initializer | Android App 初始化任务执行框架 | Job Scheduling library

 by   cheie Java Version: v1.3.1 License: MIT

kandi X-RAY | initializer Summary

kandi X-RAY | initializer Summary

initializer is a Java library typically used in Data Processing, Job Scheduling applications. initializer has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has high support. You can download it from GitHub.

A framework for initialize task of Android componentization.
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            kandi-support Support

              initializer has a highly active ecosystem.
              It has 21 star(s) with 3 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              initializer has no issues reported. There are no pull requests.
              OutlinedDot
              It has a negative sentiment in the developer community.
              The latest version of initializer is v1.3.1

            kandi-Quality Quality

              initializer has 0 bugs and 0 code smells.

            kandi-Security Security

              initializer has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              initializer code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              initializer is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              initializer releases are available to install and integrate.
              Build file is available. You can build the component from source.
              Installation instructions, examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed initializer and discovered the below as its top functions. This is intended to give you an instant insight into initializer implemented functionality, and help decide if they suit your requirements.
            • Sets the executor
            • Adds a dependency on this task
            • Sets executor
            • Set the delay in milliseconds
            • Sets the delay
            • Adds a dependency on this task
            • Sets executor
            • Set the delay in milliseconds
            • Initializes the initializer
            • Build the task graph
            • Executes this task
            • Recursively traverses all nodes in the tree starting with the given node
            • Method to wait until it has failed
            • Synchronously waits for a thread to finish
            • Wait for a period of milliseconds
            • Include a sleep period
            • Start task
            • Gets the name
            • Compares this TaskNode with the specified name
            • Wait for a period of time
            • Determines the module
            • Executes a command
            • Creates and returns the text view
            • Create a new module activity
            • Returns the hashCode of this name
            • Configure executors
            • Creates the text view
            • Compares this delay with another delay
            Get all kandi verified functions for this library.

            initializer Key Features

            No Key Features are available at this moment for initializer.

            initializer Examples and Code Snippets

            No Code Snippets are available at this moment for initializer.

            Community Discussions

            QUESTION

            Entity Framework | Sequence contains more than one matching element
            Asked 2022-Mar-31 at 09:23

            I used the database first approach. The model is right (or at least it looks like) But I always get this error. Please, I've already tried so many things.. The full code of my program (and even sql script by which I create my database) is here: https://github.com/AntonioParroni/test-task-for-backend-stack/blob/main/Server/Models/ApplicationContext.cs

            Since I have a mac. I created my model with dotnet ef cli commands (dbcontext scaffold) I can use my context. But I can't touch any DbSet..

            ...

            ANSWER

            Answered 2022-Mar-31 at 09:23

            You have net6.0 target framework which is still not released while you have installed EF6 which is a previous iteration Entity Framework (mainly used with legacy .NET Framework projects) and you also have EF Core (a modern iteration of it) but older version - 5.0 (which you are actually using for your context, see the using Microsoft.EntityFrameworkCore; statements there).

            Try removing EntityFramework package and installing preview version of Microsoft.EntityFrameworkCore.SqlServer (possibly just updating to the latest 5 version also can help) and either removing completely or installing preview version of Microsoft.EntityFrameworkCore.Design. (Also I would recommend to update your SDK to rc and install rc versions of packages).

            Or try removing the reference to EntityFramework (not Core one) and changing target framework to net5.0 (if you have it installed on your machine).

            As for why do you see this exception - I would guess it is related to new methods added to Queryable in .NET 6 which made one of this checks to fail.

            TL;DR

            As mentioned in the comments - update EF Core to the corresponding latest version (worked for 5.0 and 3.1) or update to .NET 6.0 and EF Core 6.

            Source https://stackoverflow.com/questions/69236321

            QUESTION

            The deduction guide for std::array
            Asked 2022-Mar-22 at 14:07

            In the C++ 17 and C++ 20 Working Drafts of the C++ Standard the deduction guide for the class template std::array is defined the following way

            ...

            ANSWER

            Answered 2022-Mar-22 at 13:59

            C++17 has that requirement in the deduction guide.

            Source https://stackoverflow.com/questions/71573199

            QUESTION

            Introduced intermediate variable in structured binding definition?
            Asked 2022-Mar-19 at 13:13

            In [dcl.struct.bind] 9.6.4, there is definition of structured binding when initializer is a class type with std​::​tuple_­size​::​value properly defined:

            ... variables are introduced with unique names ri as follows:
            S Ui ri = initializer ;
            Each vi is the name of an lvalue of type Ti that refers to the object bound to ri; the referenced type is Ti.

            My question is why is it necessary to introduce ri, can't we define the identifier vi directly as reference to the result of get(e)?

            ...

            ANSWER

            Answered 2022-Mar-19 at 11:43

            The intent is to disallow redeclaring structured bindings as references. See CWG 2313.

            Source https://stackoverflow.com/questions/71535696

            QUESTION

            visit_Psych_Nodes_Alias: Unknown alias: default (Psych::BadAlias)
            Asked 2022-Mar-19 at 10:21

            I updated from ruby 2.7.1 to 3.1.1, then removed Gemfile.lock and ran bundle update (it's on a dev branch, so I can throw it away if this is a bad idea, I just wanted to see if it would work).

            bundle update succeeds, but when I start the server:

            ...

            ANSWER

            Answered 2022-Mar-19 at 10:21

            The problem is related to the Ruby 3.1 / Psych 4.x incompatibility described in this issue: https://bugs.ruby-lang.org/issues/17866

            Ruby 3.0 comes with Psych 3, while Ruby 3.1 comes with Psych 4, which has a major breaking change (diff 3.3.2 → 4.0.0).

            • The new YAML loading methods (Psych 4) do not load aliases unless they get the aliases: true argument.
            • The old YAML loading methods (Psych 3) do not support the aliases keyword.

            At this point, it seems like anyone, anywhere that wants to load YAML in the same way it worked prior to Ruby 3.1, need to do something like this:

            Source https://stackoverflow.com/questions/71191685

            QUESTION

            Is use in an unused default member initializer still an odr-use?
            Asked 2022-Mar-13 at 00:25

            Is use in a default member initializer still an odr-use, even if the default member initializer is not used by any constructor?

            For example, is this program ill-formed because g is odr-used and therefore its definition implicitly instantiated?

            ...

            ANSWER

            Answered 2022-Mar-13 at 00:25

            QUESTION

            Why constinit of half-initialized struct does not work
            Asked 2022-Feb-21 at 02:52
            struct A1 { int x;     int y; };
            struct A2 { int x = 1; int y = 2; };
            struct A3 { int x = 1; int y; };
            
            constinit A1 a1; // x == 0, y == 0.
            constinit A2 a2; // x == 1, y == 2.
                      A3 a3; // x == 1, y == 0.
            constinit A3 a4; // Error: illegal initialization of 'constinit' entity with a non-constant expression
            
            int main() {}
            
            ...

            ANSWER

            Answered 2022-Feb-21 at 02:52

            I think this is a case where we might be missing some wording.

            To start with, there are three stages of initialization that happen ([basic.start.static]):

            1. Constant initialization
            2. If not that, zero-initialization (for static storage duration variables, like the ones in this question)
            3. If necessary, dynamic initialization

            (1) and (2) together are static initialization, (3) is... well, dynamic. And what constinit does is ensure that there is no dynamic iniitialization, from [dcl.constinit]:

            If a variable declared with the constinit specifier has dynamic initialization ([basic.start.dynamic]), the program is ill-formed.

            And the rule for constant initialization is, from [expr.const]:

            A variable or temporary object o is constant-initialized if

            • either it has an initializer or its default-initialization results in some initialization being performed, and
            • the full-expression of its initialization is a constant expression when interpreted as a constant-expression, except that if o is an object, that full-expression may also invoke constexpr constructors for o and its subobjects even if those objects are of non-literal class types.

            With that said, let's go through the three types. Starting with the easiest:

            Source https://stackoverflow.com/questions/71194939

            QUESTION

            Overload resolution between two constructors from std::initializer_list
            Asked 2022-Feb-12 at 23:30

            In following program, struct C has two constructors : one from std::initializer_list and the other from std::initializer_list. Then an object of the struct is created with C{{1}}:

            ...

            ANSWER

            Answered 2022-Feb-12 at 23:30

            The wording could be clearer (which is unsurprising), but GCC and MSVC are correct here: the relevant rule ([over.ics.list]/7) checks only that

            overload resolution […] chooses a single best constructor […] to perform the initialization of an object of type X from the argument initializer list

            so the fact that the initialization of B from {1} would be ill-formed is irrelevant.

            There are several such places where implicit conversion sequences are more liberal than actual initialization, causing certain cases to be ambiguous even though some of the possibilities wouldn’t actually work. If the programmer was confused and thought one of those near misses was actually a better match, it’s a feature that the ambiguity is reported.

            Source https://stackoverflow.com/questions/71095274

            QUESTION

            C++ Copy Constructors: must I spell out all member variables in the initializer list?
            Asked 2022-Jan-30 at 04:18

            I have some pretty complicated objects. They contain member variables of other objects. I understand the beauty of copy constructors cascading such that the default copy constructor can often work. But, the situation that may most often break the default copy constructor (the object contains some member variables which are pointers to its other member variables) still applies to a lot of what I've built. Here's an example of one of my objects, its constructor, and the copy constructor I've written:

            ...

            ANSWER

            Answered 2022-Jan-30 at 02:54

            C++ Copy Constructors: must I spell out all member variables in the initializer list?

            Yes, if you write a user defined copy constructor, then you must write an initialiser for every sub object - unless you wish to default initialise them, in which case you don't need any initialiser - or if you can use a default member initialiser.

            the object contains some member variables which are pointers to its other member variables)

            This is a design that should be avoided when possible. Not only does this force you to define custom copy and move assignment operators and constructors, but it is often unnecessarily inefficient.

            But, in case that is necessary for some reason - or custom special member functions are needed for any other reason - you can achieve clean code by combining the normally copying parts into a separate dummy class. That way the the user defined constructor has only one sub object to initialise.

            Like this:

            Source https://stackoverflow.com/questions/70911220

            QUESTION

            @EnableAutoConfiguration(exclude =...) on tests failed in Spring Boot 2.6.0
            Asked 2022-Jan-15 at 03:04

            I tried to upgrade my data-mongo example project to Spring Boot 2.6.0. There is a test designed to run against Testcontainers, I also included the embedded mongo dep for other tests, so I have to exclude the AutoConfiguration for embedded mongo to make sure this test working on Docker/testcontainers.

            The following configuration worked well with Spring Boot 2.5.6.

            ...

            ANSWER

            Answered 2021-Nov-20 at 17:20

            As of Spring Boot 2.6, the property spring.mongodb.embedded.version must be set to use the auto-configured embedded MongoDB. It's mentioned in the release notes: https://github.com/spring-projects/spring-boot/wiki/Spring-Boot-2.6-Release-Notes#embedded-mongo

            This is also what the error message you posted, advises to do: Set the spring.mongodb.embedd ed.version property or define your own MongodConfig bean to use embedded MongoDB

            The annotation @DataMongoTest is meta-annotated with @ImportAutoConfiguration and @AutoConfigureDataMongo, and is designed to trigger auto-configuration of MongoDB unless explicitly disabled as you do in the working configuration examples.

            In your first configuration example, the annotation @EnableAutoConfiguration(exclude = EmbeddedMongoAutoConfiguration.class) does not override this effect of @DataMongoTest.

            With Spring Boot 2.5.6, the auto-configured MongodConfig bean is most likely also part of the application context but not effectively used. But this depends on the rest of the code and in particular on the MongodbContainerInitializer.

            Source https://stackoverflow.com/questions/70047380

            QUESTION

            Union's default constructor is implicitly deleted
            Asked 2021-Dec-20 at 22:48

            The following code:

            ...

            ANSWER

            Answered 2021-Dec-20 at 22:26

            It's all slightly mysterious. gcc behaves the same as clang.

            The standard has this to say (emphasis mine):

            Absent default member initializers, if any non-static data member of a union has a non-trivial default constructor, copy constructor, move constructor, copy assignment operator, move assignment operator, or destructor, the corresponding member function of the union must be user-provided or it will be implicitly deleted for the union.

            But I think the wording is a bit wooly here. I think what they actually mean is that you must provide an initialiser for the member that has (in your example) a non-trivial constructor, like so:

            Source https://stackoverflow.com/questions/70428563

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install initializer

            You can download it from GitHub.
            You can use initializer like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the initializer component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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