DanielKeep.github.io

by DanielKeep HTML Version: Current License: No License

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DanielKeep.github.io is a HTML library. DanielKeep.github.io has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

DanielKeep.github.io

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DanielKeep.github.io has a low active ecosystem.

It has 34 star(s) with 6 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

There are 5 open issues and 3 have been closed. On average issues are closed in 0 days. There are no pull requests.

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Community Discussions

Trending Discussions on DanielKeep.github.io

Preserving struct field visibility with a macro

Where does nom's "$i" macro argument come from?

Use of internal rules in Rust macros 2.0

QUESTION

Preserving struct field visibility with a macro

Asked 2019-Dec-20 at 18:38

I'm trying to write a Rust macro that allows me to make use of the field names and types of a struct declaration, but I still need to emit the struct.

I've got it working with optional attributes, visibility of the struct (thanks to The Little Book of Rust Macros), but can't figure out how to deal with the optional presence of pub in the individual fields.

So far I've got:

...

ANSWER

Answered 2017-Feb-02 at 14:02

You can't. At least, not with a single, non-recursive rule. This is because Rust doesn't have a macro matcher for visibility.

The parse-macros crate contains a parse_struct! macro that shows the work necessary to completely parse a struct definition. Short version: you need to parse each field individually, with one rule for each of "has pub" and "doesn't have pub".

I'd also just note that there's another case your macro doesn't yet account for: attributes on the fields, which is needed for doc-comments on them to work.

Quite soon, macros 1.1 should be stabilised, which might provide an easier approach (assuming you can express your macro as a derivation, and don't care about older versions of Rust).

Source https://stackoverflow.com/questions/42003501

QUESTION

Where does nom's "$i" macro argument come from?

Asked 2019-Mar-22 at 16:22

I'm trying to understand how Rust macro captures work and am looking at the nom parser library.

Location nom/src/bytes.rs declares macro tag! which captures with ($i:expr, $tag: expr). However throughout the places where tag! is used it is used with only one argument, i.e. tag!("+"). Example: nom-lua52/op.rs. I've read tutorials about macros however this construct seems to be special.

It seems like the input $i is somehow implicit?

...

ANSWER

Answered 2018-Jul-16 at 18:24

The trick is that the tag!() macro call is inside the value! macro, which will match against tag! and pass it an additional parameter. This is described in the file implementing tag!.

Source https://stackoverflow.com/questions/51367781

QUESTION

Use of internal rules in Rust macros 2.0

Asked 2018-Oct-15 at 13:43

I cannot understand where lazy-static's @TAIL and @MAKE have been defined and their particular use cases.

If I've understood internal rules correctly, the primary usage of @as_expr in the example is to hide as_expr! (or in general, previously defined macros) from being exported i.e. it's a way of altering the global macro namespace. Following that, then @TAIL or @MAKE should already be a macro while I cannot find them in the lazy_static source.

...

ANSWER

Answered 2018-Oct-15 at 02:29

You linked to the definitions. @TAIL is right there three lines down on 137, @MAKE is on 162.

@name is not special in any way whatsoever. There is absolutely no special behaviour. It's just a sequence of tokens that cannot show up in "normal" code, and is thus unlikely to be accidentally matched to other rules. @as_expr does not hide an as_expr! macro, it's used instead of defining a publicly visible as_expr! macro.

Source https://stackoverflow.com/questions/52808949

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