theta | Generic , modular and configurable formal verification

 by   ftsrg Java Version: v4.2.5 License: Apache-2.0

kandi X-RAY | theta Summary

kandi X-RAY | theta Summary

theta is a Java library. theta has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However theta build file is not available. You can download it from GitHub.

Theta can be divided into the following four layers. The table below shows the architecture and the projects. Each project contains a README.md in its root directory describing its purpose in more detail.
Support
    Quality
      Security
        License
          Reuse

            kandi-support Support

              theta has a low active ecosystem.
              It has 37 star(s) with 32 fork(s). There are 23 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 23 open issues and 66 have been closed. On average issues are closed in 99 days. There are 7 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of theta is v4.2.5

            kandi-Quality Quality

              theta has 0 bugs and 0 code smells.

            kandi-Security Security

              theta has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              theta code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              theta is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              theta releases are available to install and integrate.
              theta has no build file. You will be need to create the build yourself to build the component from source.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed theta and discovered the below as its top functions. This is intended to give you an instant insight into theta implemented functionality, and help decide if they suit your requirements.
            • Append the XCFa location
            • Makes sure that the given CQL is a CCF
            • Generate a XCFa location
            • Makes a CCFA statement
            • Overrides the visitor to create a XCFaLocation
            • Generate XCFa locations for a statement
            • Implements the visitor to visit a CDefault
            • Updates the XCF
            • Overrides the visitor to visit a Cwitch statement
            • Overrides the superclass method
            • Overrides the superclass of a CdoWhile
            • This method is called when a CFXa method is called
            • Generate a Cifa location for a given CIF statement
            • Updates the XCFa
            • Generate XCFa
            • Region > XCFa
            • Generate XCFaLocation
            • Visit a unary expression
            • Runs the XCFa procedure call
            • Refines a single argument
            • Returns the actual type
            • Gets the RDF constraints
            • If a RelationalExpression context is one of the other types is a RelationalExpression then the check is performed
            • Computes the set of active variables for the given action
            • Handles a bodyDeclaration
            • Gets the expression of the zone
            • Writes the given CFA to the given output stream
            • Refine a single argument
            • Visit a postfix expression
            • Performs the given trace
            • Perform basic sanity checks
            Get all kandi verified functions for this library.

            theta Key Features

            No Key Features are available at this moment for theta.

            theta Examples and Code Snippets

            Theta,Read more
            Javadot img1Lines of Code : 10dot img1License : Permissive (Apache-2.0)
            copy iconCopy
            @inproceedings{theta-fmcad2017,
                author     = {T\'oth, Tam\'as and Hajdu, \'{A}kos and V\"or\"os, Andr\'as and Micskei, Zolt\'an and Majzik, Istv\'an},
                year       = {2017},
                title      = {Theta: a Framework for Abstraction Refinement-Based   

            Community Discussions

            QUESTION

            Circular histogram with fitted Von Mises Distribution
            Asked 2021-Jun-13 at 15:13

            For the past days I've been trying to plot circular data with python, by constructing a circular histogram ranging from 0 to 2pi and fitting a Von Mises Distribution. What I really want to achieve is this:

            1. Directional data with fitted Von-Mises Distribution. This plot was constructed with Matplotlib, Scipy and Numpy and can be found at: http://jpktd.blogspot.com/2012/11/polar-histogram.html

            1. This plot was produced using R, but gives the idea of what I want to plot. It can be found here: https://www.zeileis.org/news/circtree/

            WHAT I HAVE DONE SO FAR:

            ...

            ANSWER

            Answered 2021-Apr-27 at 15:36

            This is what I achieved:

            I'm not entirely sure if you wanted x to range from [-pi,pi] or [0,2pi]. If you want the range [0,2pi] instead, just comment out the lines ax.set_xlim and ax.set_xticks.

            Source https://stackoverflow.com/questions/67282865

            QUESTION

            AttributeError: module 'scipy.ndimage' has no attribute 'interpolation' Tensorflow CNN
            Asked 2021-Jun-13 at 10:55

            This is a part of my code, before data augmentation, model.fit was working, however after augmentation of data i'm getting this error;

            AttributeError: module 'scipy.ndimage' has no attribute 'interpolation'

            This is the list of all imported libraries;

            ...

            ANSWER

            Answered 2021-Jun-13 at 10:55

            I found the problem. Problem was that scipy was missing in my anaconda virtual environment. I thought scipy was installed when I saw;

            AttributeError: module 'scipy.ndimage' has no attribute 'interpolation'

            Thanks for the tip @simpleApp. And I'm sorry to bother you with the mistake of absent-mindedness... Solution is the installing scipy.

            Source https://stackoverflow.com/questions/67953561

            QUESTION

            Animate a UIBezierPath hexagon like UIActivityIndicatorview
            Asked 2021-Jun-12 at 18:48

            I'm trying to achieve exactly the same animation shown below

            .

            and my output using UIBezierPath and CABasicAnimation is this below.

            Here is my LoaderView code

            ...

            ANSWER

            Answered 2021-Jun-03 at 13:46

            The problem is - the code is rendering the complete path - start-to-end each time and start is same for all animations.

            The idea for loaders is - start point has to change after each animation - something like -

            1. Start at angle 0
            2. Go up to angle 45 /// or 60 whatever you want this to be
            3. Change start angle to next logical step - say 30
            4. Then render up to 75 /// or 90 depending on what you chose previously

            In this arrangement, you have to keep drawing a certain portion of the shape by changing start point continuously.

            In practice, achieving a smooth transition between different start point values may prove out to be difficult than it seems. You can find an example here - https://github.com/SVProgressHUD/SVProgressHUD/blob/master/SVProgressHUD/SVIndefiniteAnimatedView.m#L48-L102

            UPDATE

            The link I shared above has all the hints in it. This library uses an image as a mask and then rotate that continuously. Mask shape can be anything you like - you already have code for that.

            You just need to create an image that's appropriate for your animation. See what their asset looks like

            and AFTER masking what their animation looks like -

            Source https://stackoverflow.com/questions/67819016

            QUESTION

            Theta problems with Logistic Regressions
            Asked 2021-Jun-12 at 04:41

            BRAND new to ML. Class project has us entering the code below. First I am getting warning:

            ...

            ANSWER

            Answered 2021-Jun-12 at 04:26

            You need to set self.theta to be an array, not a scalar (at least in this specific problem).

            In your case, (intercepted-augmented) X is a '3 by n' array, so try self.theta = [0, 0, 0] for example. This will correct the specific error 'bool' object has no attribute 'mean'. Still, this will just produce preds as a zero vector; you haven't fit the model yet.

            To let you know how I approached the error, I first went to the exact line the error message was pointing to, and put print(preds == y) before the line, and it printed out False. I guess what you expected was a vector of True and Falses. Your y seemed okay; it was a vector (a list to be specific). So I tried print(pred), which showed me a '3 by n' array, which is weird. Now going up from that line, I found out that pred comes from predict_prob(), especially np.dot(X, self.theta). Here, when X is a '3 by n' array and self.theta is a scalar, numpy seems to multiply the scalar to each item in the array and return the array (having the same dimension as the original array), instead of doing matrix multiplication! So you need to explicitly provide self.theta as an array (conforming to the dimension of X).

            Hope the answer and the reasoning behind it helped.

            As for the red line you mentioned in the comment, I guess it is also because you are not fitting the model. (To see the problem, put print(probs) before plt.countour(...). You'll see an array with 0.5 only.)

            So try putting model.fit(X, y) before preds = model.predict(X). (You'll also need to put self.verbose = verbose in the __init__().)

            After that, I get the following:

            Source https://stackoverflow.com/questions/67945325

            QUESTION

            Calculating polygon vertices with an angle produce the shape wrong size
            Asked 2021-Jun-11 at 18:10

            When i call my funtion with a startingAngle=0 it produce a good shape with the correct size. Example:

            ...

            ANSWER

            Answered 2021-Jun-09 at 21:00

            Your problem is one of mathematics. You said "As observed, the side length is 10px". It very definitely is not 10px. The distance from (10,5) to (5,0) is sqrt(5*5 + 5*5), which is 7.07. That's exactly what we expect for a square that is inscribed in a circle of radius 5: 5 x sqrt(2).

            And that's what the other squares are as well.

            FOLLOWUP

            As an added bonus, here is a function that returns the radius of the circle that circumscribes a regular polygon with N sides of length L:

            Source https://stackoverflow.com/questions/67881936

            QUESTION

            How to handle Datachange signal for circle diagram?
            Asked 2021-Jun-10 at 13:23

            I'm drawing circle diagram using my own inbuilt libraries. I'm able to draw circles using table data (x1,y1 & r) ,sharing code
            I'm using datachange signal with table, whenever enter any table item data then its creating no. of graph with circles. Is there other signal I can use or what change can make in code ? I want single graph with no. of circles(based on no. of entries in table).
            Also when circles are drawn lines coming like we draw without removing our pen to draw another circle how to overcome this ?

            • CHPlotGraph2D - this class to create graph

            • CHPlotCurveData- this Class hold the data points for the curves

            • CHPlotCurve-Class to draw the data as a line curve

              CHPlotCurveData* curvedata1 = new CHPlotCurveData();
              QAbstractItemModel* table1 = ui.tableView->model();
              for (int irows = 0, maxI = table1->rowCount(); irows < maxI; ++irows)
              {
              double x1 = table1->data(table1->index(irows, 1)).toDouble();
              double y1 = table1->data(table1->index(irows, 2)).toDouble();
              double r = table1->data(table1->index(irows, 6)).toDouble();
              for (double angle = 0; angle <= 360; angle++)
              {
              double theta = (angle * 180) / 3.14;
              double zx = x1 + r * cos(theta);
              double zy = y1 + r * sin(theta);
              QPointF pt(zx, zy);
              curvedata1->append((pt));
              }
              }
              CHPlotCurve* curve1 = (CHPlotCurve*)pGr->insertCurve("circle",
              CHPlotGraph2D::Line, false );
              curve1->setSamples(curvedata1);
              connect(ui.tableView->model(), &QAbstractItemModel::dataChanged,
              this, &tablemodel::drawCircle);

            ...

            ANSWER

            Answered 2021-Jun-10 at 13:23

            Thank you ..I have solved the problem .When anything changes in the table, I need to remove the existing curve containing all the circles and build/add a new one, or replace the data

            Source https://stackoverflow.com/questions/67901885

            QUESTION

            How can I avoid a loop if I need to do a matrix multiplication?
            Asked 2021-Jun-10 at 11:49

            I have the following code:

            ...

            ANSWER

            Answered 2021-Jun-10 at 00:41

            I believe this will work:

            Source https://stackoverflow.com/questions/67907491

            QUESTION

            Algorithm for finding new points of rotating a vector
            Asked 2021-Jun-10 at 11:38

            I am trying to programmatically find the point created from rotating a vector around it's origin point (could be anywhere in 2D space).

            We see that we have our line (or vector for the math) A at some point of (x, y) that might be anywhere in 2D space. It runs to point B at some (x, y). We rotate it by Theta which then moves to some point C at an (x, y). The problem for me comes with trying to programmatically use math to solve for such.

            Originally the thought was to form a triangle and use trig but this angle could be exactly 180 (unlikely but possible) which obviously no triangle can work. Would anyone have ideas?

            I am using C# and my own vector object (below) to test out the creation of lines. Any help is appreciated!

            ...

            ANSWER

            Answered 2021-Jun-09 at 16:24

            You can convert cartesian coordinates (x, y) into polar ones (R, fi), add theta to fi and then convert back to cartesian:

            Source https://stackoverflow.com/questions/67894033

            QUESTION

            Ggplot2 : do not display 0 value in pie chart labels
            Asked 2021-Jun-10 at 11:33

            I'm trying to make a pie chart without displaying the 0 value label and I'm unable to do it.

            My data :

            ...

            ANSWER

            Answered 2021-Jun-10 at 11:33

            You can replace your 0 values with NAs, for example with, dplyr::na_if(0) on your dataframe:

            Source https://stackoverflow.com/questions/67920114

            QUESTION

            Update number of observations in each simulation (using libraries: runjags, parallel)
            Asked 2021-Jun-09 at 07:31

            I am splitting my dataset by simulation ID and applying a runjags functions to each subsest simultaneously.

            Right now, each simulation contains 1000 observations. I know that sometimes the number of observations will differ since I will be dropping rows that meet certain criteria. I don't know how many observations will be dropped but I can calculate that by using groupobs <- fulldata %>% count(SimulID, sort=TRUE).

            Is there a way that I can change N=1000 during each simulation run. It would mean having to rewrite the tempModel.txt file with every simulation that is run.

            Thank you.

            ...

            ANSWER

            Answered 2021-Jun-09 at 07:31

            You have several options

            You could construct the model string on the fly. [The model argument to run.jags can contain a character string instead of a file name, so there's no need to write to a file and then read it in again.]

            You can add an element to your data list (x in your code) that contains the number of observations,

            Source https://stackoverflow.com/questions/67889756

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install theta

            You can download it from GitHub.
            You can use theta like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the theta component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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