remap | MapReduce platform in python

You need to first get the objects, before they can be tracked for changes. However, if all you're doing with the IQueryable is to update a member without touching anything else, it would be faster to just execute the UPDATE query.

Consider:

I'm going by what I remember from the last time I investigated this. Grain of salt and all that.

the fixed point format splits the integer and fractional parts of your (x,y)-coordinates into different maps.

it's "compact" in that CV_32FC2 or 2x CV_32FC1 uses 8 bytes per pixel, while CV_16SC2 + CV_16UC1 uses 6 bytes per pixel. also it's integer-only, so using it can free up floating point compute resources for other work.

the integer parts go into the first map, which is 2-channel. no surprises there.

the fractional parts are converted to 5-bit integers, i.e. they're multiplied by 32. then they're packed together, lowest 5 bits from one coordinate, higher next 5 bits from the other one.

the resulting funny number has a range of 0 .. 1023, or 0b00000_00000 .. 0b11111_11111, which encodes fractional parts (0.0, 0.0) and (0.96875, 0.96875) respectively (that's 31/32).

during remap...

the integer map is used to look up, for every resulting pixel, several pixels in the source image required for interpolation.

the fractional map is taken as an index into an "interpolation table", which is internal to OpenCV. it contains whatever factors and shifts required to correctly blend the several sampled pixels into one resulting pixel, all using integer math. I guess there are multiple tables, one for each interpolation method (linear, cubic, ...).

If you want to bind Tab for autocompletion, paste this in your .vimrc or init.vim

If you are using neovim there is an option called :h pumblend which can be used to change the transparency of the popup menu.

Are you sure gruvbox caused your vim to lose transparency? I am not sure if vim is able to change a terminal emulator's transparency. I or someone else might be able to advise you better if you post pictures of what has changed.

Huh, I'm not sure about how you worded the second last line there but I'm assuming the function you're writing is mapping [0,1.0] st. 0.05 -> 0.01, 0.25 -> 0.02 right?

If I'm following then 0 -> 0.1 and 1.0 -> -0.11.

Plotting that out looks pretty cubic to me, not logarithmic. It's been a while but I think there's a formula by Lagrange that you can use to interpolate the function

https://en.wikipedia.org/wiki/Lagrange_polynomial

Hope that's helpful!

You can use match -

Your first line for the USART3 initialization is wrong :-)

RCC->APB2ENR |= 1; // enable clock for AF

must be (without a clock the USART doesn't work)

RCC->APB1ENR |= (1<<18); // enable clock for USART

And as an additional hint, do not use all these magic numbers for the bits. This is much more readable (and the needed defines are already done in the CMSIS:

RCC->APB1ENR |= RCC_APB1ENR_USART3EN; // enable clock for USART

The problem was my Graph Editor when I import the tf.graph_def instead of the original tf.graph that has Variables.

Quickly solve by fixing step 3

Sol1: Using Graph Editor

To my understanding, plot requires 3 vectors with one dimension each. If you just extract one column of data from you arrays you be fine I think. See the example below: