jEN | the java client for The Echo Nest API

 by   echonest Java Version: Current License: No License

kandi X-RAY | jEN Summary

kandi X-RAY | jEN Summary

jEN is a Java library. jEN has no bugs, it has no vulnerabilities and it has low support. However jEN build file is not available. You can download it from GitHub.

jEN is an open source Java library for the Echo Nest API. With jEN you have Java access to the entire set of API methods including:. artist - search for artists by name, description, or attribute, and get back detailed information about any artist including audio, similar artists, blogs, familiarity, hotttnesss, news, reviews, urls and video. song - search songs by artist, title, description, or attribute (tempo, duration, etc) and get detailed information back about each song, such as hotttnesss, audio summary, or tracks. track - upload a track to the Echo Nest and receive summary information about the track including key, duration, mode, tempo, time signature along with detailed track info including timbre, pitch, rhythm and loudness information. playlists - create personalized playlists based on a wide range of parameters. taste profiles - provide for personalized recommendation and playlisting. This is a Java client API and assorted tools and helpers for the Echo Nest API (at developer.echonest.com). This client works with Version 4 of the Echo Nest API.
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            kandi-support Support

              jEN has a low active ecosystem.
              It has 68 star(s) with 46 fork(s). There are 16 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 8 open issues and 3 have been closed. There are 4 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of jEN is current.

            kandi-Quality Quality

              jEN has 0 bugs and 0 code smells.

            kandi-Security Security

              jEN has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              jEN code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              jEN does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              jEN releases are not available. You will need to build from source code and install.
              jEN has no build file. You will be need to create the build yourself to build the component from source.
              Installation instructions, examples and code snippets are available.
              It has 13329 lines of code, 1140 functions and 75 files.
              It has high code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed jEN and discovered the below as its top functions. This is intended to give you an instant insight into jEN implemented functionality, and help decide if they suit your requirements.
            • Demonstrates how to use ECHO queries
            • Reads items from the catalog
            • Check an artist
            • List all song catalogs
            • Add standard commands
            • Dumps the commands in the interpreter
            • Gets a command by its ID
            • Load the contents of a file
            • Performs binary copy
            • Returns a list of catalogs that are similar to the Spotify catalog
            • Include all categories
            • Returns a string representation of the options
            • Demonstrates how to show a Spotify demo
            • Shows all the properties of the object
            • Entry point to the Echo News
            • Gets a track for the given idspace
            • Main method
            • Creates a general catalog
            • Get overall statistics
            • Normalize search string
            • Gets the track data for the given idSpace or creates a new one if it does not exist
            • Displays all available data
            • Collapses the genre to a collection
            • Starts a live playlist
            • Lists all available general catalogs
            • Show a single track
            Get all kandi verified functions for this library.

            jEN Key Features

            No Key Features are available at this moment for jEN.

            jEN Examples and Code Snippets

            No Code Snippets are available at this moment for jEN.

            Community Discussions

            QUESTION

            Why doesnt the index plus one on the first click of the Iconbutton
            Asked 2022-Apr-16 at 17:20

            So i have made a calendar. I am now trying to make two arrow buttons jump through the months. The only problem is that everytime i click the Iconbutton the ++ doesnt do anything the first time but does something on the second... why is this can someone please help

            ...

            ANSWER

            Answered 2022-Apr-16 at 15:10

            One problem is that i++ passes the current i value to the calculation before increasing, so you pass the same old value to onEvent. You can find more details in this answer - it's about C, but inc/dec operators work the same in all languages they exists. You could've used ++i, which will increase the value before using it in the calculations.

            But here comes the second problem. This line:

            Source https://stackoverflow.com/questions/71894649

            QUESTION

            Join operations in SQL
            Asked 2022-Apr-02 at 11:28

            I should retrieve the IDs and names of ingredients that are not contained by any ice cream and then sort the output rows in ascending order by ingredient ID. I don't quite understand how JOIN -operation works in this exercise.

            I tried e.g. the following but it gives too many rows in the output.

            ...

            ANSWER

            Answered 2022-Apr-02 at 10:17

            It appears you are asking to find where somethig does not exist, so it would make sense to express that using not exists

            So you just need to find the ingredients that don't exist in the list of contents:

            Source https://stackoverflow.com/questions/71716390

            QUESTION

            Non-anonymous named function to sort multidimensional object by SPECIFIED sub-key's value
            Asked 2022-Mar-28 at 18:55

            I have an object (not an array):

            ...

            ANSWER

            Answered 2022-Mar-28 at 18:55

            How about convert object to array to sort and convert back?

            Source https://stackoverflow.com/questions/71651854

            QUESTION

            Vectorizing a Function to Replicate Rows with Pandas
            Asked 2022-Mar-23 at 01:38

            CONTEXT:

            I have a DataFrame with a column and a function that duplicates a row based on the number in the column "count". My current method is very slow when working with larger datasets:

            ...

            ANSWER

            Answered 2022-Mar-23 at 01:38

            Try using pd.Index.repeat:

            Source https://stackoverflow.com/questions/71580813

            QUESTION

            Replace duplicate value with the value from another column on each row where a duplicate is located
            Asked 2022-Mar-01 at 19:21

            Say I have the following dataframe (Duplicate ID 1 and 3):

            ...

            ANSWER

            Answered 2022-Mar-01 at 19:16

            Just use pandas.DataFrame.duplicated, a method of your dataframe to locate which values are dupes in your "ID" column. Then use the same rows but take the value in "ALT_ID":

            Source https://stackoverflow.com/questions/71313520

            QUESTION

            Extract all links between ' and ' in a text file, using CLI (Linux)
            Asked 2022-Jan-30 at 15:53

            I have a very big text (.sql) file, and I want to get all the links out of it in a nice clean text file, where the link are all one in each line.

            I have found the following command grep -Eo "https?://\S+?\.html" filename.txt > newFile.txt from anubhava, which nearly works for me, link: Extract all URLs that start with http or https and end with html from text file

            Unfortunately, it does not quite work: Problem 1: In the above link, the webpages end with .html. Not so in my case. They do not have a common ending, so I just have to finish before the second ' symbol.

            Problem 2: I do not want it to copy the ' symbol.

            To give an example, (cause, I think I explain rather bad here):

            Say, my file says things like this:

            Not him old music think his found enjoy merry. Listening acuteness dependent at or an. 'https://I_want_this' Apartments thoroughly unsatiable terminated sex how themselves. She are ten hours wrong walls stand early. 'https://I_want_this_too'. Domestic perceive on an ladyship extended received do. Why jennings our whatever his learning gay perceive. Is against no he without subject. Bed connection unreserved preference partiality not unaffected. Years merit trees so think in hoped we as.

            I would want

            ...

            ANSWER

            Answered 2022-Jan-30 at 14:23

            You can use a GNU grep command like

            Source https://stackoverflow.com/questions/70915372

            QUESTION

            TypeError: Unhashable type: 'set'/'list'
            Asked 2022-Jan-12 at 08:18

            I am fairly new to programming and recently started working with dictionaries and a problem I am trying asks for me to create a list of names to take a poll. 2 names must not be in the dictionary while 2 more are in it. The code:

            ...

            ANSWER

            Answered 2022-Jan-12 at 08:18

            To check if element exists in some List you use in operator, elem in list

            Source https://stackoverflow.com/questions/70675032

            QUESTION

            How to handle Pandas columns where elements are Lists?
            Asked 2022-Jan-06 at 19:59

            I have loaded some JSON API data as a Pandas dataframe, as such, there are some columns that come out as lists. I also have some NaN values.

            First and foremost I want to replace the NaN with a single word such as 'empty' but the rest of the data are already in list forms. I want to ultimately create a new column that operates on this list structure and essentially turns it into a string since I will be using the strings to perform mapping logic later on.

            Here is some sample data and logic:

            ...

            ANSWER

            Answered 2022-Jan-06 at 19:58

            IIUC, you can get all the rows with NaN and fill them with ['empty'] which you can then pass through the eval function:

            Source https://stackoverflow.com/questions/70612835

            QUESTION

            "Duplicate" data from query with offset condition
            Asked 2021-Dec-27 at 11:45

            I'm working on Laravel Framework 8.73.2 project with mysql Ver 8.0.26-0ubuntu0.20.04.3 for Linux on x86_64 ((Ubuntu)).

            I'm getting wrong data from the database when using the offset condition. On the third data request I get unique data, but on the fourth data request I get repeated data

            third data request, offset = 20

            ...

            ANSWER

            Answered 2021-Dec-26 at 07:09

            Because the records are being sorted by their creation time, and there are multiple records that were created at the same time, “duplicates” can appear. The simplest option would be to include a second column to the sort:

            Source https://stackoverflow.com/questions/70484628

            QUESTION

            What does the following mean wrt. binary representations of signed types in C language?
            Asked 2021-Dec-16 at 00:01

            C allows three different sign representations:

            • Sign and magnitude

            • Ones’ complement

            • Two’s complement

            The first two nowadays probably only have historical or exotic relevance: for sign and magnitude, the magnitude is taken as positive values, and the sign bit simply specifies that there is a minus sign. Ones’ complement takes the corresponding positive value and complements all bits. Both representations have the disadvantage that two values evaluate to 0: there is a positive and a negative 0.

            Source: Modern C, Jens Gustedt

            Question: What's wrong with "two values evaluating to zero" according to the last statement (in bold)?

            ...

            ANSWER

            Answered 2021-Dec-15 at 11:11

            What's wrong with "two values evaluating to zero" according to the last statement (in bold)?

            Example: strings

            When char is signed, what is wrong with this code if integer encoding is not 2's complement?

            Source https://stackoverflow.com/questions/70362250

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install jEN

            Download the latest distribution
            Read the extensive Javadocs for jEN
            Browse the examples
            download the latest release
            unzip the archive
            add the jEN.jar file to your CLASSPATH
            get an API key from developer.echonest.com
            Browse the Javadocs included with the distribution
            Here's some sample code that shows how to get similar artists with the API:.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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