heron | a little bit of automata theory

"One slot per core" is merely a rule of thumb. Nothing enforces this.

Each subtask (an instance of an operator chain) is single-threaded, but the slots within a task manager, and the task managers within a machine or container, will use all of the resources made available to them.

If you need division of this kind, you probably want to use (/) instead of div and Fractional instead of Integral. So:

char letters[8][20] = …; defines an array with automatic storage duration. Memory is reserved for it only during the function call. The statement return (str); returns a pointer to an element of this array, and then the memory is no longer reserved for the array. In C’s abstract model of computing, the array ceases to exist. In typical practice, the array is on the stack, but the printf call overwrites it.

You can fix this by defining the array with static storage duration, which reserves memory for it during all of program execution:

Is something like this what you are looking for? I just extracted out the hour and plotted that. Can do some more formatting from here.

Try this approach. Your first can use dplyr functions to count the number of species by each day and after that you can compute the cumulative sum by day using cum() with mutate(). The good thing is that you can integrate all the process in one pipeline with dplyr and ggplot2. Here the code using the data you provided:

You have a little syntax mistake in css.

As already pointed out by @Duck there are some minor issues in your code. Unfortunaetly these will not solve the ggtext issue

1. When you want to make use of ggtext you have to make use of element_markdown by setting e.g. axis.text.y = element_markdown() inside theme().

2. To make the styling work you have to escape the point . in your Comname by the HTML entity .. (The reason is that a number followed by a . marks the start of an ordered list in markdown.)

3. After these changes you don't need the scale_y_discrete. ggplot2 will by default use name to label the ticks

The problem is barcode scanners are standard keyboard inputs, but without sending that value to an input field, you won't get the entire string as you noticed. You can try my answer in regards to the zebra (the same issue) https://stackoverflow.com/a/54769272/3684265

Another option in keeping with your existing code, is DON'T alert instead APPEND to the barcode value on each keypress.

stop_words = set(stopwords.words('english')) and ... if word not in [stop_words]: you created a set with just one element - the list of stopwords. No word equals this whole list, therefore stopwords are not removed. So it must be:
stop_words = stopwords.words('english')
df['tokenized_text'].apply(lambda words: [word for word in words if word not in stop_words + list(string.punctuation)])

lemmatizer = WordNetLemmatizer here you assign the class but you need to create an object of this class: lemmatizer = WordNetLemmatizer()

You can't lemmatize a whole list in one take, instead you need to lemmatize word by word: df['tokenized_text'].apply(lambda words: [lemmatizer.lemmatize(word) for word in words])