initializer | Android App 初始化任务执行框架 | Job Scheduling library
kandi X-RAY | initializer Summary
kandi X-RAY | initializer Summary
A framework for initialize task of Android componentization.
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Top functions reviewed by kandi - BETA
- Sets the executor
- Adds a dependency on this task
- Sets executor
- Set the delay in milliseconds
- Sets the delay
- Adds a dependency on this task
- Sets executor
- Set the delay in milliseconds
- Initializes the initializer
- Build the task graph
- Executes this task
- Recursively traverses all nodes in the tree starting with the given node
- Method to wait until it has failed
- Synchronously waits for a thread to finish
- Wait for a period of milliseconds
- Include a sleep period
- Start task
- Gets the name
- Compares this TaskNode with the specified name
- Wait for a period of time
- Determines the module
- Executes a command
- Creates and returns the text view
- Create a new module activity
- Returns the hashCode of this name
- Configure executors
- Creates the text view
- Compares this delay with another delay
initializer Key Features
initializer Examples and Code Snippets
Community Discussions
Trending Discussions on initializer
QUESTION
I used the database first approach. The model is right (or at least it looks like) But I always get this error. Please, I've already tried so many things.. The full code of my program (and even sql script by which I create my database) is here: https://github.com/AntonioParroni/test-task-for-backend-stack/blob/main/Server/Models/ApplicationContext.cs
Since I have a mac. I created my model with dotnet ef cli commands (dbcontext scaffold) I can use my context. But I can't touch any DbSet..
...ANSWER
Answered 2022-Mar-31 at 09:23You have net6.0
target framework which is still not released while you have installed EF6 which is a previous iteration Entity Framework (mainly used with legacy .NET Framework projects) and you also have EF Core (a modern iteration of it) but older version - 5.0 (which you are actually using for your context, see the using Microsoft.EntityFrameworkCore;
statements there).
Try removing EntityFramework
package and installing preview version of Microsoft.EntityFrameworkCore.SqlServer
(possibly just updating to the latest 5 version also can help) and either removing completely or installing preview version of Microsoft.EntityFrameworkCore.Design
. (Also I would recommend to update your SDK to rc and install rc versions of packages).
Or try removing the reference to EntityFramework
(not Core one) and changing target framework to net5.0
(if you have it installed on your machine).
As for why do you see this exception - I would guess it is related to new methods added to Queryable
in .NET 6 which made one of this checks to fail.
TL;DR
As mentioned in the comments - update EF Core to the corresponding latest version (worked for 5.0 and 3.1) or update to .NET 6.0 and EF Core 6.
QUESTION
In the C++ 17 and C++ 20 Working Drafts of the C++ Standard the deduction guide for the class template std::array
is defined the following way
ANSWER
Answered 2022-Mar-22 at 13:59C++17 has that requirement in the deduction guide.
QUESTION
In [dcl.struct.bind] 9.6.4, there is definition of structured binding when initializer is a class type with std::tuple_size::value
properly defined:
... variables are introduced with unique names ri as follows:
S Ui ri = initializer ;
Each vi is the name of an lvalue of type Ti that refers to the object bound to ri; the referenced type is Ti.
My question is why is it necessary to introduce ri, can't we define the identifier vi directly as reference to the result of get(e)
?
ANSWER
Answered 2022-Mar-19 at 11:43The intent is to disallow redeclaring structured bindings as references. See CWG 2313.
QUESTION
I updated from ruby 2.7.1 to 3.1.1, then removed Gemfile.lock and ran bundle update
(it's on a dev branch, so I can throw it away if this is a bad idea, I just wanted to see if it would work).
bundle update
succeeds, but when I start the server:
ANSWER
Answered 2022-Mar-19 at 10:21The problem is related to the Ruby 3.1 / Psych 4.x incompatibility described in this issue: https://bugs.ruby-lang.org/issues/17866
Ruby 3.0 comes with Psych 3, while Ruby 3.1 comes with Psych 4, which has a major breaking change (diff 3.3.2 → 4.0.0).
- The new YAML loading methods (Psych 4) do not load aliases unless they get the
aliases: true
argument. - The old YAML loading methods (Psych 3) do not support the
aliases
keyword.
At this point, it seems like anyone, anywhere that wants to load YAML in the same way it worked prior to Ruby 3.1, need to do something like this:
QUESTION
Is use in a default member initializer still an odr-use, even if the default member initializer is not used by any constructor?
For example, is this program ill-formed because g
is odr-used and therefore its definition implicitly instantiated?
ANSWER
Answered 2022-Mar-13 at 00:25As stated in the comments, g
is odr-used. However, there is a definition for it available, so there is no non-diagnosable violation here; MSVC is wrong to accept it. (This is true even without the constructor declaration; the implicitly declared B::B()
is never defined, but the default member initializer is still an odr-use like it is here.)
QUESTION
struct A1 { int x; int y; };
struct A2 { int x = 1; int y = 2; };
struct A3 { int x = 1; int y; };
constinit A1 a1; // x == 0, y == 0.
constinit A2 a2; // x == 1, y == 2.
A3 a3; // x == 1, y == 0.
constinit A3 a4; // Error: illegal initialization of 'constinit' entity with a non-constant expression
int main() {}
...ANSWER
Answered 2022-Feb-21 at 02:52I think this is a case where we might be missing some wording.
To start with, there are three stages of initialization that happen ([basic.start.static]):
- Constant initialization
- If not that, zero-initialization (for static storage duration variables, like the ones in this question)
- If necessary, dynamic initialization
(1) and (2) together are static initialization, (3) is... well, dynamic. And what constinit
does is ensure that there is no dynamic iniitialization, from [dcl.constinit]:
If a variable declared with the
constinit
specifier has dynamic initialization ([basic.start.dynamic]), the program is ill-formed.
And the rule for constant initialization is, from [expr.const]:
A variable or temporary object
o
is constant-initialized if
- either it has an initializer or its default-initialization results in some initialization being performed, and
- the full-expression of its initialization is a constant expression when interpreted as a constant-expression, except that if
o
is an object, that full-expression may also invoke constexpr constructors foro
and its subobjects even if those objects are of non-literal class types.
With that said, let's go through the three types. Starting with the easiest:
QUESTION
In following program, struct C
has two constructors : one from std::initializer_list
and the other from std::initializer_list
. Then an object of the struct is created with C{{1}}
:
ANSWER
Answered 2022-Feb-12 at 23:30The wording could be clearer (which is unsurprising), but GCC and MSVC are correct here: the relevant rule ([over.ics.list]/7) checks only that
overload resolution […] chooses a single best constructor […] to perform the initialization of an object of type
X
from the argument initializer list
so the fact that the initialization of B
from {1}
would be ill-formed is irrelevant.
There are several such places where implicit conversion sequences are more liberal than actual initialization, causing certain cases to be ambiguous even though some of the possibilities wouldn’t actually work. If the programmer was confused and thought one of those near misses was actually a better match, it’s a feature that the ambiguity is reported.
QUESTION
I have some pretty complicated objects. They contain member variables of other objects. I understand the beauty of copy constructors cascading such that the default copy constructor can often work. But, the situation that may most often break the default copy constructor (the object contains some member variables which are pointers to its other member variables) still applies to a lot of what I've built. Here's an example of one of my objects, its constructor, and the copy constructor I've written:
...ANSWER
Answered 2022-Jan-30 at 02:54C++ Copy Constructors: must I spell out all member variables in the initializer list?
Yes, if you write a user defined copy constructor, then you must write an initialiser for every sub object - unless you wish to default initialise them, in which case you don't need any initialiser - or if you can use a default member initialiser.
the object contains some member variables which are pointers to its other member variables)
This is a design that should be avoided when possible. Not only does this force you to define custom copy and move assignment operators and constructors, but it is often unnecessarily inefficient.
But, in case that is necessary for some reason - or custom special member functions are needed for any other reason - you can achieve clean code by combining the normally copying parts into a separate dummy class. That way the the user defined constructor has only one sub object to initialise.
Like this:
QUESTION
I tried to upgrade my data-mongo example project to Spring Boot 2.6.0. There is a test designed to run against Testcontainers, I also included the embedded mongo dep for other tests, so I have to exclude the AutoConfiguration for embedded mongo to make sure this test working on Docker/testcontainers.
The following configuration worked well with Spring Boot 2.5.6.
...ANSWER
Answered 2021-Nov-20 at 17:20As of Spring Boot 2.6, the property spring.mongodb.embedded.version
must be set to use the auto-configured embedded MongoDB. It's mentioned in the release notes: https://github.com/spring-projects/spring-boot/wiki/Spring-Boot-2.6-Release-Notes#embedded-mongo
This is also what the error message you posted, advises to do: Set the spring.mongodb.embedd ed.version property or define your own MongodConfig bean to use embedded MongoDB
The annotation @DataMongoTest
is meta-annotated with @ImportAutoConfiguration
and @AutoConfigureDataMongo
, and is designed to trigger auto-configuration of MongoDB unless explicitly disabled as you do in the working configuration examples.
In your first configuration example, the annotation @EnableAutoConfiguration(exclude = EmbeddedMongoAutoConfiguration.class)
does not override this effect of @DataMongoTest
.
With Spring Boot 2.5.6, the auto-configured MongodConfig
bean is most likely also part of the application context but not effectively used. But this depends on the rest of the code and in particular on the MongodbContainerInitializer
.
QUESTION
The following code:
...ANSWER
Answered 2021-Dec-20 at 22:26It's all slightly mysterious. gcc behaves the same as clang.
The standard has this to say (emphasis mine):
Absent default member initializers, if any non-static data member of a union has a non-trivial default constructor, copy constructor, move constructor, copy assignment operator, move assignment operator, or destructor, the corresponding member function of the union must be user-provided or it will be implicitly deleted for the union.
But I think the wording is a bit wooly here. I think what they actually mean is that you must provide an initialiser for the member that has (in your example) a non-trivial constructor, like so:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install initializer
You can use initializer like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the initializer component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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