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def resource_input_index(tensor_name, input_names, node_defs, functions):
"""Returns the index of the input corresponding to `tensor_name`.
This method is used to find the corresponding index of an arbitrary resource
tensor in a function (the
def index_of(
self, file_path, line_number, called_function_name, called_file_path,
called_function_start_line):
"""Returns index of the location, adding the location if needed.
Args:
file_path: (string) Path to file that m
def get_squared_primes_to_use(
num_to_look: int, squared_primes: list[int], previous_index: int
) -> int:
"""
Returns an int indicating the last index on which squares of primes
in primes are lower than num_to_look.
This metho
Community Discussions
Trending Discussions on the-index
QUESTION
I'm trying to get pull a value from an array based on the index and I can't get it to work for some reason. Keeps returning -1
...ANSWER
Answered 2021-Jun-06 at 18:57Hope this helps you identify the problem:
QUESTION
When using 'git ls-files -s' and 'git log' on the same file, I get different SHA hashes. Take the file lib/nerdtree/nerdtree.vim in repo https://github.com/preservim/nerdtree, tag 6.10.5, for example.
The command git log lib/nerdtree/nerdtree.vim
produces,
commit 593c16add35a5461f189b8189abe219f7bbbd604 (tag: 6.10.5)
But the command git ls-files -s lib/nerdtree/nerdtree.vim
produces,
100644 61a11a96ba44c7b1bf0472b598f2c967b2dce9f2 0 lib/nerdtree/nerdtree.vim
If I attempt to checkout the SHA returned by 'git log', that command succeeds. If I attempt to checkout the SHA returned by 'git ls-files -s', that produces a fatal error:
git checkout 61a11a96ba44c7b1bf0472b598f2c967b2dce9f2 lib/nerdtree/nerdtree.vim
fatal: reference is not a tree: 61a11a96ba44c7b1bf0472b598f2c967b2dce9f2
Why does 'git ls-files -s' and 'git log' produce different SHA hashes for the same file?
NOTE: I searched around for an answer and found this thread: Git - finding the SHA1 of an individual file in the index. This thread explains why there might be differences between the output of 'git hash-object' and 'git ls-files -s', but it does not explain the difference between the output of 'git ls-files -s' and 'git log'.
...ANSWER
Answered 2021-Jun-02 at 19:37git log
with a path lists commits that change what's recorded at that path.
git ls-files
with a path lists what's recorded in your current checkout at that path.
QUESTION
Hi peeps, this question is closely related to this question. Instead of getting the name
of the Series, now I'd like to get the index
of each particular series. I've tried using the x.index
but it returns a list of indices instead of the index
of that particular cell.
ANSWER
Answered 2021-May-07 at 04:24You can directly modify the row
Series and return the modified row
Series.
QUESTION
The indexes of the k lowest elements of an array can be found using np.argpartition as in this question, I can only think of applying this to many rows using a loop. Is there a way that this can be done without a loop, using some kind of matrix operation? I would like a resulting matrix where each row contains k indexes (of the k lowest elements).
...ANSWER
Answered 2021-Mar-06 at 18:10You don't have to worry about having to use loops in NumPy. All such operations are broadcastable. If you want to apply the op to a matrix and have each row containing k lowest elements, use np.argpartition(matrix, axis=-1)
QUESTION
I've been noodling over this postgres DB schema and query for a while now and I think I need a fresh set of eyes to understand if/how it can be improved. My schema and query are rather simple which is why a query time of 600-700 MS feels wrong but maybe that's just what it is.
For background I have a table of IPs that contain basic information about an IP address, and a second table containing DNS names mapped back to the IP table via a has many foreign key. An example subset of the data the query in question was run against contained ~5 million IPs with ~39 million associated domains. The table schema is shown below:
This allows queries like the one this question is about:
...ANSWER
Answered 2021-Feb-27 at 17:26This was a classic case of rubber duck debugging! While writing this I had a great insight that greatly reduced the query times!
Suffix fuzzy searches are much faster than prefix searches. (foo%
vs %bar
) so what I did was use the reverse function on the domain field in the DB which results in this (ford.com
=> moc.drof
) and switched the query to using a suffix fuzzy search:
QUESTION
I do realize this has already been addressed here (e.g., Removing duplicates in the lists), Accessing the index in 'for' loops?, Append indices to duplicate strings in Python efficiently and many more...... Nevertheless, I hope this question was different.
Pretty much I need to write a program that checks if a list has any duplicates and if it does, returns the duplicate element along with the indices.
The sample list sample_list
ANSWER
Answered 2021-Feb-10 at 12:09You could do something along these lines:
QUESTION
I tried this link Stack Link FOR 404 Error but error not going showing 404 error for area
...ANSWER
Answered 2021-Jan-27 at 07:07you can add a pattern like this for different areas. For student area you add this code snippet:
QUESTION
How can I find the index of an element, when the element is determined using quantile()
?
The match()
and which()
solutions from this similar question do not work (they return NA), and I think they don't work because of rounding issues.
In the case that the quantile result is averaged/interpolated across two indices, can I specify if it takes the lower/higher index? My data x
will always be sorted.
Example Dataset (Obviously the 0 and 1 quantiles here are just the min and max, they are just shown for a sanity check)
...ANSWER
Answered 2021-Jan-26 at 03:09Use findInterval
?
QUESTION
I am trying to copy the index of a dataframe (newdf
) to a new column (temp_index
) using the answer here but am receiving the infamous SettingWithCopyWarning
. I tried the answer here, which says to add .loc[:, colname]
but it throws even more warnings. All errors are thrown on the last line of code; no errors come up if the code stops when newdf
is created.
What's the correct way to copy the index? Would prefer not to reset the index, I'd like the indices from df
and newdf
to be agreeable. I just need the copy column for something else.
Example Reproducible Code
...ANSWER
Answered 2021-Jan-24 at 18:14There's nothing wrong with how you are setting the temp_index
column in the last line. The issue is as it says in the warning. What are you actually trying to achieve? To avoid this warning do newdf = df[df.col2 >= 3].copy()
. Note you are indexing with a Boolean key which, AFAIK, creates a copy anyway so the above will not increase your memory footprint.
If you actually want to insert the index to df
but only to a subset of the rows try
QUESTION
This question is related to but different from this one, which wonders how to access the row index from within apply. That can be done with row.name
. However, in my case I am applying a function to query
'd dataframe, and the row's name
are just their index in the original df. I need them to be zero-based for the queried DataFrame.
ANSWER
Answered 2021-Jan-12 at 09:18I think you want default index, because filtered rows has original index, there is no change:
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