christopher5106.github.io

 by   christopher5106 HTML Version: Current License: No License

kandi X-RAY | christopher5106.github.io Summary

kandi X-RAY | christopher5106.github.io Summary

christopher5106.github.io is a HTML library. christopher5106.github.io has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

christopher5106.github.io
Support
    Quality
      Security
        License
          Reuse

            kandi-support Support

              christopher5106.github.io has a low active ecosystem.
              It has 15 star(s) with 5 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              christopher5106.github.io has no issues reported. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of christopher5106.github.io is current.

            kandi-Quality Quality

              christopher5106.github.io has no bugs reported.

            kandi-Security Security

              christopher5106.github.io has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              christopher5106.github.io does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              christopher5106.github.io releases are not available. You will need to build from source code and install.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of christopher5106.github.io
            Get all kandi verified functions for this library.

            christopher5106.github.io Key Features

            No Key Features are available at this moment for christopher5106.github.io.

            christopher5106.github.io Examples and Code Snippets

            No Code Snippets are available at this moment for christopher5106.github.io.

            Community Discussions

            QUESTION

            Different Matrix multiplication behaviour between Keras and Pytorch
            Asked 2021-Jan-10 at 07:10

            I was trying to understand how matrix multiplication works over 2 dimensions in DL frameworks and I stumbled upon an article here. He used Keras to explain the same and it works for him. But when I try to reproduce the same code in Pytorch, it fails with the error as in the output of the following code

            Pytorch Code:

            ...

            ANSWER

            Answered 2021-Jan-10 at 07:10

            Matrix multiplication (aka matrix dot product) is a well defined algebraic operation taking two 2D matrices.
            Deep-learning frameworks (e.g., tensorflow, keras, pytorch) are tuned to operate of batches of matrices, hence they usually implement batched matrix multiplication, that is, applying matrix dot product to a batch of 2D matrices.

            The examples you linked to show how matmul processes a batch of matrices:

            Source https://stackoverflow.com/questions/65650760

            QUESTION

            YOLO and adjusting number of anchor boxes for custom dataset
            Asked 2019-Jan-09 at 16:02

            I am working on implementing YOLO v2 and 3 for object detection on a custom dataset. While YOLO v2 and 3 use something like 5 or so anchor boxes, I generally have maybe 50-100 detections each image. My sense is that if there are only 5 anchor boxes, then there are at most 5 detections per image right? So I was trying to understand if I needed to adjust the number of anchor boxes to my dataset.

            My questions is, does the number of anchor boxes need to be larger than the maximum count of bounding boxes in any training image? That way, I would never run into detections where there is no corresponding anchor box. Is that the right way of thinking about adapting YOLO?

            If my intuition is correct then would I need to do k-means to cluster the bounding boxes in the ground truth images and set the anchor box coordinates. Then I would use the usual regression method as specified in this blog post.

            Thanks for any help that anyone can provide.

            ...

            ANSWER

            Answered 2018-Jun-05 at 21:58

            My sense is that if there are only 5 anchor boxes, then there are at most 5 detections per image right?

            There are five anchor boxes for each prediction cell and not for the whole image. Lets consider Yolo v2, where the input image is of size 416x416x3 and outputs is 13x13xN . Each of the 13x13 corresponds to a 32x32 cell region in the input image (as shown in the image below from the blog post) and for each of the 13x13 cells there are 5 anchors defined. So you can technically have 13x13x5 bounding boxes for an image of size 416x416 (You can train with larger images as well, as yolo v2 is a fully convolutional network and then you get more cell regions).

            Lets say you have 50 bounding boxes in your image, each of the bounding box should be assigned to a cell based on how close the center of the bounding box is to the cell center. Now for this cell pick one of the 5 anchor boxes which gives the best IOU. For each cell construct a label that should contain confidence scores and box position and dimension of all 5 anchor boxes (except for the anchor box selected, others will be marked zero) along with the class scores.

            On the k-means clustering mentioned in the link, it describes how they arrived at the five anchor boxes. Its better you just stick with the 5 bounding boxes, unless you have any specific reasons to include more or have different shapes if any specific requirement arises.

            Source https://stackoverflow.com/questions/50708758

            QUESTION

            LSTM parity generator
            Asked 2018-Feb-07 at 20:57

            I am trying to learn deep learning, I have stumbled on one exercise here

            It is first warm-up exercise. I am stuck. For constant sequence of small lengths(2,3) it solves it no problem. However when I try whole sequence of 50. it stops at 50% accuracy, which is basically random guess.

            According to here it is too big flat space ant cant find gradient to solve it. So i tried approach of continuously increasing length ans saving model each time (2,5,10,15,20,30,40,50).It seems it does not generalise well, as if i type bigger sequence then what I learned it on, it fails.

            According to here it should be easy problem. I cant figure it out. There is used some different LSTM architecture hoverer.

            And one solution here to exactly same problem says it works with Adagrad optimizer and learning rate of 0.5.

            I am unsure about one bit at time, if I am feeding it right in first place. I hope I got it right.

            And for variable length, i tried and failed miserably.

            Code:

            ...

            ANSWER

            Answered 2018-Feb-07 at 20:57

            Well, this might be a really valuable exercise about LSTM and vanishing gradient. So let's dive into it. I'd start from changing task a little bit. Let's change our dataset to:

            Source https://stackoverflow.com/questions/48666843

            QUESTION

            How to calculate third element of caffe convnet?
            Asked 2017-Jun-11 at 07:58

            Following this question and this tutorial I've create a simple net just like the tutorial but with 100X100 images and first convolution kernel of 11X11 and pad=0.

            I understand that the formula is : (W−F+2P)/S+1 and in my case dimension became [51X51X3] (3 is channel of rgb) but the number 96 popup in my net diagram and as this tutorial said it is third dimension of the output, in other hand , my net after first conv became [51X51X96]. I couldn't figure out , how the number 96 calculated and why.

            Isn't the network convolution layer suppose to pass throw three color channel and the output should be three feature map? How come its dimension grow like this? Isn't it true that we have one kernel for each channel ? How this one kernel create 96(or in the first tutorial, 256 or 384) feature map ?

            ...

            ANSWER

            Answered 2017-Jun-11 at 07:57

            You are mixing input channels and output channels.
            Your input image has three channels: R, G and B. Each filter in your conv layer acts on these three channels and its spatial kernel size (e.g., 3-by-3). Each filter outputs a single number per spatial location. So, if you have one filter in your layer then your output would have only one output channel(!)
            Normally, you would like to compute more than a single filter at each layer, this is what num_output parameter is used for in convolution_param: It allows you to define how many filters will be trained in a specific convolutional layer.
            Thus a Conv layer

            Source https://stackoverflow.com/questions/44481504

            QUESTION

            Training Watson Visual Recognition classifier
            Asked 2017-May-30 at 06:29

            I am trying to evaluate the training function of the Watson visual Recognition API. Has anyone some experience with costumizing classifers for Visual Recognition? I have some expierence myself with training the classifier and found some infomation in this blog: http://christopher5106.github.io/computer/vision/2016/12/23/ibm-watson-bluemix-visual-api-to-create-custom-classifier.html

            What I really would like to know is how much pictures do I need of an object to classify it with an accuracy of 75%? How long does it take to get such a result?

            Thank you in advance for your help.

            ...

            ANSWER

            Answered 2017-May-30 at 06:29

            The number of pictures you need depends on how unique the object is, how many distinct image features a picture with it has, etc.

            To give you a few examples from my own experience:

            Logo detection: one image of the logo can be used to create several samples by adding noise, changing contrast, making small distortions and rotations, etc. If the logo is detailed and has good contrast, you should easily get 75%.

            Cat detection using Haar wavelets: 100 images with data augmentation can yield around 75%

            Human ear detection: about 300 images could get me to around 80%. This detector is being used in an iPhone app for virtual-trying eyeglasses.

            You can also try this out yourself using Kaggle's Dogs Vs. Cats data. Just try various classifiers on them with different amounts of data, and you will get a very good idea.

            Source https://stackoverflow.com/questions/44215222

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install christopher5106.github.io

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

            Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items

            Find more libraries
            CLONE
          • HTTPS

            https://github.com/christopher5106/christopher5106.github.io.git

          • CLI

            gh repo clone christopher5106/christopher5106.github.io

          • sshUrl

            git@github.com:christopher5106/christopher5106.github.io.git

          • Stay Updated

            Subscribe to our newsletter for trending solutions and developer bootcamps

            Agree to Sign up and Terms & Conditions

            Share this Page

            share link