RDFS | RDFS : an erasure code based cloud storage system | Cloud Storage library

 by   iVCE Java Version: Current License: Apache-2.0

kandi X-RAY | RDFS Summary

kandi X-RAY | RDFS Summary

RDFS is a Java library typically used in Storage, Cloud Storage, Amazon S3 applications. RDFS has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However RDFS build file is not available. You can download it from GitHub.

RDFS: an erasure code based cloud storage system.
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            kandi-support Support

              RDFS has a low active ecosystem.
              It has 36 star(s) with 7 fork(s). There are 15 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              RDFS has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of RDFS is current.

            kandi-Quality Quality

              RDFS has 0 bugs and 0 code smells.

            kandi-Security Security

              RDFS has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              RDFS code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              RDFS is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              RDFS releases are not available. You will need to build from source code and install.
              RDFS has no build file. You will be need to create the build yourself to build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              RDFS saves you 1658933 person hours of effort in developing the same functionality from scratch.
              It has 705253 lines of code, 30020 functions and 2583 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed RDFS and discovered the below as its top functions. This is intended to give you an instant insight into RDFS implemented functionality, and help decide if they suit your requirements.
            • Copy and configuration files from the jobtracker
            • Add block to block map .
            • Get the number of blocks for each file
            • Sets the properties for copy by chunk .
            • Retrieves the number of recent edits .
            • Initializes Hadoop logs .
            • Prints the available pools .
            • Process a datanode error .
            • Calculate the fairness for a given poolMetadataList .
            • Dumps the properties of a TFile to a PrintStream .
            Get all kandi verified functions for this library.

            RDFS Key Features

            No Key Features are available at this moment for RDFS.

            RDFS Examples and Code Snippets

            No Code Snippets are available at this moment for RDFS.

            Community Discussions

            QUESTION

            SPARQL Inference with SKOS
            Asked 2021-Jun-08 at 12:26

            We are trying to showcase inference with linked-data.

            The simple graph looks like the following in turtle-format:

            ...

            ANSWER

            Answered 2021-Jun-08 at 12:26

            To complete the question, I'm posting my comment above as an answer...

            To make it work, You need to define some meaning to your properties ex:isPartOf and ex:livesIn. Suggest to make ex:isPartOf transitive and then to define ex:livesIn as a property chain over ex:isPartOf, e.g.:

            Source https://stackoverflow.com/questions/67786448

            QUESTION

            How to write SPARQL query to fetch counts based on outer subject
            Asked 2021-Jun-01 at 17:10

            I am struggling to write a SPARQL query to fetch a list of products by the owner along with a count of other owners.

            following is the query i expect to get the result

            ...

            ANSWER

            Answered 2021-Jun-01 at 17:10

            SPARQL Query semantics specify how portions of the query are joined together. Your sub-query does not project any common variables that are shared with the outer query. It only SELECTs the ?allOwners variable which does not appear in the rest of the query.

            This means that you get a cross product of all the counts and all your other results; this is why you get duplicate rows and no correlations between the counts and rows.

            This kind of query can be achieved if you structure it correctly. Since you haven't provided example results you desire, I'm having to make a best guess of what you want. Something like the following may have the desired results:

            Source https://stackoverflow.com/questions/67757332

            QUESTION

            How to access the child elements of an element with minidom?
            Asked 2021-May-24 at 06:46

            I am reading an XML/OWL file (generated from Protege) in Jupyter notebook.

            I can read the root element, but for children its showing error/blank.

            ...

            ANSWER

            Answered 2021-May-24 at 06:46

            You have this structure

            Source https://stackoverflow.com/questions/67667051

            QUESTION

            Get highest level P131 for given place on Wikidata
            Asked 2021-May-18 at 07:59

            I have the following query:

            ...

            ANSWER

            Answered 2021-May-07 at 09:46

            This query seems to work quite well for me: Edited answer:

            Source https://stackoverflow.com/questions/67417266

            QUESTION

            Out of Memory Exception when trying to execute test for Apache Jena via MockMVC and Junit5
            Asked 2021-May-16 at 11:27

            I am running an Apache Jena Fuseki server als the SPARQL endpoint that I can connect to when using the application normally. Everything works and I get the output from the resulting query.

            But When I try to run my test with Springboot, Junit5 (I assume) and MockMVC it always get stuck on the following part:

            ...

            ANSWER

            Answered 2021-May-16 at 11:27

            The answer I found was that the heap size was constantly overflowing. Adding the line:

            Source https://stackoverflow.com/questions/67485559

            QUESTION

            SPARQL query on HM land registry site based on first part of postcode
            Asked 2021-May-08 at 16:18

            I'm trying to find out average house price data for a postcode area using the HM Land Registry open data SPARQL query via https://landregistry.data.gov.uk/app/qonsole, what the best way to do this if it's for a postcode sector (e.g. GL52)?

            The 'transactions in a postcode' example code given on there shows how to search a full postcode and I have attempted to alter the code using STRSTARTS() on the VALUES ? postcode section but it's coming back with an error..

            ...

            ANSWER

            Answered 2021-May-08 at 16:18

            Your syntax is wrong I'm afraid. For this type of query, you will need a filter, like:

            Source https://stackoverflow.com/questions/67449152

            QUESTION

            Aren't anonymous classes automatically a type of owl:Class?
            Asked 2021-May-08 at 15:32

            This ontology does not quite seem to do what I have in mind:

            ...

            ANSWER

            Answered 2021-May-08 at 15:32

            In your first snippet, it is clear that the intersection must be an OWL class because it is an intersection of OWL classes. Therefore, :CClass must also be an OWL class. However, this implies some reasoning based on how terms are defined. An OWL parser does not have to apply reasoning and should be directed explicitly to whether a term is an OWL class, an object property, a datatype property, an individual, an ontology, an annotation property, a datatype or some other kind of annotation. In the case of an owl:intersectionOf axiom, it is possible that you are declaring a datatype, rather than an OWL class. So it is only by looking at the content of the list, and finding how the terms inside are declared (viz., :AClass and :BClass), that you can eventually infer that they are all OWL classes, and therefore the intersection is an OWL class, and therefore it is equivalent to an OWL class, and therefore :CClass should or could appear as an OWL class in the editor. OWL tools are free to make this kind of inferences for the sake of robustness, but it is not mandated by the OWL standard.

            Edit for clarification: the standard defines a way to map RDF graphs to the abstract syntax of OWL where the constructs that use owl:intersectionOf can be mapped to either a class definition or a datatype definition. The only way the standard recommends to discriminate the two cases is by adding explicitly rdf:type owl:Class or rdf:type rdfs:Datatype (see Tables 12 and 13 of OWL 2 Web Ontology Language Mapping to RDF Graphs). OWL parsers may go beyond what the standard recommends and infer some types based on the context, but they do not have to do it. I know that the OWL API does some such syntactic inferences to avoid crashing on every invalid ontologies.

            Source https://stackoverflow.com/questions/67393325

            QUESTION

            Reasoning over OWL cardinality restriction
            Asked 2021-May-05 at 18:29

            I think I still have a fundamental misunderstanding of OWL axioms :(.

            Here is a small test ontology I created:

            ...

            ANSWER

            Answered 2021-Apr-26 at 20:10
            Premise

            OWL semantics is defined under open-world assumption, so you can't check if the cardinality for a certain property is exactly N, because there may be other property instances even if not declared.

            More precisely, these are the checks that you can do:

            Cardinality check Possible answers Sound Complete At-least N Yes (if N or more)
            I don't know (otherwise) Yes No Exactly N No (if N+1 or more)
            I don't know (otherwise) Yes No At-most N No (if N+1 or more)
            I don't know (otherwise) Yes No Solution

            You can check if a cardinality is exactly 1 only if you explicitly state that "value1" is the only value for :Ind1. In this case :Ind1 will be part of :Class1.

            In FOL:

            ∀x.(R(Ind1, x) → x = "value1")

            In DL:

            ∃R⁻.{Ind1} ⊑ {"value1"}

            In OWL2 (not tested):

            Source https://stackoverflow.com/questions/67270554

            QUESTION

            Get label only for items that exists on wikidata with php sparql
            Asked 2021-May-02 at 16:35

            I am working on a personal project using PHP and RDF4J Workbench Service and I have a repository with 3 contexts, one for robot categories, one for those robots that belongs to these categories and another one in which I store the owl:sameAs property to wikidata identifiers for the initial data.

            The problem is that a user can insert robots and the new inserted ones will not be linked to wikidata identifiers but instead will have unique URI's resulted by just removing the extra-space and concatenating the name that user had inserted. Now, when I query for the data I need, I want all these robots to be shown, but if my query is as it follows:

            ...

            ANSWER

            Answered 2021-May-02 at 16:35

            QUESTION

            Can't get actor names for a given film title when multiple films have the same name in DBpedia
            Asked 2021-Apr-28 at 19:30

            I am trying to get actor names for a given film title (I also have the release date in hand) with my sparql query, but given the situation that multiple films have the same name, I'm trying to differentiate them with the release date. Some films don't have the release date specified, some films don't have the label specified.

            I'm trying to get results when either the release date is specified and is matching, or when it is in the label of the film and is also matching. If I can't match the date with one of these attributes, I want no results in return

            Here is my current query:

            ...

            ANSWER

            Answered 2021-Apr-28 at 19:30

            I think you are misusing OPTIONAL here. Instead you should be looking at UNION. What's the difference?

            Source https://stackoverflow.com/questions/67305313

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install RDFS

            You can download it from GitHub.
            You can use RDFS like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the RDFS component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

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