encrypting String
            Asked 2021-Dec-20 at 23:09

            I'm using a string Encryption/Decryption class similar to the one provided here as a solution.

            This worked well for me in .Net 5.
            Now I wanted to update my project to .Net 6.

            When using .Net 6, the decrypted string does get cut off a certain point depending on the length of the input string.

            ▶️ To make it easy to debug/reproduce my issue, I created a public repro Repository here.

            • The encryption code is on purpose in a Standard 2.0 Project.
            • Referencing this project are both a .Net 6 as well as a .Net 5 Console project.

            Both are calling the encryption methods with the exact same input of "12345678901234567890" with the path phrase of "nzv86ri4H2qYHqc&m6rL".

            .Net 5 output: "12345678901234567890"
            .Net 6 output: "1234567890123456"

            The difference in length is 4.

            I also looked at the breaking changes for .Net 6, but could not find something which guided me to a solution.

            I'm glad for any suggestions regarding my issue, thanks!

            Encryption Class

            ...

            ANSWER

            Answered 2021-Nov-10 at 10:25

            The reason is this breaking change:

            DeflateStream, GZipStream, and CryptoStream diverged from typical Stream.Read and Stream.ReadAsync behavior in two ways:

            They didn't complete the read operation until either the buffer passed to the read operation was completely filled or the end of the stream was reached.

            And the new behaviour is:

            Starting in .NET 6, when Stream.Read or Stream.ReadAsync is called on one of the affected stream types with a buffer of length N, the operation completes when:

            At least one byte has been read from the stream, or The underlying stream they wrap returns 0 from a call to its read, indicating no more data is available.

            In your case you are affected because of this code in Decrypt method:

            Source https://stackoverflow.com/questions/69911084

            QUESTION

            Missing entries in user.config after decryption/encryption
            Asked 2021-Dec-01 at 09:21

            I like to store a username and password to the user.config in my C# .net5 program. I don't want to store the password direct and I decided to decrypt the userSettings section. After decryption parts of the file are missing.

            Orginal user.config:

            ...

            ANSWER

            Answered 2021-Dec-01 at 09:21

            After playing around with this for a while, I discovered that the issue comes from the ConfigurationSaveMode.Full option.

            In both ProtectSettings() and UnProtectSettings(), instead of

            Source https://stackoverflow.com/questions/70169794

            QUESTION

            multithreading or multiprocessing for encrypting multiple files
            Asked 2021-Nov-08 at 12:09

            i have created a function enc()

            ...

            ANSWER

            Answered 2021-Nov-07 at 12:03

            You need to rework your function.

            Python isn’t smart enough to know which part of the code you need multiprocessed.

            Most likely it’s the for loop right, you want to encrypt the files in parallel. So you can try something like this.

            Define the function which needs to be run for each loop, then, create the for loop outside. Then use multiprocessing like this.

            Source https://stackoverflow.com/questions/69872049

            QUESTION

            How do I correctly store encryption keys on macOS so only my executable can access them?
            Asked 2021-Sep-29 at 16:50
            Introduction

            Basically, how/where do I persist encryption keys my executable needs?

            Let me explain how my executable looks like. It's basically a Swift script that is compiled using swift build --configuration=release --product=App.

            Package.swift:

            ...

            ANSWER

            Answered 2021-Sep-29 at 16:50

            To protect your app from modification, codesign it. You can use a private key or use Apple's notarization service. This will ensure no one modifies your app or distributes an installer that tries to replace your app.

            Keychain items your app creates can have access control lists, but even by default, the OS won't allow other apps to read your app's keychain items without being approved by the user. The user will receive a pop-up indicating the item the app is requesting.

            So I believe your best bet is to sign your app, and store the data in Keychain. It should generally work as you want out of the box. But of course do a lot of testing. Generally these things fail-secure, so in most cases it won't leak any data to other apps. But you may get more pop-ups than you want the user to deal with if you make mistakes.

            Source https://stackoverflow.com/questions/69379477

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

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