pieces | Here are some random pieces of code , tools , and scripts | Runtime Evironment library

 by   wqking HTML Version: Current License: Non-SPDX

kandi X-RAY | pieces Summary

kandi X-RAY | pieces Summary

pieces is a HTML library typically used in Server, Runtime Evironment, Nodejs applications. pieces has no bugs, it has no vulnerabilities and it has low support. However pieces has a Non-SPDX License. You can download it from GitHub.

Here are some random pieces of code, tools, and scripts. They are too small to be a separated repository. If no specified, all codes are under Apache License, Version 2.0. Each folder is one piece of code. The folder name contains the programming language, and something about what the code does.

            kandi-support Support

              pieces has a low active ecosystem.
              It has 2 star(s) with 1 fork(s). There are 2 watchers for this library.
              It had no major release in the last 6 months.
              pieces has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of pieces is current.

            kandi-Quality Quality

              pieces has 0 bugs and 0 code smells.

            kandi-Security Security

              pieces has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              pieces code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              pieces has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              pieces releases are not available. You will need to build from source code and install.
              It has 251 lines of code, 0 functions and 1 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

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            pieces Key Features

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            pieces Examples and Code Snippets

            No Code Snippets are available at this moment for pieces.

            Community Discussions


            Why do these ways of creating a reference behave differently?
            Asked 2022-Apr-02 at 18:41

            The following code runs correctly.



            Answered 2022-Apr-02 at 18:41

            This is a concept in Rust called temporary lifetime extension. There are rules that govern when a temporary's lifetime is extended, though. It doesn't happen any time a borrow of a temporary occurs; the expression on the right side of a let statement needs to be a so-called "extending expression." This part of the document linked above neatly explains the first and third examples in your question:

            So the borrow expressions in &mut 0, (&1, &mut 2), and Some { 0: &mut 3 } are all extending expressions. The borrows in &0 + &1 and Some(&mut 0) are not: the latter is syntactically a function call expression.

            Since the expression assigned to a in the third example isn't an extending expression, the lifetime of the temporary is not extended beyond the let statement, and that causes the lifetime problem.

            Why does this work for Some(&3) then? Because of constant promotion:

            Promotion of a value expression to a 'static slot occurs when the expression could be written in a constant and borrowed, and that borrow could be dereferenced where the expression was originally written, without changing the runtime behavior.

            Since you borrow immutably, Rust allocates a hidden, static i32 and borrows that instead, giving you an Option<&'static i32>, which is obviously valid for the whole life of the program itself. This is not technically temporary lifetime extension because after the i32 is promoted to have static lifetime it's no longer a temporary.

            It's basically equivalent to this (except that HIDDEN has no name):

            Source https://stackoverflow.com/questions/71719617


            log4js-node-DEP0004 - Deprecation warning in Angular 12 karma unit tests
            Asked 2022-Feb-16 at 17:00

            I'm getting the following deprecation warning when running unit tests in a brand new Angular 12 application:

            (node:14940) [log4js-node-DEP0004] DeprecationWarning: Pattern %d{DATE} is deprecated due to the confusion it causes when used. Please use %d{DATETIME} instead.

            why log4js prompts "karma" depends on it. The warning itself is clear as to what should be done but there are two key missing pieces of information:

            • it doesn't say when/if the old syntax will stop working
            • it doesn't provide a workaround (other than forking karma and replacing the deprecated syntax with the new one - which I'm definitely not going to do).

            Downgrading log4js to an earlier version, which doesn't output the warning, using forceResolutions doesn't seem like a good idea, especially since I've found a few github threads related to vulnerabilities in it, although karma doesn't seem to be affected.

            The question: are there actionable paths for not getting the warning, or is "and now we wait" (for a karma update) the only option?

            Note: I've also asked it on karma's repo.



            Answered 2022-Feb-16 at 17:00

            Got the fix from karma maintainers:

            Update karma (in package.json > devDependencies.karma) to ^6.3.12.

            Warnings gone. Well done, karma. That was fast!

            Source https://stackoverflow.com/questions/70841924


            Why does "L.insert(it--, i);" behave differently from "L.insert(it, i); it--;"?
            Asked 2022-Feb-08 at 15:53

            These are two pieces of code that I ran under the C++11 standard. I expected the post-decrement of the iterator to produce the same effect, but these two pieces of code produce completely different results. Where is my understanding off?



            Answered 2022-Feb-08 at 15:38

            Your code invokes undefined behaviour.

            The begin iterator is not decrementable and the behavior is undefined if --container.begin() is evaluated.


            As such, anything could happen.

            Source https://stackoverflow.com/questions/71036571


            How to automate legends for a new geom in ggplot2?
            Asked 2022-Jan-30 at 18:08

            I've built this new ggplot2 geom layer I'm calling geom_triangles (see https://github.com/ctesta01/ggtriangles/) that plots isosceles triangles given aesthetics including x, y, z where z is the height of the triangle and the base of the isosceles triangle has midpoint (x,y) on the graph.

            What I want is for the geom_triangles() layer to automatically provide legend components for the height and width of the triangles, but I am not sure how to do that.

            I understand based on this reference that I may need to adjust the draw_key argument in the ggproto StatTriangles object, but I'm not sure how I would do that and can't seem to find examples online of how to do it. I've been looking at the source code in ggplot2 for the draw_key functions, but I'm not sure how I would introduce multiple legend components (one for each of height and width) in a single draw_key argument in the StatTriangles ggproto.



            Answered 2022-Jan-30 at 18:08

            I think you might be slightly overcomplicating things. Ideally, you'd just want a single key drawing method for the whole layer. However, because you're using a Stat to do the majority of calculations, this becomes hairy to implement. In my answer, I'm avoiding this.

            Let's say I'd want to use a geom-only implementation of such a layer. I can make the following (simplified) class/constructor pair. Below, I haven't bothered width_scale or height_scale parameters, just for simplicity.


            Source https://stackoverflow.com/questions/70916440


            Best functional-style syntax to build this object?
            Asked 2022-Jan-16 at 10:59

            The below code achieves desired output. Is there a more elegant way to do this?

            For example, is there some native javascript function like flatMap etc that would help?

            (I know I could get rid of the intermediate variable pieces).



            Answered 2022-Jan-15 at 04:01

            It's more concise, and I think prettier, to pair fromEntries with a map over .entries.

            Source https://stackoverflow.com/questions/70718736


            unit testing callbackFlow
            Asked 2022-Jan-04 at 16:11

            I have a callback based API like this:



            Answered 2022-Jan-04 at 16:03

            and an extension function which converts the API into a hot flow

            This extension looks correct, however the flow is not hot (nor should it be). It only registers a callback when an actual collection starts, and unregisters when the collector is cancelled (this includes when the collector uses terminal operators that limit the number of items, such as .first() or .take(n)).

            This is quite an important note to keep in mind for your other questions.

            In the absence of that SupervisorJob(), it appears that test will never end. Maybe collecting the flow never ends for some reason, which I don't understand

            As mentioned above, due to how the flow is constructed (and how the CallbackApi works), the flow collection cannot end by decision of the producer (the callback API). It can only stop by cancellation of the collector, which will also unregister the correponding callback (which is good).

            The reason your custom job allows the test to end is probably because you're escaping structured concurrency by overriding the job in the context by a custom one that doesn't have that current job as parent. However you're likely still leaking that neverending coroutine from the scope that is never cancelled.

            I'm feeding captured callback in a separate coroutine.

            And that's correct, although I don't understand why you call removeListener from this separate coroutine. What callback are you unregistering here? Note that this also cannot have any effect on the flow, because even if you could unregister the callback that was created in the callbackFlow builder, it wouldn't magically close the channel of the callbackFlow, so the flow wouldn't end anyway (which I'm assuming is what you tried to do here).

            Also, unregistering the callback from outside would prevent you from checking it was actually unregistered by your production code.

            2- If I remove the launch body which callbackSlot.captured.onResult(10) is inside it, test will fail with this error UninitializedPropertyAccessException: lateinit property captured has not been initialized. I would think that yield should start the flow.

            yield() is quite brittle. If you use it, you must be very conscious about how the code of each concurrent coroutine is currently written. The reason it's brittle is that it will only yield the thread to other coroutines until the next suspension point. You can't predict which coroutine will be executed when yielding, neither can you predict which one the thread will resume after reaching the suspension point. If there are a couple suspensions, all bets are off. If there are other running coroutines, all bets are off too.

            A better approach is to use kotlinx-coroutines-test which provides utilities like advanceUntilIdle which makes sure other coroutines are all done or waiting on a suspension point.

            Now how to fix this test? I can't test anything right now, but I would probably approach it this way:

            • use runTest from kotlinx-coroutines-test instead of runBlocking to control better when other coroutines run (and wait for instance for the flow collection to do something)
            • start the flow collection in a coroutine (just launch/launchIn(this) without custom scope) and keep a handle to the launched Job (return value of launch/launchIn)
            • call the captured callback with a value, advanceUntilIdle() to ensure the flow collector's coroutine can handle it, and then assert that the list got the element (note: since everything is single threaded and the callback is not suspending, this would deadlock if there was no buffer, but callbackFlow uses a default buffer so it should be fine)
            • optional: repeat the above several times with different values and confirm they are collected by the flow
            • cancel the collection job, advanceUntilIdle(), and then test that the callback was unregistered (I'm not a Mockk expert, but there should be something to check that removeListener was called)

            Note: maybe I'm old school but if your CallbackApi is an interface (it's a class in your example, but I'm not sure to which extent it reflects the reality), I'd rather implement a mock manually using a channel to simulate events and assert expectations. I find it easier to reason about and to debug. Here is an example of what I mean

            Source https://stackoverflow.com/questions/70576533


            GitHub Codespaces: how to set x86_64, AMD64, ARM64 platform?
            Asked 2021-Dec-17 at 21:44

            First, the question: is there a way to choose the platform (e.g. x86_64, AMD64, ARM64) for a GitHub Codespace?

            Here's what I've found so far:

            Attempt 1 (not working):

            From within GitHub.com, you can choose the "machine" for a Codespace, but the only options are RAM and disk size.

            Attempt 2 (EDIT: not working): devcontainer.json

            When you create a Codespace, you can specify options by creating a top-level .devcontainer folder with two files: devcontainer.json and Dockerfile

            Here you can customize runtimes, installed packages, etc., but the docs don't say anything about determining architecture...

            ...however, the VSCode docs for devcontainer.json has a runArgs option, which "accepts Docker CLI arguments"...

            and the Docker CLI docs on --platform say you should be able to pass --platform linux/amd64 or --platform linux/arm64, but...

            When I tried this, the Codespace would just hang, never finishing building.

            Attempt 3 (in progress): specify in Dockerfile

            This route seems the most promising, but it's all new to me (containerization, codespaces, docker). It's possible that Attempts 2 and 3 work in conjunction with one another. At this point, though, there are too many new moving pieces, and I need outside help.

            1. Does GitHub Codespaces support this?
            2. Would you pass it in the Dockerfile or devcontainer.json? How?
            3. How would you verify this, anyway? [Solved: dpkg --print-architecture or uname -a]
            4. For Windows, presumably you'd need a license (I didn't see anything on GitHub about pre-licensed codespaces) -- but that might be out of scope for the question.




            Answered 2021-Dec-17 at 21:44

            EDIT: December 2021

            I received a response from GitHub support:

            The VM hosts for Codespaces are only x86_64 and we do not offer any ARM64 machines.

            So for now, setting the platform does nothing, or fails.

            But if they end up supporting multiple platforms, you should be able to (in Dockerfile)

            RUN --platform=arm64|amd64|x86-64 [image-name],

            Which is working for me in the non-cloud version of Docker.

            Original answer:

            I may have answered my own question

            In Dockerfile:

            I had RUN alpine

            changed to

            RUN --platform=linux/amd64 alpine


            RUN --platform=linux/x86-64 alpine

            checked at the command line with

            uname -a to print the architecture.

            Still verifying, but seems promising. [EDIT: Nope]

            So, despite the above, I can only get GitHub codespaces to run x86-64. Nevertheless, the above syntax seems correct.

            A clue:

            In the logs that appear while the codespace is building, I saw target OS: x86

            Maybe GitHub just doesn't support other architectures yet. Still investigating.

            Source https://stackoverflow.com/questions/70219806


            Variable assignment avoids an infinite loop
            Asked 2021-Sep-01 at 13:49

            I have two pieces of recursive code, intending to recursively print out half of the array until we get to arrays of array length 1. The code without variable assignment runs infinitely while the code with variable assignment behaves as expected.

            Any clues why this is the case?

            Runs infinitely, CAREFUL



            Answered 2021-Sep-01 at 13:49

            Because it lacks var, let and const, halfway has global scope, as if you wrote window.halfway. As a result, all recursive calls modify and use the same single variable.

            In the 1st function the value is changed in the first recursive call before it can be used in the second recursive call. In my testing this actually led to a kind of Stack Overflow error (or rather a Maximum call stack size error), very appropriate for this site :-).

            In the 2nd function the value is used twice before the recursive calls start, and then it gets modified by both after each other.

            Issue solved by using const:

            Source https://stackoverflow.com/questions/69014517


            Discord.py How to make clean dialog trees?
            Asked 2021-Aug-16 at 15:49

            My goal is to clean up my code so that I can more easily make dialog trees without constant copied pieces that don't have to be there. I can do it cleanly in python, but discord.py seems to have different requirements. Here is a sample of my current, very redundant code:



            Answered 2021-Aug-16 at 15:08
            di = {'hallucinated': {
                1: {
                    'Text': [
                        "It sounds like you may be hallucinating, would you like help with trying to disprove it?"
                    'Options': {'yes': 2, 'no': 3}
                2: {
                    'Text': [
                        "Is it auditory, visual, or tactile?"
                    'Options': {
                        "auditory": 4,
                        "visual": 5,
                        "tactile": 6
            # Modified the dictionary a little bit, so we can get the option values directly, and the starter keywords.
            def make_check(options, message):
                def predicate(msg):
                    return msg.author == message.author and msg.channel == message.channel and msg.content.lower() in options
                return predicate
            # I noticed the check function in your code was repetitive, we use higher order functions to solve this
            async def response(dialogues, number, message, client): 
                await message.channel.send(dialogues[number]['Text'])
                options = [x[0] for x in dialogues[number]['Options']]
                if options:
                    msg = await client.wait_for("message", check=make_check(options, message), timeout=30.0)
                    return await response(dialogues, dialogues[number]['Options'][msg], message, client)
                    # end dialogues
            # Use recursion to remove redundant code, we navigate through the dialogues with the numbers provided
            async def on_message(message):
                # basic on_message for example
                starters = ['hallucinated']
                initial = [x for x in starters if x in message.content.lower()]
                if initial:
                    initial_opening_conversation = initial[0]
                    await response(di.get(initial_opening_conversation), 1, message, client)

            Source https://stackoverflow.com/questions/68747114


            `if let` does not run destructor if intermediary value
            Asked 2021-Aug-07 at 10:05

            Consider two semantically equivalent pieces of code:



            Answered 2021-Aug-07 at 10:05

            The answer can be found on docs.rust-lang.org. Specifically refer to if let article, where it's said that:

            An if let expression is equivalent to a match expression as follows:

            if let PATS = EXPR { /* body */ } else { /*else */ }

            is equivalent to

            match EXPR { PATS => { /* body */ }, _ => { /* else */ } }

            After heading to the match article, it's said that

            A match behaves differently depending on whether or not the scrutinee expression is a place expression or value expression.

            If the scrutinee expression is a value expression, it is first evaluated into a temporary location, and the resulting value is sequentially compared to the patterns in the arms until a match is found. The first arm with a matching pattern is chosen as the branch target of the match, any variables bound by the pattern are assigned to local variables in the arm's block, and control enters the block.

            ... more about place expressions

            In your case the scrutinee *x.lock().unwrap() is a value expression, thus the guard's lifetime is the same as the lifetime of your main branch. Thus you get a deadlock, trying to .lock() mutex again after it's already locked by your own if let

            Source https://stackoverflow.com/questions/68691171

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