Serializability | Determines whether a schedule
kandi X-RAY | Serializability Summary
kandi X-RAY | Serializability Summary
I developed this brute force algorithm during my masters studies. It's a great aid to quickly determine whether a schedule is serializable and draw a precendence graph.
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Top functions reviewed by kandi - BETA
- Entry point for testing purposes
- Getter for item
- Test if the given schedule contains the conflict with the given transaction
- Gets the conflict object
- Returns the transaction id of the operation
- Gets the toOperation property
- Returns the action of this action
- Get precedence graph
- Get the full schedule
- Returns a string describing the conflict serializable solution
- Compares two OperationConflict objects
- Compares this operation
- Populate the action schedule
- Append an operation to the queue
- Creates a hash code for this operation
- Returns a hashcode of this transaction
- Returns the item at the given index
- Returns a string representation of this Operation
Serializability Key Features
Serializability Examples and Code Snippets
Community Discussions
Trending Discussions on Serializability
QUESTION
I am new to DDD and I am strugling with the concept of aggregate routes and it's implementation in ASP .NET Core.
Basicaly, I have two aggregate routes (AR):
- User
- Group
Where there can be a group with multiple users and each of it's user can belong to many different groups.
If I correctly understand it, the rule relationships aggregate routes are following:
- aggregate route should be serializable (no circle relationship)
- aggregate route must not have navigation property pointing to another aggregate route
The fact, that one AR should not have navigation property to another means, that I have to connect them in some kind of different way, for example with ValueObject.
ValueObject:UserToGroup (can't have navigation properties cause of serializability)
- GUID UserId
- GUID GroupId
AR User:
- GUID Id
- ICOLLECTION< UserToGroup > Groups
AR Group
- GUID Id
- ICOLLECTION< UserToGroup > Users
With this setup I managed to get everything according to the rules. But one unexplained question arises. How do I query for all Users from a Group?? I could for example do this (with LINQ): var ids = group.Users.Select(g => g.UserId) var usersFromGroup = userRepository.FetchByIds(ids)
But this seems kind of stupid, I felling like I am basically killing one of the EF best features, navigation properties...
Any suggestions how to implement this in some kind of better way??
Thank you so much for your response.
Bruno
...ANSWER
Answered 2022-Jan-31 at 05:01My recommendation would be to never query the domain model.
There may be a few instances where the complete data you need in a query would be available/surfaced in a particular instance of a domain object (aggregate root). But this more-often-than-not is not the case.
Queries should be a specific concern and be as close to the data store as possible. Typically the data is either returned in some low-level data structure such as a DataRow
or perhaps a read model (data transfer object). A domain object should never cross a wire (well, that's my take on it).
For querying I would use an implementation of an ISomethingQuery
where my domain interaction would be through the ISomethingRepository
. In this way you can stay away from navigation properties and oddities such as "lazy-loading". You can be specific with the data you need.
The above structure usually leads to a situation where an ORM doesn't necessarily add much value but YMMV.
QUESTION
Looking at the implementation for Stream#toList
, I just noticed how overcomplicated and suboptimal it seemed.
Like mentioned in the javadoc just above, this default
implementation is not used by most Stream
implementation, however, it could have been otherwise in my opinion.
ANSWER
Answered 2021-Apr-04 at 21:49The toArray
method might be implemented to return an array that is then mutated afterwards, which would effectively make the returned list not immutable. That's why an explicit copy by creating a new ArrayList
is done.
It's essentially a defensive copy.
This was also discussed during the review of this API, where Stuart Marks writes:
As written it's true that the default implementation does perform apparently redundant copies, but we can't be assured that toArray() actually returns a freshly created array. Thus, we wrap it using Arrays.asList and then copy it using the ArrayList constructor. This is unfortunate but necessary to avoid situations where someone could hold a reference to the internal array of a List, allowing modification of a List that's supposed to be unmodifiable.
QUESTION
As the heading mentions, the ArrayList and its iterator not working. Not able to figure why. The ArrayList should expect Employees and it is getting it. Then why the iterator is not giving proper objects?Any help?
Code:
...ANSWER
Answered 2021-Jan-25 at 16:54Change
QUESTION
I've been reading about the read-only lock-free transactions as implemented in Google Spanner and CockroachDB. Both claim to be implemented in a lock-free manner by making use of system clocks. Before getting to the question, here is my understanding (please skip the following section if you are aware of the machineries in both systems or just in CockroachDB):
- Spanner's approach is simpler -- before committing a write transaction, Spanner picks the max timestamp across all involved shards as the commit timestamp, adds a wait, called commit wait, to for the max clock error before returning from it's write transaction. This means that all causally dependent transactions (both reads and writes) will have a timestamp value higher than the commit timestamp of the previous write. For read transactions, we pick the latest timestamp on the serving node. For example, if there was a write committed at timestamp 5, and the max clock error was 2, future writes and reads-only transactions will at least have a timestamp of 7.
- CockroachDB on the other hand, does something more complicated. On writes, it picks the highest timestamp among all the involved shards, but does not wait. On reads, it assigns a preliminary read timestamp as the current timestamp on the serving node, then proceeds optimistically by reading across all shards and restarting the read transaction if any key on any shard reports a write timestamp that might imply uncertainty about whether the write causally preceeded the read transaction. It assumes that keys with write timestamps less than the timestamp for the read transaction either appeared before the read transaction or were concurrent with it. The uncertainty machinery kicks in on timestamps higher than the read transaction timestamp. For example, if there was a write committed at timestamp 8, and a read transaction was assigned timestamp 7, we are unsure about whether that write came before the read or after, so we restart the read transaction with a read timestamp of 8.
Relevant sources - https://www.cockroachlabs.com/blog/living-without-atomic-clocks/ and https://static.googleusercontent.com/media/research.google.com/en//archive/spanner-osdi2012.pdf
Given this implementation does CockroachDB guarantee that the following two transactions will not see a violation of serializability?
- A user blocks another user, then posts a message that they don't want the blocked user to see as one write transaction.
- The blocked user loads their friends list and their posts as one read transaction.
As an example, consider that the friends list and posts lived on different shards. And the following ordering happens (assuming a max clock error of 2)
- The initial posts and friends list was committed at timestamp 5.
- A read transaction starts at timestamp 7, it reads the friends list, which it sees as being committed at timestamp 5.
- Then the write transaction for blocking the friend and making a post gets committed at 6.
- The read transaction reads the posts, which it sees as being committed at timestamp 6.
Now, the transactions violate serializability becasue the read transaction saw an old write and a newer write in the same transaction.
What am I missing?
...ANSWER
Answered 2020-Oct-20 at 18:53CockroachDB handles this with a mechanism called the timestamp cache (which is an unfortunate name; it's not much of a cache).
In this example, at step two when the transaction reads the friends list at timestamp 7, the shard that holds the friends list remembers that it has served a read for this data at t=7 (the timestamp requested by the reading transaction, not the last-modified timestamp of the data that exists) and it can no longer allow any writes to commit with lower timestamps.
Then in step three, when the writing transaction attempts to write and commit at t=6, this conflict is detected and the writing transaction's timestamp gets pushed to t=8 or higher. Then that transaction must refresh its reads to see if it can commit as-is at t=8. If not, an error may be returned and the transaction must be retried from the beginning.
In step four, the reading transaction completes, seeing a consistent snapshot of the data as it existed at t=7, while both parts of the writing transaction are "in the future" at t=8.
QUESTION
I am trying to implement a class that enables the user to manipulate N input Streams without having constraints on Types of input Streams.
For starter, I wanted to transform all input DataStreams into keyedStreams. So, I mapped the input dataStream into a Tuple and after that, I applied KeyBy to convert it into keystream.
I always get a problem of serialization, I tried to follow this guide https://ci.apache.org/projects/flink/flink-docs-stable/dev/java_lambdas.html and it didn't work.
What I do like to know is :
- What is Serialization/Deserialization in Java ? and what is used for.
- What are the problems that I can counter in Flink with Serialization
- What is the problem in my code( you may find below the code and the error message)
Thank you very much.
Main Class:
...ANSWER
Answered 2020-Apr-10 at 05:51Flink is a distributed framework. That means, your program is potentially going to run on a thousands of nodes. This also means that each worker node has to receive code to be executed along with the required context. Simplifying a bit, both events flowing through the system and functions to be executed have to be serializable - as they are transfer via the wire. This is why serialization is important in distributed programming in general.
In short, serialization is a process of encoding data into byte representation that can be transferred and restored on another node (another JVM).
Back to the problem. Here is your cause:
QUESTION
I am having an issue like
Cannot add property X, object is not extensible
after updating my angular project to angular 9 with Ngrx update as well. When I rollback Ngrxversion to 8 it's working fine. But I need to update that as well to v9 with angular 9 updates. This has happened when I add this as datasource.data in the material table with additional attribute. I think that additional attribute alteration is a reason for that. But I create new array from what we got and tried out like below by using slice.
...ANSWER
Answered 2020-Mar-27 at 12:46You should deep-clone myDataArray
because it's coming out from the store through a selector. Keeping the immutability of the data in the store is an important part of redux pattern and you'd be changing the data directly in the store if you modify myDataArray
(depending on your selector, it could be the same data => a reference to the array in the store).
You can do myDataArray = JSON.parse(JSON.stringify(myDataArray))
before trying to make any change in it.
There are more efficient ways of deep-cloning an object, for example using fast-copy.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install Serializability
You can use Serializability like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the Serializability component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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