citrus | :rainbow: 低代码快速开发脚手架，灵活、高效，降低开发成本 | Authentication library

Even if you make it fixed it would still cover other content of the page. I would have helped you if the content to the right wouldn't create a problem for your users. Instead, have a add to cart button appear at the bottom when the user scrolls down.

Since you are using JQUERY, you can check out this tutorial on how to detect when the user scrolls down the page https://www.geeksforgeeks.org/how-to-detect-when-user-scrolls-to-the-bottom-of-a-div/ and then show your footer pannel. I'll attach a preview of what I am suggesting.

This should appear fixed on the bottom of your window only on scroll.

I also have a pure javascript method to track when a scroll happens, you may also want to try that out. How to detect if browser window is scrolled to bottom?

You are using modules.

Every module has its own scope. So, the object candle1 is only available inside the module it was declared in, not globally.
Thus, the console.log in the js file works since it's in the same scope, but doesn't work on dev tools because that is the global scope.

ES6 has these kinds of scopes (top to bottom):

• Global scope
• Module scope
• Function scope
• Block scope

If you want to access something globally, you can create a global object.
Example: window.candle1 = candle1;

It seems to me that all you need is this:

A self join can help, the second condition is implemented in the join condition. Then the n-grams are created by combining the arrays of the two sides. When combining the arrays the element that is common in both arrays is omitted:

Use:

You can use aggregate and array_intersect, along with collect_set to compute the intersection on list_of_fruits and collected_tokens to obtain intersection_list_of_fruits and intersection_collected_tokens.

However, since intersection_most_common_word needs to account for the count of the words. To do this,

1. Find the intersections of words excluding counts
2. Iterate over the intersection words and the collect arrays in most_common_word and find the minimum count

You need to cast it.

Should be quicker than copy-paste:

There may be a better way but let me explain my process.

1. First I splitted individually and sorted descending no of elements. This was done so the first element has the highest no of levels which I'm later going to use to decide the no of levels.
2. Then I ran reduce on sorted array. In the first If statement I'm initializing the levels in the accumulator object. That if statement will be accessed only for the first element.
   After that I'm pushing subarrays to individual arrays based on the level

Well in this specific example sorting is not even necessary since it is already sorted.