jsjs | JavaScript engine written in JavaScript on top of the Java | Interpreter library

 by   forax Java Version: Current License: GPL-2.0

kandi X-RAY | jsjs Summary

kandi X-RAY | jsjs Summary

jsjs is a Java library typically used in Utilities, Interpreter applications. jsjs has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. However jsjs build file is not available. You can download it from GitHub.

jsjs is a JavaScript compiler + engine written in JavaScript on top of the Java Virtual Machine.
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            kandi-support Support

              jsjs has a low active ecosystem.
              It has 8 star(s) with 0 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              jsjs has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of jsjs is current.

            kandi-Quality Quality

              jsjs has no bugs reported.

            kandi-Security Security

              jsjs has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              jsjs is licensed under the GPL-2.0 License. This license is Strong Copyleft.
              Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

            kandi-Reuse Reuse

              jsjs releases are not available. You will need to build from source code and install.
              jsjs has no build file. You will be need to create the build yourself to build the component from source.
              Installation instructions, examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed jsjs and discovered the below as its top functions. This is intended to give you an instant insight into jsjs implemented functionality, and help decide if they suit your requirements.
            • Create a Bsm_method for a given lookup
            • Returns the getter for the property key
            • Returns the getter method handle for prototype
            • Returns a getter method handle for the given key
            • Create a static call site for a single class
            • Defines a function handle
            • Creates a JSFunction for a function
            • Create a new function for a function
            • Get the value associated with the key
            • Returns the value for the given key
            • Populates a set of methods that match a given filter
            • Sets a prototype of the given object
            • Sets a hidden object
            • Create a CallSite for a given name
            • Creates a JSF function for the Java class
            • Create a call site with a lambda
            • Create a new call site with a lambda
            • Add two numbers
            Get all kandi verified functions for this library.

            jsjs Key Features

            No Key Features are available at this moment for jsjs.

            jsjs Examples and Code Snippets

            No Code Snippets are available at this moment for jsjs.

            Community Discussions

            QUESTION

            How to solve Cannot invoke "String.compareTo(String)" because "[]" is null?
            Asked 2021-Mar-24 at 02:27
            import java.util.Scanner;
            
            
            public class Search {
                static Scanner scanner = new Scanner(System.in);
                static Scanner kb = new Scanner(System.in);
                static Scanner kb2 = new Scanner(System.in);
                public static void main (String[] args)
                {
            
                    int choice;
                    System.out.print("Choose a number of students: ");
                    int n = scanner.nextInt();  
                    String name[] = new String[n+1];
                    String course[] = new String[n+1];
                    int ID[] = new int[n+1];
            
                    for(int i=1;i <= n; i++)
                    {
                        System.out.print("Enter ID number " + i + ": ");
                        ID[i] = scanner.nextInt();
                        System.out.print("Enter Student name " + i + ": ");
                        name[i] = kb.nextLine();
                        System.out.print("Enter Student course " + i + ": ");
                        course[i] = kb2.nextLine();
                        System.out.println("----------------------------------------");
                    }
            
                   
                  
                    do
                    {
                        choice = menu();
                        if(choice == 1)
                        {
                            sortID(ID);
                            printValues(ID);
            
                        }else if(choice == 2)
                        {
                            nameSort(name,n);
                            printName(name,n);
                        }else if(choice == 3)
                        {
            
                        }
                    }while(choice !=0);
                }
            
                public static int menu()
                {
                    System.out.print("\n1. Sort by ID\n2. Sort by Name\n3. Search by ID\n4. Search by Name\n5. Search by Course\n6. Display Records In table Form.\nYour Choice: ");
                    return scanner.nextInt();
                }
            
                public static void sortID(int []id)
                {
                    int temp;
                    int index, counter;
                    for (counter=0; counter < id.length -1; counter++) {
                        for (index=0; index < id.length - 1 - counter; index++) {
                            if (id[index] > id[index+1]) {
                                temp = id[index];
                                id[index]=id[index+1];
                                id[index+1]=temp;
                            }
                        }
                    }
                }
            
                public static void printValues (int[]array) {
                    
                    System.out.println ("\nSorted Id Number: ");
                    for(int i = 1; i < array.length; i++){
                        System.out.print ("\n" + array[i]);            
                    }
                        
                }
            
                public static void printName (String[]array,int a) {
                    
                    for (int i = 0; i <= a - 1; i++) 
                    {
                        System.out.print(array[i] + ", ");
                    }
                        
                }
            
               public static void nameSort(String[] name,int a)
                {
                    String temp;
                    for (int i = 0; i < a; i++) 
                    {
                        for (int j = i + 1; j < a; j++) { 
                            if  (name[i].compareTo(name[j])>0) 
                            {
                                temp = name[i];
                                name[i] = name[j];
                                name[j] = temp;
                            }
                        }
                    }
                }
            
            
            
            
            
            
            }
            
            ...

            ANSWER

            Answered 2021-Mar-24 at 02:27
            String name[] = new String[n+1];
            

            Source https://stackoverflow.com/questions/66773616

            QUESTION

            Regular Expression for a pattern
            Asked 2020-Jan-20 at 09:38

            I was looking for regular expression to find a string having a particular pattern (first occurrence )

            Consider this as my strings

            ...

            ANSWER

            Answered 2020-Jan-20 at 09:32

            You could take a positive look ahead for a colon and take the first element of the match.

            Source https://stackoverflow.com/questions/59820312

            QUESTION

            How do I select json from my table Postgres
            Asked 2018-Dec-08 at 05:14

            I have a table named loans with a lot of fields such as (id, name, description, etc.) And inside that table, I have a column which type is JSON(TermsMessage)(ARRAY OF JSON), and when I make a select query it returns me an error

            my query

            `

            ...

            ANSWER

            Answered 2018-Dec-08 at 05:14

            PostgreSQL doesn't have a built-in equality operator for the datatypes JSON or arrays of JSON. When grouping by a JSON field, the db needs to know which are the same values and can be grouped together. You can work around this by turning the JSON (or JSON arrays) into either text arrays or JSONb arrays using something like ::jsonb[] or ::text[]. I'd probably do in the innermost part of the query so that it flows through later naturally:

            Source https://stackoverflow.com/questions/53679567

            QUESTION

            MySQL, move data from rows to columns with Images pictures
            Asked 2018-Jun-06 at 09:32

            table1

            ...

            ANSWER

            Answered 2018-Jun-05 at 13:44

            You can do it with INSERT INTO ... SELECT statement:

            Source https://stackoverflow.com/questions/50701492

            QUESTION

            json file offline can read by chart.js, but online json can't read
            Asked 2017-Jul-12 at 08:41

            I have some problem with my chart.js, if i read offline json file, chart will be appear, but if I use online json from Firebase, it won't show anything, jsut white screen.

            I export json file from firebase, before I use it in online mode, but it won't show anything.

            this is my code, just one page.

            ...

            ANSWER

            Answered 2017-Jul-12 at 07:20

            Just remove window.onload = function() {} inside $.getJSON()

            Because window is already loaded before getting JSON

            Source https://stackoverflow.com/questions/45050731

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install jsjs

            First, you need a Java 8 compatible JDK, then you have to edit the line in the script run_build.js that define where the JDK is. then you can build it with the following command. The script will use the Nashorn JavaScript Engine to compile itselef (jsjs.js) to a .class file and then use this class to recompile itself, bootstraping itself.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

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          • HTTPS

            https://github.com/forax/jsjs.git

          • CLI

            gh repo clone forax/jsjs

          • sshUrl

            git@github.com:forax/jsjs.git

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