books | Find books from Google Play Books | Runtime Evironment library
kandi X-RAY | books Summary
kandi X-RAY | books Summary
📚 Find books from Google Play Books - For all the book lovers in the world. https://liyasthomas.github.io/books
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of books
books Key Features
books Examples and Code Snippets
public Page findPaginated(Pageable pageable) {
int pageSize = pageable.getPageSize();
int currentPage = pageable.getPageNumber();
int startItem = currentPage * pageSize;
List list;
if (books.size() < startI
@Override
public BigInteger getAuthorBooksCount(String username) {
BigInteger bookcount;
try (var session = sessionFactory.openSession()) {
var sqlQuery = session.createSQLQuery(
"SELECT count(b.title)" + " FROM Book b, Aut
@Override
public List getAuthorBooks(String username) {
List bookDTos;
try (var session = sessionFactory.openSession()) {
var sqlQuery = session.createSQLQuery("SELECT b.title as \"title\", b.price as \"price\""
+ " FROM Aut
Community Discussions
Trending Discussions on books
QUESTION
I'm trying to get my head around programming real mode MS-DOS in C. Using some old books on game programming as a starting point. The source code in the book is written for Microsoft C, but I'm trying to get it to compile under OpenWatcom v2. I've run into a problem early on, when trying to access a pointer to the start of VGA video memory.
...ANSWER
Answered 2022-Apr-03 at 07:23It appears your OpenWatcom C compiler is defaulting to using C89. In C89 variable declarations must be at the beginning of a block scope. In your case all your code and data is at function scope, so the variable has to be declared at the beginning of main
before the code.
Moving the variable declaration this way should be C89 compatible:
QUESTION
The useHistory() hook is not working in my project. I have it in different components but none of them work. I am using "react-router-dom": "^5.2.0",
...ANSWER
Answered 2021-Aug-01 at 20:01QUESTION
I am learning about references in C++. In particular, i have learnt that references are not actual objects. Instead they refer to some other object. That is, reference are just alias for other objects.
Then i came across this which says:
Important note: Even though a reference is often implemented using an address in the underlying assembly language, please do not think of a reference as a funny looking pointer to an object. A reference is the object, just with another name. It is neither a pointer to the object, nor a copy of the object. It is the object. There is no C++ syntax that lets you operate on the reference itself separate from the object to which it refers.
I get that the above quote means that we can't operate on the reference itself separate from the object to which it refers but it still seems to imply that "a reference is an object".
Also, i have come across the the sentence given below:
In ISO C++, a reference is not an object. As such, it needs not have any memory representation.
I don't have a link to this 2nd quote but i read it in one of SO's post somewhere.
My question is that assuming the second quote is also from the standard(which may not be the case), doesn't these 2 quoted statements contradict each other. Or at least the first quote is misleading. Which one is correct.
My current understanding(by reading books like C++ Primer 5th edition) is that references are an alias for objects. Which leads me to the thinking that they should not take any space in memory.
...ANSWER
Answered 2022-Mar-18 at 17:40The first quote is really saying the reference is not separable from the object.
... still seems to imply that "a reference is an object".
It really implies that a reference is a non-separable, non-first-class alias for an object, exactly as you first said.
The difficulty with these discussions is that the standardese meaning of "object" is already different from the meaning used in most less-formal contexts.
Let's start simple:
int a;
Would often be described as declaring an integer object a
, right? It actually
- declares an integer object
- binds the name
a
to that object in the appropriate scope
Now, if we write
int &b = a;
we could say that b
is the object in the same way as we could say that a
is the object. Actually neither are correct, but given that informal text already uses the latter, it's no worse.
We should instead say that the name b
refers to the same object as the name a
. This is exactly consistent with calling it an alias, but informal or introductory texts would seem pretty cumbersome if they wrote "... the integer object referred to by the name a
..." everywhere instead of just "the integer a
".
As for taking space in memory ... it depends. If I introduce 100 aliases for a single object inside a single function I'd be really surprised if the compiler didn't just collapse them (although of course they might still show up in debug symbols). No information is being lost here by eliding the redundant names.
If I pass an argument by reference to a non-inlined function, some actual information is being communicated, and that information must be stored somewhere.
QUESTION
I saw an answer to a question here. There the author of the answer made use of the fact that
exception specifications do not participate1 in template argument deduction.
In the answer linked above it is explained why the following doesn't compile:
...ANSWER
Answered 2022-Mar-17 at 13:25Here since there is no func
, so during the substitution of the template argument(s) in the return type of the function template, we get substitution failure and due to SFINAE this function template is not added to the set. In other words, it is ignored.
Thus the call timer(5);
uses the ordinary function timer
since it is the only viable option now that the function template has been ignored. Hence the program compiles and gives the output:
QUESTION
I've read a few books on Haskell but haven't coded in it all that much, and I'm a little confused as to what Haskell is doing in a certain case. Let's say I'm using getLine
so the user can push a key to continue, but I don't really want to interpret that person's input in any meaningful way. I believe this is a valid way of doing this:
ANSWER
Answered 2022-Mar-03 at 19:06The first case is desugared like you expected:
QUESTION
I have the following 2 query plans for a particular query (second one was obtained by turning seqscan off):
The cost estimate for the second plan is lower than that for the first, however, pg only chooses the second plan if forced to do so (by turning seqscan off).
What could be causing this behaviour?
EDIT: Updating the question with information requested in a comment:
Output for EXPLAIN (ANALYZE, BUFFERS, VERBOSE)
for query 1 (seqscan on; does not use index). Also viewable at https://explain.depesz.com/s/cGLY:
ANSWER
Answered 2022-Feb-17 at 11:43You should have those two indexes to speed up your query :
QUESTION
I am reading this book by Fedor Pikus and he has some very very interesting examples which for me were a surprise.
Particularly this benchmark caught me, where the only difference is that in one of them we use || in if and in another we use |.
ANSWER
Answered 2022-Feb-08 at 19:57Code readability, short-circuiting and it is not guaranteed that Ord will always outperform a ||
operand.
Computer systems are more complicated than expected, even though they are man-made.
There was a case where a for loop with a much more complicated condition ran faster on an IBM. The CPU didn't cool and thus instructions were executed faster, that was a possible reason. What I am trying to say, focus on other areas to improve code than fighting small-cases which will differ depending on the CPU and the boolean evaluation (compiler optimizations).
QUESTION
I am trying to understand overloading resolution in C++ through the books listed here. One such example that i wrote to clear my concepts whose output i am unable to understand is given below.
...ANSWER
Answered 2022-Jan-25 at 17:19Essentially, skipping over some stuff not relevant in this case, overload resolution is done to choose the user-defined conversion function to initialize the variable and (because there are no other differences between the conversion operators) the best viable one is chosen based on the rank of the standard conversion sequence required to convert the return value of to the variable's type.
The conversion int -> double
is a floating-integral conversion, which has rank conversion.
The conversion float -> double
is a floating-point promotion, which has rank promotion.
The rank promotion is better than the rank conversion, and so overload resolution will choose operator float
as the best viable overload.
The conversion int -> long double
is also a floating-integral conversion.
The conversion float -> long double
is not a floating-point promotion (which only applies for conversion float -> double
). It is instead a floating-point conversion which has rank conversion.
Both sequences now have the same standard conversion sequence rank and also none of the tie-breakers (which I won't go through) applies, so overload resolution is ambigious.
The conversion int -> bool
is a boolean conversion which has rank conversion.
The conversion float -> bool
is also a boolean conversion.
Therefore the same situation as above arises.
See https://en.cppreference.com/w/cpp/language/overload_resolution#Ranking_of_implicit_conversion_sequences and https://en.cppreference.com/w/cpp/language/implicit_conversion for a full list of the conversion categories and ranks.
Although it might seem that a conversion between floating-point types should be considered "better" than a conversion from integral to floating-point type, this is generally not the case.
QUESTION
I am not using AWS AppSync for this app. I have created Graphql schema, I have made my own resolvers. For each create, query, I have made each Lambda functions. I used DynamoDB Single table concept and it's Global secondary indexes.
It was ok for me, to create an Book item. In DynamoDB, the table looks like this: .
I am having issue with the return Graphql queries. After getting the Items
from DynamoDB table, I have to use Map function then return the Items
based on Graphql type
. I feel like this is not efficient way to do that. Idk the best way query data. Also I am getting null both author and authors query.
This is my gitlab-branch.
This is my Graphql Schema
...ANSWER
Answered 2022-Jan-09 at 17:06TL;DR You are missing some resolvers. Your query resolvers are trying to do the job of the missing resolvers. Your resolvers must return data in the right shape.
In other words, your problems are with configuring Apollo Server's resolvers. Nothing Lambda-specific, as far as I can tell.
Write and register the missing resolvers.GraphQL doesn't know how to "resolve" an author's books, for instance. Add a Author {books(parent)}
entry to Apollo Server's resolver map. The corresponding resolver function should return a list of book objects (i.e. [Books]
), as your schema requires. Apollo's docs have a similar example you can adapt.
Here's a refactored author
query, commented with the resolvers that will be called:
QUESTION
Supposing I'm running a Servant webserver, with two endpoints, with a type looking like this:
...ANSWER
Answered 2022-Jan-02 at 18:53Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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