puzzles | Raccolta personale di giochi ed enigmi matematici | Dependency Injection library
kandi X-RAY | puzzles Summary
kandi X-RAY | puzzles Summary
Raccolta personale di giochi ed enigmi matematici.
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Top functions reviewed by kandi - BETA
- Test dates
- Create a predicate to check for month day
- Checks if the given dates are unique within the month
- Create a predicate to check for month
- Entry point for testing
- Get the y value
- Gets the x coordinate
- Finds a board
- Main program for testing
- Checks if c is under pressure
- Computes the number of challenges that should be hit
- Generate a random number of iterations
- Returns the largest word length of n
- Converts an integer to a word
- Build a word based on the nth word
- Test program
- Returns a string representation of the grid
- Get the cell for given point
- Returns a string representation of the shape
- Returns a string representation of this coordinate
puzzles Key Features
puzzles Examples and Code Snippets
public class SwitchPuzzleRunner {
public static void main(String[] args) {
puzzleOne();
}
public static void puzzleOne() {
int number = 2;
switch(number) {
case 1:
System.out.println(1);
case 2:
System.out.print
jshell> interface InterfaceOne {
...> void methodOne();
...> }
| created interface InterfaceOne
jshell> interface InterfaceTwo extends InterfaceOne {
...> void methodTwo();
...> }
| created interface InterfaceT
class Planet {
void revolve() {
System.out.println("Revolve");
}
public static void main(String[] args) {
Planet earth = new Planet();
earth.revolve();
}
}
class Planet {
void revolve() {
System.out.println("Revolve")
Community Discussions
Trending Discussions on puzzles
QUESTION
There are a number of different ways, that make a type/class usable in a ranged for loop. An overview is for example given on cppreference:
range-expression
is evaluated to determine the sequence or range to iterate. Each element of the sequence, in turn, is dereferenced and is used to initialize the variable with the type and name given in range-declaration.
begin_expr
andend_expr
are defined as follows:
- If
range-expression
is an expression of array type, thenbegin_expr
is__range
andend_expr
is (__range
+__bound
), where__bound
is the number of elements in the array (if the array has unknown size or is of an incomplete type, the program is ill-formed)- If
range-expression
is an expression of a class typeC
that has both a member namedbegin
and a member namedend
(regardless of the type or accessibility of such member), thenbegin_expr
is__range.begin()
andend_expr
is__range.end()
- Otherwise,
begin_expr
isbegin(__range)
andend_expr
isend(__range)
, which are found via argument-dependent lookup (non-ADL lookup is not performed).
If I want to use a ranged for loop say in a function template, I want to constrain the type to be usable in a ranged for loop, to trigger a compiler error with a nice "constraint not satisfied" message. Consider the following example:
...ANSWER
Answered 2022-Apr-14 at 09:51It seems like what you need is std::ranges::range
which requires the expressions ranges::begin(t)
and ranges::end(t)
to be well-formed.
Where ranges::begin
is defined in [range.access.begin]:
The name
ranges::begin
denotes a customization point object. Given a subexpressionE
with typeT
, let t be an lvalue that denotes the reified object forE
. Then:
If
E
is an rvalue andenable_borrowed_range>
isfalse
,ranges::begin(E)
is ill-formed.Otherwise, if
T
is an array type andremove_all_extents_t
is an incomplete type,ranges::begin(E)
is ill-formed with no diagnostic required.Otherwise, if T is an array type,
ranges::begin(E)
is expression-equivalent tot + 0
.Otherwise, if
auto(t.begin())
is a valid expression whose type modelsinput_or_output_iterator
,ranges::begin(E)
is expression-equivalent toauto(t.begin())
.Otherwise, if
T
is a class or enumeration type andauto(begin(t))
is a valid expression whose type modelsinput_or_output_iterator
with overload resolution performed in a context in which unqualified lookup forbegin
finds only the declarations
QUESTION
Consider following examples for calculating sum of i32 array:
Example1: Simple for loop
...ANSWER
Answered 2022-Apr-09 at 09:13It appears you forgot to tell rustc it was allowed to use AVX2 instructions everywhere, so it couldn't inline those functions. Instead, you get a total disaster where only the wrapper functions are compiled as AVX2-using functions, or something like that.
Works fine for me with -O -C target-cpu=skylake-avx512
(https://godbolt.org/z/csY5or43T) so it can inline even the AVX512VL load you used, _mm256_load_epi32
1, and then optimize it into a memory source operand for vpaddd ymm0, ymm0, ymmword ptr [rdi + 4*rax]
(AVX2) inside a tight loop.
In GCC / clang, you get an error like "inlining failed in call to always_inline foobar
" in this case, instead of working but slow asm. (See this for details). This is something Rust should probably sort out before this is ready for prime time, either be like MSVC and actually inline the instruction into a function using the intrinsic, or refuse to compile like GCC/clang.
Footnote 1: See How to emulate _mm256_loadu_epi32 with gcc or clang? if you didn't mean to use AVX512.
With -O -C target-cpu=skylake
(just AVX2), it inlines everything else, including vpaddd ymm
, but still calls out to a function that copies 32 bytes from memory to memory with AVX vmovaps
. It requires AVX512VL to inline the intrinsic, but later in the optimization process it realizes that with no masking, it's just a 256-bit load it should do without a bloated AVX-512 instruction. It's kinda dumb that Intel even provided a no-masking version of _mm256_mask[z]_loadu_epi32
that requires AVX-512. Or dumb that gcc/clang/rustc consider it an AVX512 intrinsic.
QUESTION
Let us say that we would like to build a long (metal) chain which will be composed of smaller links, chained together. I know what the length of the chain should be: n. The links are represented as 2-tuples: (a, b). We may chain links together if and only if they share the same element at the side by which they would be chained.
I am given a list of lists of length n-1 - links
- which represents all links available to me at each position of the chain. For example:
ANSWER
Answered 2022-Apr-09 at 16:10Since counting is enough, let's just do that, and then it takes a split second for large cases as well.
QUESTION
In short I would like to be able to generate a dynamic Rmarkdown report file (pdf or html) from my shiny app with a button click. For this I thought I will use parameterized Report for Shiny. But somehow I can not transfer the single puzzles to the desired aim:
With this code we can generate and download a reactive radarchart in R Shiny:
...ANSWER
Answered 2022-Apr-02 at 19:22Basically your question already included all the building blocks. I only updated the report template to include the code to plot the radar chart. As a parameter I decided to pass the filtered dataset. In the server I only adjusted the specs for the params
:
QUESTION
Question in short
To have a proper input for pycosat, is there a way to speed up calculation from dnf to cnf, or to circumvent it altogether?
Question in detail
I have been watching this video from Raymond Hettinger about modern solvers. I downloaded the code, and implemented a solver for the game Towers in it. Below I share the code to do so.
Example Tower puzzle (solved):
...ANSWER
Answered 2022-Mar-19 at 22:23First, it's good to note the difference between equivalence and equisatisfiability. In general, converting an arbitrary boolean formula (say, something in DNF) to CNF can result in a exponential blow-up in size.
This blow-up is the issue with your from_dnf
approach: whenever you handle another product term, each of the literals in that product demands a new copy of the current cnf clause set (to which it will add itself in every clause). If you have n product terms of size k, the growth is O(k^n)
.
In your case n
is actually a function of k!
. What's kept as a product term is filtered to those satisfying the view constraint, but overall the runtime of your program is roughly in the region of O(k^f(k!))
. Even if f grows logarithmically, this is still O(k^(k lg k))
and not quite ideal!
Because you're asking "is this satisfiable?", you don't need an equivalent formula but merely an equisatisfiable one. This is some new formula that is satisfiable if and only if the original is, but which might not be satisfied by the same assignments.
For example, (a ∨ b)
and (a ∨ c) ∧ (¬b)
are each obviously satisfiable, so they are equisatisfiable. But setting b
true satisfies the first and falsifies the second, so they are not equivalent. Furthermore the first doesn't even have c
as a variable, again making it not equivalent to the second.
This relaxation is enough to replace this exponential blow-up with a linear-sized translation instead.
The critical idea is the use of extension variables. These are fresh variables (i.e., not already present in the formula) that allow us to abbreviate expressions, so we don't end up making multiple copies of them in the translation. Since the new variable is not present in the original, we'll no longer have an equivalent formula; but because the variable will be true if and only if the expression is, it will be equisatisfiable.
If we wanted to use x
as an abbreviation of y
, we'd state x ≡ y
. This is the same as x → y
and y → x
, which is the same as (¬x ∨ y) ∧ (¬y ∨ x)
, which is already in CNF.
Consider the abbreviation for a product term: x ≡ (a ∧ b)
. This is x → (a ∧ b)
and (a ∧ b) → x
, which works out to be three clauses: (¬x ∨ a) ∧ (¬x ∨ b) ∧ (¬a ∨ ¬b ∨ x)
. In general, abbreviating a product term of k literals with x
will produce k binary clauses expressing that x
implies each of them, and one (k+1)
-clause expressing that all together they imply x
. This is linear in k
.
To really see why this helps, try converting (a ∧ b ∧ c) ∨ (d ∧ e ∧ f) ∨ (g ∧ h ∧ i)
to an equivalent CNF with and without an extension variable for the first product term. Of course, we won't just stop with one term: if we abbreviate each term then the result is precisely a single CNF clause: (x ∨ y ∨ z)
where these each abbreviate a single product term. This is a lot smaller!
This approach can be used to turn any circuit into an equisatisfiable formula, linear in size and in CNF. This is called a Tseitin transformation. Your DNF formula is simply a circuit composed of a bunch of arbitrary fan-in AND gates, all feeding into a single arbitrary fan-in OR gate.
Best of all, although this formula is not equivalent due to additional variables, we can recover an assignment for the original formula by simply dropping the extension variables. It is sort of a 'best case' equisatisfiable formula, being a strict superset of the original.
To patch this into your code, I added:
QUESTION
I'm doing something kinda simple, but tidyeval always puzzles me. In this case, I have a function that plots something and I want to also save it afterwards using the name of the column I'm plotting, something like this:
...ANSWER
Answered 2022-Mar-15 at 18:23You can do this:
QUESTION
I stumbled upon a very bizarre struct member packing in 32-bit clang. Here is the link to the compiler explorer experiment.
In essence, I have the following structs:
...ANSWER
Answered 2022-Mar-01 at 06:00Here's my test program in Compiler Explorer using clang.
And here is the same program in OnlineGDB using gcc.
The
sizeof(_16Bytes)
is 16 as expected, howeveroffsetof(Test, test)
is 12 because the compiler decided to pack it right after_16Bytes::_4bytes
.
This actually makes perfect sense to me, based on standard packing rules, assuming that struct Test : _16Bytes
turns into the equivalent of this:
QUESTION
I am currently working on a project that regularly saves several java objects to a MongoDB database.
This object contains a Date
.
The conversion of java Date to Json Mongo give this:
...ANSWER
Answered 2022-Feb-03 at 20:07You need to use SimpleDateFormat
or DateTimeFormatter
classes to convert Date from one representation to another.
QUESTION
With the sample code below I have made a test to understand the async and await mechanism in Swift. The sequence of processes is achieved. My test prints to the console do appear in the intended sequence (step 1-4). However, what puzzles me is that the test messages, which shall appear on the UI, do not show up in the intended sequence. Both messages (Message1
and Message2
) appear together at the end of the entire process after step 4. So why does Message1
not appear right after step 1 as coded?
ANSWER
Answered 2022-Feb-05 at 03:38You ask:
So why does Message1 not appear right after step 1 as coded?
Because you are blocking the main thread with your repeat
-while
loop. Your code is a perfect demonstration of why you should never block the main thread, as the UI cannot be updated until you free up the main thread. Any system events will be prevented, too. If you block the main thread for long enough, you even risk having your app unceremoniously killed by the watchdog process (designated with the termination code 0x8badf00d
, pronounced “ate bad food”).
Your code says:
QUESTION
I'm currently developing a program in which I use Java.util.Collection.parallelStream()
, and wondering if it's possible to make it more Multi-threaded.
I was wondering if using multiple map
might allow the Java.util.Collection.parallelStream()
to distribute the tasks better:
ANSWER
Answered 2022-Jan-30 at 08:21I looked into the Stream
source code. The result of a map operation is just fed into the next operation. So there is almost no difference between one big map()
call or several small map()
calls.
And for the map()
operation a parallel Stream
makes no difference at all. Meaning each input object will be processed until the end by the same Thread
in any case.
Also note: A parallel Stream
only splits up the work if the operation chain allows it and there is enough data to process. So for a small Collection
or a Collection
that allows no random access, a parallel Stream
behaves like a sequential Stream
.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install puzzles
You can use puzzles like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the puzzles component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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