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Just use Array.prototype.map():

Vue tries to render Tasks.vue file, but that file could not be found, because it probably does not exist. So just create ./components/Tasks.vue! :)

The generic split operation divides the data into several sets of data. See help(split).

The method split.ppp in the spatstat package divides a point pattern into a list of point patterns. For example if you had a point pattern X representing the locations of trees in a forest, with marks indicating the species of each tree, then split(X) would produce a list of point patterns, each containing the locations of trees of one species.

It seems that you did not want to split your point pattern as you had asked in the previous three questions. Rather, it seems that you probably wanted to produce a single point pattern with factor-valued marks, where the mark value identifies the grouping/classification. You've already done this in the previous question, by doing marks(X) <- factor(.....), so just plot that point pattern X.

With spatstat loaded and the ppp object saved as sf_owin (very counterintuitive name for a ppp object) you can simply overwrite the marks as:

This question is about the spatstat package.

The error message indicates that the split command is dispatched to split.ppp, so you could look up the help for split.ppp to figure out the problem.

The help file would tell you that the argument which.marks is ignored by split.ppp. So you can remove that argument.

To split the point pattern, you need a factor (a vector of categorical values which specify the grouping). The marks in the point pattern are not factors. (This is what the error message is saying.) According to your printed output, the column STATION_NA is character valued. If you want to split the pattern according to these values, you need to convert them to factor values. For example

Ok, here is one way to obtain what you want in about 2min. Some tickers are bad, that's why it crashes.

Here's the code. I use joblib for threading or multiprocess since it doesn't work in my env. But, that's the spirit.

The error message is pretty self-explanatory: the "Edge" in line 26 is undeclared, just as it sais:

graph->edge = Edge[E];

Edge is a type in your code, so Edge[E] does not really make sense. You would use the [] indexing operator on arrays, so that is definitely a problem there.

I guess I know what you wanted to do there, you wanted to create an array of Edge types. Try it like this:

graph->edge = (struct Edge*)malloc(E * sizeof(struct Edge));

Since you have a pointer in graph, you need to allocate the memory for that. But don't forget to delete it at the end.

free(graph->edge);

Or else you will get a memory leak.

You want to select one element every three elements starting from the second one i.e. index=1.

You can achieve this with the built-in list __getitem__: