Ency | 『Ency』 微信精选 & 每日一文 & 干货热门 & 开眼视频 & 我的收藏 的Android客户端
kandi X-RAY | Ency Summary
kandi X-RAY | Ency Summary
『Ency』 微信精选&每日一文&干货热门&开眼视频&我的收藏 的Android客户端
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Top functions reviewed by kandi - BETA
- Initializes drawable
- Exit the app
- Read assets value
- Remove all activity
- Provide an OkHttpClient
- Checks if the network is connected
- Initializes the View
- Initialize JavaScript
- Get network type
- Get operator name
- Get IP address
- Sets the icon to be selected
- Initialize view
- Convert the item view
- Get value by key
- This method initializes IxInAdapter
- Initializes the instance
- Check download status
- Called when a navigation item is selected
- Initializes the instance
- Method used to initialize the recyclerView
- Called when an item is selected
- Region ImageVideoCollection
- Initializes the GankAdapter
- Initialize view
- Initialize the recyclerView
Ency Key Features
Ency Examples and Code Snippets
Community Discussions
Trending Discussions on Ency
QUESTION
I have a problem. I created 2 maven projects and copied both the folders to my Ubuntu server. When I want to mvn package
program A, which has included the dependency of project B (Simulator):
ANSWER
Answered 2021-Jun-08 at 18:47You need to run mvn install
on the dependency first.
QUESTION
I am capturing MQTT traffic for troubleshooting using below command
...ANSWER
Answered 2020-Sep-24 at 20:35As @hardillb suggested, use tshark instead. Due to tshark's architecture, you can't write a file at the same time as a display filter (it would be too slow).
To get the information you need, it would look something like this
QUESTION
I have a Django application that has a long name "encyclopedia". I would like the url for the application that appears on the address bar to be something shorter like "http://127.0.0.1:8000/ency" instead of "http://127.0.0.1:8000/encyclopedia" . What is the simplest way to accomplish this without compromising the functionality of the application?
I suspect its something very simple like modifying ROOT_URLCONF in settings.py. There is a general lack of examples that illustrate how to in the documents.
...ANSWER
Answered 2020-Sep-10 at 19:11Assuming you have a separate urls.py file for the Django application "encyclopedia", simply include it as follows in the main urls.py file of your project:
QUESTION
So this program is supposed to marshall the object I've created. I create an object and give value to every property it has, with the intention of generating a .xml with its data. To do so i have to make an instance of JAXBContext in which I specify the class of the object. And this is where i get the IndexOutOfBoundsException:
"JAXBContext jc = JAXBContext.newInstance(HealthTopic.class);"
Right as i get to the above mentioned line, i get
Output from ActividadXML3
...ANSWER
Answered 2020-May-19 at 03:35in HealthTopic class, change your getter for list. if list is null then create object and then only return list like below (change for all list):
QUESTION
I'm trying to package my Spring Boot App which uses Jersey. When the app is launched during development it has no problems to run, the problem comes when I generate a jar file using
...ANSWER
Answered 2018-May-30 at 02:05Jersey classpath scanning limitations
The change to the layout of executable jars means that a limitation in Jersey’s classpath scanning now affects executable jar files as well as executable war files. To work around the problem, classes that you wish to be scanned by Jersey should be packaged in a jar and included as a dependency in BOOT-INF/lib. The Spring Boot launcher should then be configured to unpack those jars on start up so that Jersey can scan their contents.
This is a known problem and there is a open pull request that's not merged yet. I suggest you refer this issue which mentions some workarounds.
There are few workarounds
Configure Boot's Maven plugin to unpack the jars containing that package
Use the below workaround
QUESTION
My application was running fine locally but when I deployed to heroku, I got application error. I tried several times the same thing happening. I checked database connection and everything is fine. These are my logs
...ANSWER
Answered 2017-Jun-13 at 19:57If your Heroku account has not been verified, then you cannot install AddOns (such as the Database AddOn). You can solve this by adding a credit card in Heroku's dashboard. Full instructions can be found in Heroku's docs:
To verify your Heroku account:
1) Go to your account page.
2) Click the Billing tab.
3) Click Add Credit Card.
This error is now printed during deployment in JHipster v4.5.3+, in previous versions it was ignored silently.
QUESTION
For some reason this little part of my code is giving me a problem. I have been trying to figure out why it is giving me a "list index out of range" error
...ANSWER
Answered 2017-Oct-30 at 16:14I'm assuming arg
is a string. string.split()
does not accept regex as delimiter. You can read about it here.
Instead, you should use arg.split("Manufacturer/Distributor name", 1)[1]
.
QUESTION
Right now I've implemented serveral if
s to specify each condition, once the case is specified:
- strip
@
(@
only appears at the end of a token) - join with the following word
- replace the afterwards tokens with the newly created token
But as you see (from the code), it's very repetitive, could anyone suggest a more concise way to present the code?
A snapshot of the code:
...ANSWER
Answered 2017-Oct-21 at 06:04Alright , this is a litte repetitive but should do it
QUESTION
Here I want to store the data from the list given on a website page. If I'm running the commands
...ANSWER
Answered 2017-Mar-06 at 14:41You need to fix your URL, it is https://medlineplus.gov/ency/article/000178.htm
and not https://medlineplus.gov/ency/article/000178.html/
.
Also, and more importantly, you need to define an Item
class and yield/return it from the parse()
callback of your spider:
QUESTION
I obtain this error when I try to launch Hybris platform at runtime:
...ANSWER
Answered 2017-Mar-01 at 22:38It is looking for the default constructor, hence the ()
. You need to either create a default constructor, or utilize constructor arguments when you declare the bean.
In this case, since you are extending the existing TokenBasedRememberMeServices
class, you will need to declare the bean with the relevant constructor arguments (key, userDefaultsService) instead of injecting them as properties. Your declaration should look something like this:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install Ency
You can use Ency like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the Ency component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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