hermit | 能将对API的调用转化为对手机的操作,软件自身提供 restful API,运行于安卓,一切操作与获取信息均由软件完成。
kandi X-RAY | hermit Summary
kandi X-RAY | hermit Summary
Hermit,是一款用于Android自动化测试的软件,运行于安卓,通过接收restful API请求,进而转化为对设备的操作。 支持快速的点击、滑动、读取与设置剪切板(支持中文)、模拟输入、寻找控件并点击等一系列操作,支持可视化布局分析。 大小不到 3Mib,默认运行端口9999。.
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- Get device info
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- Click by text
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- List all packages
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hermit Key Features
hermit Examples and Code Snippets
Community Discussions
Trending Discussions on hermit
QUESTION
I'm trying to produce entailment for the rule in OWL 2 RL 'The Semantics of Equality' using owl-api. I already tried to follow: Why the inferences visualised in Protege differ from the exported inferred axioms
...ANSWER
Answered 2021-May-16 at 14:02There is no inferred axiom generator that materialises the sameAs
relations. You could write one yourself, based e.g., on InferredPropertyAssertionGenerator
, or you can open an issue on the OWLAPI GitHub repo for the functionality to be added to the library.
QUESTION
This ontology does not quite seem to do what I have in mind:
...ANSWER
Answered 2021-May-08 at 15:32In your first snippet, it is clear that the intersection must be an OWL class because it is an intersection of OWL classes. Therefore, :CClass
must also be an OWL class. However, this implies some reasoning based on how terms are defined. An OWL parser does not have to apply reasoning and should be directed explicitly to whether a term is an OWL class, an object property, a datatype property, an individual, an ontology, an annotation property, a datatype or some other kind of annotation. In the case of an owl:intersectionOf
axiom, it is possible that you are declaring a datatype, rather than an OWL class. So it is only by looking at the content of the list, and finding how the terms inside are declared (viz., :AClass
and :BClass
), that you can eventually infer that they are all OWL classes, and therefore the intersection is an OWL class, and therefore it is equivalent to an OWL class, and therefore :CClass
should or could appear as an OWL class in the editor. OWL tools are free to make this kind of inferences for the sake of robustness, but it is not mandated by the OWL standard.
Edit for clarification: the standard defines a way to map RDF graphs to the abstract syntax of OWL where the constructs that use owl:intersectionOf
can be mapped to either a class definition or a datatype definition. The only way the standard recommends to discriminate the two cases is by adding explicitly rdf:type owl:Class
or rdf:type rdfs:Datatype
(see Tables 12 and 13 of OWL 2 Web Ontology Language Mapping to RDF Graphs). OWL parsers may go beyond what the standard recommends and infer some types based on the context, but they do not have to do it. I know that the OWL API does some such syntactic inferences to avoid crashing on every invalid ontologies.
QUESTION
What kind of OWL profiles are supported in VOS DL, EL, QL ,RL? Is is possible to use or integrate standard reasoners? (Hermit, Pellets, etc.)
...ANSWER
Answered 2021-May-04 at 15:02Reasoning support in Virtuoso Open Source (VOS) is detailed in the inferencing and reasoning documentation. Integration with other standard reasoners is not supported, although it probably could be implemented if there were sufficient demand for it.
Virtuoso 8+ commercial edition supports Magic Sets and Custom Inference Rules allowing custom inference rules to be created for most use case.
(Also asked and answered on the OpenLink Community Forum)
QUESTION
I think I still have a fundamental misunderstanding of OWL axioms :(.
Here is a small test ontology I created:
...ANSWER
Answered 2021-Apr-26 at 20:10OWL semantics is defined under open-world assumption, so you can't check if the cardinality for a certain property is exactly N, because there may be other property instances even if not declared.
More precisely, these are the checks that you can do:
Cardinality check Possible answers Sound Complete At-least N Yes (if N or more)I don't know (otherwise) Yes No Exactly N No (if N+1 or more)
I don't know (otherwise) Yes No At-most N No (if N+1 or more)
I don't know (otherwise) Yes No Solution
You can check if a cardinality is exactly 1 only if you explicitly state that "value1"
is the only value for :Ind1
. In this case :Ind1
will be part of :Class1
.
In FOL:
∀x.(R(Ind1, x) → x = "value1")
In DL:
∃R⁻.{Ind1} ⊑ {"value1"}
In OWL2 (not tested):
QUESTION
I am using the OWL-API to load and owl ontology with SWRL rules.
I loaded an ontology with the following code:
...ANSWER
Answered 2021-Apr-27 at 15:15Running inferences over the model was the missing step. Therefore, I needed to use the InferredOntologyGenerator
class.
One line of code speaks more than a thousand words:
QUESTION
I can use this code to Create the restricted data range :
...ANSWER
Answered 2021-Jan-20 at 07:26The screenshot appears to show 8.4.3 Literal Value Restriction, see also OWL2 Quick Guide, Data Property Restrictions. Programmatically this looks like following:
QUESTION
I am trying to convert a Matlab code to Python and mostly everything is quite simple to change. But I got stuck with this part when there appeared a lot of colons in one place. This is the original Matlab code:
...ANSWER
Answered 2020-Nov-27 at 17:55The syntax a : b : c
creates a sequence from a to c (inclusive if possible) using steps of b. Wrapping this further in brackets has no effect in this case, since a sequence is already a matrix (i.e. it is true that a:b:c
is equivalent to [a:b:c]
). Therefore
QUESTION
I am using protege5-5 and the reasoner HermiT 1.4 3.456.
I have a class Animal
containing 2 subclasses Animal1
and Animal2
. I have a property eats
and a property isEatenBy
which is defined as the inverse of eats
. When I add in the description of Animal1
that it's subclass of eats some(Animal2)
, I expect the reasoner to add in the description of Animal2
that it's a subclass of isEatenBy Animal1
but it doesn't.
Any idea what should I do to make that happen or if what I am expecting is not supposed to happen anyway ?
...ANSWER
Answered 2020-Nov-05 at 14:33I think there are 3 issues here.
(1) Stating Animal1 SubClassOf eats some Animal2
merely states that there is a subset of individuals of the Animal1
set that eats
at least 1 individual that belongs to the set of Animal2
. At most you can infer that some individuals of Animal2
are eaten by Animal1
. That is that isEatenBy some Animal1 SubClassOf Animal2
. In (3) I will explain why you do not get this inference.
Most importantly it cannot infer that all individuals of Animal2
are eaten by Animal1
, which is what is needed to infer Animal2 SubClassOf isEatenBy some Animal1
.
(2) Inverse roles make claims about individuals. Hence, when you have a statement about specific individuals like eats(animal1, animal2)
where animal1
and animal2
are individuals, the reasoner will infer that animal2 isEatenBy animal1
.
(3) A class like isEatenBy some Animal1
is sometimes referred to as an anonymous class while classes like Animal
, Animal1
and Animal2
are referred to as named classes. Because in general the number of inferences that can be made from a set of axioms is infinite, reasoners restrict their inferences to named classes.
As an example, for your eats
property you can define the domain as Animal1
and the range as Animal2
. This means that whenever you have eats(x, y)
, individuals x
will be inferred to be of type Animal1
and individual y
will be inferred to be of type Animal2
.
To now also get an inference that is the equivalent is isEatenBy some Animal1 SubClassOf Animal2
, you need to introduce a new class, say AnimalsThatAreEatenByAnimal1
that is equivalent to isEatenBy some Animal1
. The reasoner will now infer that AnimalsThatAreEatenByAnimal1
is a subclass of Animal2
.
In general, to understand the inferences that a reasoner can make, it crucial to understand the semantics of the axioms you define. For this you can look at the direct semantics. For an introduction on the logic, see An Introduction to Description Logics.
QUESTION
I am quite new in protege. I have been able to run some of the examples like pizza.owl
or travel.owl
. I then opened an ontology that someone else created and when I run the HermiT reasoner I get the following error:
ANSWER
Answered 2020-Oct-27 at 11:59From
QUESTION
I’m trying to use a Hermite curve in a project, with an admittedly limited understanding of how the math actually works, and I’ve run into some behavior I don’t understand. I've demonstrated my confusion with a minimal code sample below, but basically I would expect points along a subcurve of a hermite curve (i.e. a subcurve defined using points and tangents on the original curve) to fit the original curve, but this seems to be false.
The following c# code defines a Hermite curve class that provides functions for computing the position and the tangent of a point at some ratio along the curve. I copy/pasted the math for both functions from other places on the internet.
A small test harness then performs the test that I would expect to succeed, but doesn’t. It is unclear to me if there is a bug in my code, a mistake in my math, or if I misunderstand something about how Hermite curves work and this test actually should not pass.
Any insight is appreciated.
...ANSWER
Answered 2020-Oct-05 at 09:33you're using pointer equality instead of object equality?
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