DailyCodingProblem | I am using Java
kandi X-RAY | DailyCodingProblem Summary
kandi X-RAY | DailyCodingProblem Summary
Here is my approach for coding challenges at dailycodingproblem.com. I am using Java. Feel free to create a new issue thread for your questions or suggestions. The area of a circle is defined as πr2. Estimate π to 3 decimal places using a Monte Carlo method. Hint: The basic equation of a circle is x2 + y2 = r2. Given an integer k and a string s, find the length of the longest substring that contains at most k distinct characters. For example, given s = "abcba" and k = 2, the longest substring with k distinct characters is "bcb", so your function should return 3.
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Top functions reviewed by kandi - BETA
- Returns the number of univalued subtrees
- Get the unival tree count for a node
- Returns whether this node is a unival tree
- Generate a random value of a circle
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- Decodes number decoder
- Find the intersection of two lists
- Creates a clone
- Deserialize given string into nodes
- Gets the first word found in trie
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- Schedules a function to run in a thread
- Compares this node with the specified value
- Given a string representation of a file system returns an absolute path
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- Calculate the minimum number of times for a given interval
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QUESTION
I am very new to Python's regex module. I am trying to find the problem number and corresponding company name which asked the question. My text looks like this:
Text input:
...ANSWER
Answered 2020-May-20 at 20:41I assumed that the line with "asked by" is always after the problem number. For me it work with pattern.
QUESTION
This is a question from https://www.dailycodingproblem.com/:
Given a string, find the palindrome that can be made by inserting the fewest number of characters as possible anywhere in the word. If there is more than one palindrome of minimum length that can be made, return the lexicographically earliest one (the first one alphabetically).
For example, given the string "race", you should return "ecarace", since we can add three letters to it (which is the smallest amount to make a palindrome). There are seven other palindromes that can be made from "race" by adding three letters, but "ecarace" comes first alphabetically.
As another example, given the string "google", you should return "elgoogle".
It is similar to this SO question, or this GeeksforGeeks post. Similar, but not the same; none of them provide any explanation for the recurrence, as if they plucked the solution out of thin air, and they don't reconstruct the solution, let alone the lexicographically earliest one.
After some thinking, my understanding is as follows:
Observe that for any string
s[i..j], ifs[i] == s[j], then the number of insertions required to make it a palindrome is the same as the number of insertions required to makes[i+1..j-1]a palindrome.If, however,
s[i] != s[j], then we may converts[i..j-1]to a palindrome and then inserts[j]at the beginning, or converts[i+1..j]to a palindrome and inserts[i]at the end. Since we are looking for the fewest number of insertions, we will choose the minimum of the two options. The number of insertions is one more than the number of insertions required for the chosen subproblem (for adding a character at the beginning or at the end).
How do I reconstruct the lexicographically earliest solution?
...ANSWER
Answered 2019-Mar-15 at 09:31First, lets answer "how do I reconstruct the solution", then focus on ordering. Assuming you store the number of insertions in a 2D matrix insertions[start][stop], you just need to retrace your steps, "collecting" the characters inserted as you go. We'll need a new array to store out output string, of length equal to our starting string plus the minimal number of insertions. We'll also store two indices, pointing to the next available spots from the front and back into the array.
Start by comparing the first and last letters of the current substring, and if equal assign the output string both of those, in the next available positions from the front and back respectively. For example, if we have FYRF as our current substring, we'll assign our output string F..F, where . are undetermined characters. Our substring then becomes s[i+1..j-1] or YR.
If the two characters do not match, we'll compare our records in insertions[i+1][j] and insertions[i][j-1], to see which is smaller (at least one of them will be exactly one less than insertions[i][j]). If they're equal, just pick one (we'll return to this later). Assign the character in our output string which corresponds to the letter of the substring we duplicated / inserted, at the next available front and back indices into the output string. That is, in the case JLL, if we decide to add a J for JLLJ, we'd take the substring s[i+1..j], so we'd store J and J in our output string J..J. If our output string already contained AR....RA, we'd have stored ARJ..JRA instead. We repeat this entire process until all characters are assigned.
Now, to make it ordered lexicographically. Regarding the case in the previous paragraph where insertions[i+1][j] and insertions[i][j-1] are equal, we shouldn't pick one of them at random. Instead, we should compare s[i] and s[i+1] lexicographically, and if s[i] comes first, insert s[i] into the output string / proceed on insertions[i+1][j]. Otherwise, use s[i+1] / insertions[i][j-1]. This will give us the lexicographically soonest string from all available options.
QUESTION
In an attempt to improve my general problem solving skills, I recently subscribed to Daily Coding Problem. One of the challenges that came up has the following description:
This problem was asked by Uber.
Given an array of integers, return a new array such that each element at index i of the new array is the product of all the numbers in the original array except the one at i.
For example, if our input was [1, 2, 3, 4, 5], the expected output would be [120, 60, 40, 30, 24]. If our input was [3, 2, 1], the expected output would be [2, 3, 6].
Follow-up: what if you can't use division?
I solved this particular challenge within minutes using the following function:
...ANSWER
Answered 2018-Jul-29 at 20:42As @Steve alluded in the comments, you would:
first find the product of all the elements in the array:
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