flask-socketio-celery-example | Example based on Miguel Grinberg | Platform As A Service library

 by   jwhelland HTML Version: Current License: MIT

kandi X-RAY | flask-socketio-celery-example Summary

kandi X-RAY | flask-socketio-celery-example Summary

flask-socketio-celery-example is a HTML library typically used in Cloud, Platform As A Service, Docker applications. flask-socketio-celery-example has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Using Celery with Flask-SocketIO.
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              flask-socketio-celery-example has a low active ecosystem.
              It has 94 star(s) with 21 fork(s). There are 6 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              flask-socketio-celery-example has no issues reported. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of flask-socketio-celery-example is current.

            kandi-Quality Quality

              flask-socketio-celery-example has no bugs reported.

            kandi-Security Security

              flask-socketio-celery-example has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              flask-socketio-celery-example is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

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              flask-socketio-celery-example releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            Community Discussions

            QUESTION

            SocketIO to emit to a particular user (without using separate room for every client)
            Asked 2021-Mar-14 at 10:50

            I am trying to develop a web application that supports a long task at the backend. I am using flask-socketio package on my server along with celery. My workflow is following :

            1. When a client opens the Html page -- I initiate a socket connection to the server which creates a uid for the user and emits it back.
            2. Now once the user posts a request for the long task -- I schedule it using celery and once finished I need to emit it to the user who posted the request. (I stored the relevant userid in post request)

            I have looked at @Miguels's answer for 39423646/flask-socketio-emit-to-specific-user which creates a separate room for each user and then broadcasts the message on that room. But I wanted to ask if there is some other simpler way to do this since it seems inefficient or forced way to do this.

            I also came across the nodejs solution (how-to-send-a-message-to-a-particular-client-with-socket-io) which I felt to be a more natural way to accomplish this. Is there a similar solution in python-socketio too?

            Update: After some more search I came across the following solution on a github gist. According to this -- ** flash-socketIO already puts all clients in the separate room given by request.sid **.

            I would still wish to discuss other ways to do this. Specifically if the site traffic is quite high -- wouldn't it lead to too many rooms?

            Update (2): my current (working) server code which makes use of rooms. This is borrowed and modified from flask-SocketIO celery example

            ...

            ANSWER

            Answered 2021-Mar-13 at 08:50

            You can make a room for every separate user. And you can emit to a particular room which user you want to share the message.

            Source https://stackoverflow.com/questions/66610562

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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            Install flask-socketio-celery-example

            You can download it from GitHub.

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