word-checker | 🇨🇳🇬🇧Chinese and English word spelling corrector | Natural Language Processing library

 by   houbb Java Version: 1.1.0 License: Apache-2.0

kandi X-RAY | word-checker Summary

kandi X-RAY | word-checker Summary

word-checker is a Java library typically used in Artificial Intelligence, Natural Language Processing applications. word-checker has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can download it from GitHub, Maven.

🇨🇳🇬🇧Chinese and English word spelling corrector.
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            kandi-support Support

              word-checker has a low active ecosystem.
              It has 157 star(s) with 40 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 2 open issues and 5 have been closed. On average issues are closed in 195 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of word-checker is 1.1.0

            kandi-Quality Quality

              word-checker has 0 bugs and 0 code smells.

            kandi-Security Security

              word-checker has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              word-checker code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              word-checker is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              word-checker releases are not available. You will need to build from source code and install.
              Deployable package is available in Maven.
              Build file is available. You can build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              word-checker saves you 499 person hours of effort in developing the same functionality from scratch.
              It has 1640 lines of code, 177 functions and 50 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed word-checker and discovered the below as its top functions. This is intended to give you an instant insight into word-checker implemented functionality, and help decide if they suit your requirements.
            • Delete the candidate list
            • Build string
            • Build String set
            • Get edit result list
            • Checks whether the given word is correct
            • Checks if the specified text is correct
            • Se string
            • Static char segment
            • Checks whether the word is correct
            • Format a word
            • Formats a character
            • Gets the word collection
            • Segment the given string
            • Default implementation
            • Correct the word
            • Define English word data
            • Set word format
            • Correct word list
            • Put candidate
            • Format a character
            • Init word map
            • Set word data
            • Compares twoDtoDto objects
            • Set the word format
            • Correct word
            • Checks if the given word is correct
            Get all kandi verified functions for this library.

            word-checker Key Features

            No Key Features are available at this moment for word-checker.

            word-checker Examples and Code Snippets

            Chinese spelling correction,Return the best match result
            Javadot img1Lines of Code : 5dot img1License : Permissive (Apache-2.0)
            copy iconCopy
            final String right = "正确";
            final String error = "万变不离其中";
            
            Assert.assertEquals("正确", ZhWordCheckers.correct(right));
            Assert.assertEquals("万变不离其宗", ZhWordCheckers.correct(error));
              
            Chinese spelling correction,Is the spelling correct?
            Javadot img2Lines of Code : 5dot img2License : Permissive (Apache-2.0)
            copy iconCopy
            final String right = "正确";
            final String error = "万变不离其中";
            
            Assert.assertTrue(ZhWordCheckers.isCorrect(right));
            Assert.assertFalse(ZhWordCheckers.isCorrect(error));
              
            Quick start,maven introduction
            Javadot img3Lines of Code : 5dot img3License : Permissive (Apache-2.0)
            copy iconCopy
            
                 com.github.houbb
                 word-checker
                0.0.6
            
              

            Community Discussions

            QUESTION

            Why should "aaaaAAAAAA000000123456"take 5 steps and not 6
            Asked 2021-Dec-23 at 06:17

            I was doing this problem on leetcode: https://leetcode.com/problems/strong-password-checker/ and I came across an edge case where "aaaaAAAAAA000000123456" was expected to take 5 steps to become a good password, according to the somewhat vague description:

            deleting a character takes one step,
            adding a character takes one step,
            replacing a character takes one step.

            The max allowed number of characters is 20 in a "strong" password, and "aaaaAAAAAA000000123456" has 22 characters. Repeating 3s like "aaa" or "OOO" are considered insecure, so to make a password secure, you'd remove, replace or add a new char to one of the characters in the repeating 3s. You also have to make sure there are capital letters, small letters, and numbers in the password to be truly secure.

            According to my logic, "aaaaAAAAAA000000123456" or "aaa"+"a" +"AAA"+"AAA"+"000"+"000"+"123456" (noting the repeating 3s) should take 6 steps to become "secure", not 5:

            Step 1: the string is 22 characters, so remove a char from one repeating 3 making; "aa"+"a"+"AAA"+"AAA"+"000"+"000"+"123456"

            Step 2: it's now 21 chars, so remove another repeating 3 char; "aa"+"AAA"+"AAA"+"000"+"000"+"123456"

            Step 3: (now 20 chars) replace a repeating 3 char; "aa"+"A1A"+"AAA"+"000"+"000"+"123456"

            Step 4: replace another repeating 3 (I have to remove all of them); "aa"+"A1A"+"A2A"+"000"+"000"+"123456"

            Step 5: replace another repeating 3; "aa"+"A1A"+"A2A"+"030"+"000"+"123456"

            Step 6: remove the last repeating 3; "aa"+"A1A"+"A2A"+"030"+"040"+"123456"

            Why should this take 5 steps and not 6?

            I don't think it's necessary to add my code for this.

            ...

            ANSWER

            Answered 2021-Dec-23 at 00:16
            aaaaAAAAAA000000123456
            delete A
            delete 0
            aaaaAAAAA00000123456
            replace a
            replace A
            replace 0
            aazaAAzAA00z00123456
            

            Source https://stackoverflow.com/questions/70456271

            QUESTION

            Checking for a strong password fails for a case it shouldn't
            Asked 2021-Apr-19 at 09:20

            I am working through Leetcode problem 420. Strong Password Checker. This is the problem statement:

            A password is considered strong if the below conditions are all met:

            • It has at least 6 characters and at most 20 characters.
            • It contains at least one lowercase letter, at least one uppercase letter, and at least one digit.
            • It does not contain three repeating characters in a row (i.e., "...aaa..." is weak, but "...aa...a..." is strong, assuming other conditions are met).

            Given a string password, return the minimum number of steps required to make password strong. if password is already strong, return 0.

            In one step, you can:

            • Insert one character to password,
            • Delete one character from password, or
            • Replace one character of password with another character.
            Example 1: ...

            ANSWER

            Answered 2021-Apr-19 at 09:19

            It requires only one step which resolves two problems:

            Source https://stackoverflow.com/questions/67158503

            QUESTION

            Mark.js contenteditable - run Mark on input
            Asked 2021-Mar-27 at 20:24

            I'm am making a "word-checker" with a contenteditable div while using mark.js to highlingt certain words/word groups.

            The problem I am having is that I can't find a way to "run" Mark.js as the words are being typed (copy/pasted) in.

            I have tried to achieve this by adding an event listener to the textarea, but that throws an error: mark is not defined. textarea.addEventListener("input", mark); and by changing mark to instance textarea.addEventListener("input", instance); which gives me an error: TypeError: Property 'handleEvent' is not callable.. Here is the fiddle.

            I have also looked at various examples found on SO and on google, but I just can't seem to find what I'm looking for. The closest thing I found was this, but I still couldn't get it to work.

            Any help would be much appreciated. If I can provide any additional information, please let me know.

            ...

            ANSWER

            Answered 2021-Mar-27 at 20:24

            You can put all the instance.mark(...) calls to a separate function (e.g. markWords). You can then call that function when the input text changes:

            Source https://stackoverflow.com/questions/66835523

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install word-checker

            You can download it from GitHub, Maven.
            You can use word-checker like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the word-checker component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

            Support

            You can quickly determine whether the current word is spelled incorrectly. Can return the best match result. You can return to the corrected matching list, support specifying the size of the returned list. Error message support i18n. Support uppercase and lowercase, full-width and half-width formatting.
            Find more information at:

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          • HTTPS

            https://github.com/houbb/word-checker.git

          • CLI

            gh repo clone houbb/word-checker

          • sshUrl

            git@github.com:houbb/word-checker.git

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