cbc | Cb is simplified C
kandi X-RAY | cbc Summary
kandi X-RAY | cbc Summary
Cb (C flat) compiler. Cb is simplified C.
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Top functions reviewed by kandi - BETA
- Handles a suffix operation
- Translates a cast node
- Visits a FOR node
- Adds a pointer to the pointer list
- Visits a member
- Visits a label node
- Visits an expression node
- Visit a range of nodes
- Translate an assign node
- Emit an assignment node
- Visit a CondExpression node
- Visits a switch node
- Visits a While node
- Visit a binary operation
- Visit a doWhile node
- Visits an IF node
- Visits a logical AND node
- Visits a logical or statement
- Creates a FUNCTION node
- Transforms a block node
- Visits an ExprStmtNode
- Visits a UnaryOpNode
- Handles an assignment
- Visits a return node
- Visits a conditional expression
- Visits a FUNCTION node
- Makes sure this is an integer assignable
- Visits a binary operator node
- Compile a unary unary operator
- Implements the visitor to visit an array node
- Visits a DereferenceNode
cbc Key Features
cbc Examples and Code Snippets
Community Discussions
Trending Discussions on cbc
QUESTION
Based on the example provided here on how to establish a shared secret and derived key between JS (Crypto-JS) and Python, I can end up with the same shared secret and derived key on both ends.
However, when I try to encrypt as below, I cannot find a way to properly decrypt from Python. My understanding is that probably I am messing with the padding or salts and hashes.
...ANSWER
Answered 2022-Mar-28 at 11:29The issue is that the key is not passed correctly in the CryptoJS code.
The posted Python code generates LefjQ2pEXmiy/nNZvEJ43i8hJuaAnzbA1Cbn1hOuAgA=
as Base64-encoded key. This must be imported in the CryptoJS code using the Base64 encoder:
QUESTION
we are currently working with a cloud product that uses JSCH internally to connect to external sftp sources. Im investigating an connection reset exception that we are getting when trying to connect to azure sftp.
Using wireshark i determined that the problem occurs after we send the Client: Key Exchange Init. Establishing the same connection with filezilla we dont have this issue.
comparing the packages from jsch and filezilla i didn't see an obivious issue, but im not an expert on the ssh protocol. im gonna post both requests below if somebody could give me any pointers it would be greatly appreciated.
Request with JSCH (not working)
Request with Filezilla (working)
Response with Filezilla (working)
See below for the log output:
...ANSWER
Answered 2022-Feb-03 at 08:09i wanted to post a quick update for anybody that is having the same issue, i opened a similiar question on the microsoft q&a site and looks like it's an issue on the azure side that they are working on fixing for GA Microsoft Q&A
QUESTION
I have encrypted in flutter using dart library encrypt. Below is the code sample:
...ANSWER
Answered 2022-Feb-14 at 23:36The CryptoJS code is incomaptible because the IV is decoded incorrectly. Instead of the Hex encoder, the Utf8 encoder must be used.
Also, the encrypt library applies the CTR mode by default. Therefore, in the CryptoJS code the CTR mode must be used instead of the CBC mode:
QUESTION
I am using CryptoSwift 1.4.1, iOS 15.2, PyCryptodome 3.12.0, and XCode 13.2.1 to encrypt small string messages that I send to a Raspberry Pi Linux Device over BLE. It works when iOS encrypts the message and sends it to the Raspberry Pi. The Pi can successfully decrypt it. Now I want to do the inverse, encrypt a message on the Pi and have the iOS App read and decrypt it. This, however is not working and the decrypted value is the not the message I encrypted on the Pi.
Working iOS encryption:
...ANSWER
Answered 2022-Jan-28 at 10:30In the encrypt()
method the IV is not considered. As in aesEncrypt()
, the IV must be passed and used when creating the AES object.
Furthermore there are bugs in the encoding: The plaintext must be UTF8 encoded and the ciphertext must be hex encoded:
QUESTION
I'm trying to implement a function in Java to calculate the key check value for a 128 bit AES encryption key. The AES128CBCEncryptor class is implementing AES/128/CBC with ISO 9797-1 M2 padding.
The only information I can find on the key check value algorithm for AES says "the KCV for an AES key is computed by encrypting 16 bytes, each with value '01'.". It does not specify how the IV should be constructed.
Here is what I have thus far, but it's not generating the expected result:
...ANSWER
Answered 2022-Jan-13 at 16:47For a Key Check Value (KCV) one generally uses single block encryption, without any mode such as ECB or CBC. As only a constant value of 16 bytes is used, there is no need for padding either.
If you just have a CBC class that performs ISO 9797-1 M2 padding then you could encrypt the static value of 01010101010101010101010101010101
(hex encoding of 16 bytes), using an all-zero IV and taking the first 16 bytes from the result (removing 16 bytes of ciphertext at the end that is just encryption of the mandatory padding).
As you can see in the image below, because the IV is all zero, the XOR with the plaintext leaves the input intact, basically making the first ciphertext identical to direct encryption with the block cipher.
By WhiteTimberwolf (SVG version) - PNG version, Public Domain, https://commons.wikimedia.org/w/index.php?curid=26434096
However, as you are using Java, it makes more sense to use a Cipher
object using algorithm "AES/ECB/NoPadding"
and use that to encrypt the value of 01010101010101010101010101010101
directly. ECB doesn't take an IV, so that problem is avoided. Also, no padding needs to be considered when "NoPadding"
is specified.
If you need fewer bytes: those are usually taken from the left (lowest index) of the result.
Beware that these kinds of KCV's are somewhat dangerous as they show the ciphertext of one particular plaintext block. In the worst instances, this could lead to an adversary decrypting one ciphertext block, or for an authenticated scheme to lose its integrity/authentication properties.
Commonly KCV's are over an all-zero plaintext block. Using an all one-valued block makes the chance that this happens smaller, but that chance is still significant.
QUESTION
I have a Python 3 application running on CentOS Linux 7.7 executing SSH commands against remote hosts. It works properly but today I encountered an odd error executing a command against a "new" remote server (server based on RHEL 6.10):
encountered RSA key, expected OPENSSH key
Executing the same command from the system shell (using the same private key of course) works perfectly fine.
On the remote server I discovered in /var/log/secure
that when SSH connection and commands are issued from the source server with Python (using Paramiko) sshd complains about unsupported public key algorithm:
userauth_pubkey: unsupported public key algorithm: rsa-sha2-512
Note that target servers with higher RHEL/CentOS like 7.x don't encounter the issue.
It seems like Paramiko picks/offers the wrong algorithm when negotiating with the remote server when on the contrary SSH shell performs the negotiation properly in the context of this "old" target server. How to get the Python program to work as expected?
Python code
...ANSWER
Answered 2022-Jan-13 at 14:49Imo, it's a bug in Paramiko. It does not handle correctly absence of server-sig-algs
extension on the server side.
Try disabling rsa-sha2-*
on Paramiko side altogether:
QUESTION
How to convert the following Node's built-in crypto module encryption to CryptoJS?
...ANSWER
Answered 2022-Jan-10 at 21:43Both codes use the OpenSSL proprietary key derivation function EVP_BytesToKey()
with an iteration count of 1 and MD5 as digest.
NodeJS does not use a salt, while CryptoJS applies a random salt. For this reason, the NodeJS result is unchanged for each encryption, while the CryptoJS result always changes (assuming the same plaintext and passphrase).
Thus, to get the result of the NodeJS code with the CryptoJS code, you must not use a salt. However, by default, a salt is always applied. This can only be circumvented by explicitly determining key and IV with the key derivation function EvpKDF
and then using both in the encryption:
QUESTION
I'm using a string Encryption/Decryption class similar to the one provided here as a solution.
This worked well for me in .Net 5.
Now I wanted to update my project to .Net 6.
When using .Net 6, the decrypted string does get cut off a certain point depending on the length of the input string.
▶️ To make it easy to debug/reproduce my issue, I created a public repro Repository here.
- The encryption code is on purpose in a Standard 2.0 Project.
- Referencing this project are both a .Net 6 as well as a .Net 5 Console project.
Both are calling the encryption methods with the exact same input of "12345678901234567890"
with the path phrase of "nzv86ri4H2qYHqc&m6rL"
.
.Net 5 output: "12345678901234567890"
.Net 6 output: "1234567890123456"
The difference in length is 4
.
I also looked at the breaking changes for .Net 6, but could not find something which guided me to a solution.
I'm glad for any suggestions regarding my issue, thanks!
Encryption Class
...ANSWER
Answered 2021-Nov-10 at 10:25The reason is this breaking change:
DeflateStream, GZipStream, and CryptoStream diverged from typical Stream.Read and Stream.ReadAsync behavior in two ways:
They didn't complete the read operation until either the buffer passed to the read operation was completely filled or the end of the stream was reached.
And the new behaviour is:
Starting in .NET 6, when Stream.Read or Stream.ReadAsync is called on one of the affected stream types with a buffer of length N, the operation completes when:
At least one byte has been read from the stream, or The underlying stream they wrap returns 0 from a call to its read, indicating no more data is available.
In your case you are affected because of this code in Decrypt
method:
QUESTION
I want to encrypt a data with PHP. I before used from a javascript code to encrypt.
JavaScript Code:
...ANSWER
Answered 2021-Dec-15 at 07:54You must use aes-256-cbc
as algorithm in the PHP code, because the key is 32 bytes large.
Also you have to apply a zero vector as IV in the PHP code, which you can create with:
QUESTION
I'm trying to decrypt a string using phpseclib.
My hashed string is being generated from a javascript library called jsencrypt. The result of the encryption is saved in a database.
Afterwards I'm using phpseclib3 to try and decrypt the string using this:
...ANSWER
Answered 2021-Dec-08 at 04:49You need to use PKCS1 padding. eg.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install cbc
You can use cbc like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the cbc component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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