kandi X-RAY | BRZ Summary
kandi X-RAY | BRZ Summary
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Top functions reviewed by kandi - BETA
- Search for orders
- Finds carrier
- Finds the formal formalities
- Request an access token
- Decrypt a ciphertext
- Calculate a portion of a byte array
- Create RSA private key
- Performs an HTTP PUT request
- Analyze the header and return the response header
- Sign a captcha
- Deserialize JSON from JSON
- Sign an order token
- Modify a signer
- Find order
- Finds aware for a given car IDs
- Download contract
- Send a send message
- Reject an order token
- Send a captcha for the given access token
- Find waybill for the given car ids
- Finds the contract uri
- Download file
- Verify data
- Sign data
- Encrypt a plaintext
- Performs a POST to a given URL
BRZ Key Features
BRZ Examples and Code Snippets
Community Discussions
Trending Discussions on BRZ
QUESTION
I am trying to write a LMC program that takes two integer inputs, divides them, and produces the quotient and remainder. To start, I broke down the problem into 4 stages:
1.Divide num1 by num2 to get the quotient, q.
2.Multiply q and num2 to get the exact multiplied number, and store it in num2.
3.Subtract num2 from num1, and store the answer in rem.
4.Output q and rem.
Here is the code I wrote:
...ANSWER
Answered 2021-Nov-25 at 21:50Is there a better way to do this?
Your approach is logical, but probably overkill. Just doing the division alone, and stopping when you can no longer subtract the divisor from the dividend will produce both the quotient and the remainder together.
For example, if you want to divide 13 by 4, then subtract 4 from 13 yielding 9, then subtract 4 from 9 yielding 5, then subtract 4 from 5 yielding 1, and now we stop as 4 is greater than 1 (we cannot subtract without going negative). The quotient is the number of times we were able to subtract 4 (which was 3 times), and the remainder is what's left after stopping, here, 1.
How can I make it work?
As far as why your code does infinite loop, it is probably that you're only looking for division that is exact, by using BRZ
. You should consider using BRP
instead, which will allow for a non-zero remainder. You should single step in the LMC debugger to see why it doesn't stop when you'd like it to.
QUESTION
"previousPasswords": [
"$2a$10$.6cY1diu9kkAhQCBxlVb7unBCxHGCblucOHp4g/z6rE9a3/YQEHqq",
"$2a$10$T.G1BZ3SCCY4p1H6sXlpz.daJuX6s/YbFReGmQlWIOMCZcwUPIhE6",
"$2a$10$ZeW2A6YQw4dI07PDwwql/.vA4tJdvkq9EAcduIEnpFuAzjvXURi5a",
"$2a$10$iuHu21hA9J55ai1gWrJ96OKfl7X0sD/FzT7nd0gKzw38NTYOXdiWG",
"$2a$10$ID/fYCOJ0KOb010f7OZf1ON7RNQJwcMT1px5dBpQx2.juoBugiEQe",
"$2a$10$lIvpPNK6lMs4CpAzBl1wZOjq9HF12lIffs7TybaWqo8v7g76KJ3s2",
"$2a$10$Brz/WRZGKBEzLJEpzrFEwuRccVAI1K7KEXfv5GVxFV4H34r9WhMke",
"$2a$10$QD/6DDQD2n1KWoYO6PBPtu4rp1HfX2sSy2uBbWj5d0tw.EmaEl/Yy",
"$2a$10$sP03DLwC.yPt.c3i.CdD0OmYBS6m6XQpPycuFE49GLPWvHEvjiBXW"
],
...ANSWER
Answered 2021-Oct-01 at 17:18I came up with this solution now its working
QUESTION
)
I'm trying to hide the text "Produktgrundpreis (falls vorhanden):" if the siblings child div is empty. That's how the site looks like atm
Here's the DOM Structure
...ANSWER
Answered 2021-Sep-27 at 16:21Since empty ('') is falsy value you can use false value check. You can also use trim if you think there can be space (' ')
QUESTION
I am working at this coding challenge:
Write a program for the Little Man Computer that allows the user to manage a list of values. It should start with an empty list and then process input as follows:
If the input is:
- less than 100: add this value to a list, unless the list already has 10 values, in which case the value is ignored
- 995: make the list empty
- 996: output the number of values the list currently has
- 997: output each value the list currently has, in the order they were added to it
- 998: output each value the list currently has, in reversed order
- 999: end the program
- Any other value is ignored
The processing of input values continues as long as the input value is not 999.
I'm having issues getting the code to print the stored list in forward order when 997 is input. I think I may have the ADD
and SUB
instructions confused. I also can't get the stored list to reset correctly when 995 is input.
Everything else I was able to program correctly.
Below is my code:
...ANSWER
Answered 2021-Jul-18 at 12:37The issues in your program can be categorised in:
- Issues related to labels that a good simulator should detect before running your program
- Issues related to program logic, that make the program produce the wrong output
- Issues related to code style
A good simulator should not accept the following errors:
PRINTF
label is not defined.There is a
brz printf
instruction, but that label is not defined, since---
makes it a comment. Obviously that---
needs to be removed for the label reference to be valid.LDIT
label is duplicate:The label LDIT is defined twice. This will have unreliable behaviour. A good simulator should give an error message about this, but other simulators will just take one definition and ignore the duplicates. Either way, the intention of the program is that one
STA LDIT
uses the first LDIT location and the secondSTA LDIT
uses the second LDIT location. If anything, this will not be what happens. So rename one of the two labels, and adjust one of theSTA LDIT
instructions accordingly.zero
label is undefined:The code to reset the counter refers to an undefined label
zero
. Again, good simulators will produce an error when loading the program, but others may silently use mailbox 0 instead, which leads to undesirable behaviour. So define thezero
label as
QUESTION
I am working on this challenge:
The program needs to accept a sequence of integers. It ends with number 999. The integers (except 999) are placed in a list. The integers must be less than or equal to 99. Any inputs greater than 99 are not placed in the list.
If the input would have more than ten numbers, only the first ten are stored.
999 is not part of the output.
I don't know how to limit the list length to ten (10) numbers. Also I don't know how to output the list in reverse order.
This is my code:
...ANSWER
Answered 2021-Jul-06 at 13:03The xx
in your program show that you haven't taken the hint from How can I store an unknown number of inputs in different addresses in LMC (little-man-computer)?
It explains how you can have self-modifying code to walk through an array -- either to store values or to load them.
In your attempt there is no section that deals with outputting.
For the start section of the program I would actually suggest to subtract first the 100 and then 899 (which amounts to 999). That way you can keep the (reducing) input in the accumulator without having to restore it.
Also, due to an ambiguity in the specification of LMC, it is not entirely "safe" to do a BRZ
right after a SUB
(this is because the content of the accumulator is undefined/unspecified when there is underflow, so in theory it could be 0). You should always first do a BRP
before doing a BRZ
in the branched code. However, as input cannot be greater than 999, a BRP
is enough to detect equality.
For the self modifying part, you can set an end-marker in your array data section, and define the LDA
and STA
instructions that would read/store a value at the end of the array. Whenever your code has that exact instruction, you know you have reached the end.
Here is how it can work:
QUESTION
I have already searched the Internet for my problem but nothing quite the same. I am quite new in Pandas.
I have a huge dataframe, around 800K of rows. Out of 800K of rows, 200K of them are duplicates that indicate an owner who owns multiple cars under the same SSN (may have a different name due to spelling and such). For example, below is my dataframe.
SSN is the key in determining they are the same person albeit the name might be different (or slightly different) :
...ANSWER
Answered 2021-Apr-22 at 02:49Hopefully this will help you get started. This should give you the channel
column you are looking for.
QUESTION
I am looking at this Little man computer problem:
- the first input determines the value for n, it is assumed this value will be equal to four, or greater
- Example: if the first input is eight (8), then eight subsequent inputs are requested. If the subsequent inputs number were 1, 0, 0, 1, 0, 0, 0, 0 then the output would be 9.
- n input values are provided by the user, one for each bit: The first of these is the least-significant bit. The n’th input is the most-significant bit.
My attempt:
...ANSWER
Answered 2021-Apr-10 at 11:46The code you have does not use the first input. Instead it uses FOUR
. This is the first thing to change, as you don't want to loop exactly four times, but as many times as your first input is.
Secondly, you don't need to store each next input in a separate mailbox. Instead you can immediately process the 0/1 input as it decides whether you want to add something to the result or not. So you only need to update the result depending on the input's 0/1 value. You don't need to store that 0/1 value itself -- so no need of A
, B
, C
...etc. Instead put the IN
instruction inside the loop.
Then remains what exactly you should add to the result when an input turns out to be 1. As the input is in reversed order (the least significant bits come first), you should keep track of a power of 2, which you double in each iteration of the loop. That will be the number to add to the result whenever you encounter an input of 1. Because that is how the binary system works. For instance if the input of digits is 1 1 0 1, then the calculation is:
input digit power of 2 to be added running sum 1 1 yes 1 1 2 yes 3 0 4 no 3 1 8 yes 11So here is the script for that. You can run it here: first run the code snippet (which starts the LMC simulator) and then use the controls in the right panel:
QUESTION
This code is a Little Man Computer program that Bubblesorts and uses input, output, and sorts itself and then repeats. This is the program but I would like to use Labels for all constants, variables, and branch target locations where the branch would go to to help simplify the code and make it more readable. I'm not sure what label names to use to improve maintainability. Numeric codes are not needed. Only the line number, labels, Mnemonic Data and comments.
...ANSWER
Answered 2020-Dec-02 at 19:49Just use the comments as inspiration for the labels. Lines that are not the target of any operation can go without labels. So for instance:
QUESTION
This is what I have so far but I can't get it to work. I need to have it input a dividend and a divisor and output the result along with the remainder. Example: if the input is 33 followed by 6 the output will be 5 followed by 3 since 33/6 is 5 remainder 3.
...ANSWER
Answered 2020-Nov-29 at 17:43Currently you correctly get the input, calculate the remainder and output it. You just miss the part where you calculate the quotient and output it. The quotient is really the number of times you jump back to the start of the loop. So, increment a counter in each iteration of the loop. Then when you exit the loop you'll have counted one too many, so for the quotient you would output one less than that value.
Other remarks:
It is not necessary to perform
LDA RESULT
if it immediately followsSTA RESULT
, since that value is still in the accumulator -- no need to reload it.There is no need to have
HLT
followed byHLT
. That second one will never be executed.It is not useful to say in comments what an LMC instruction does... For instance, "ask the user" is not a useful comment next to
INP
. Comments should explain something more -- something that is specific to this program. Most of your comments are just saying what someone could look up in a LMC language specification. That is not the purpose of comments.
So here is your code with the extra counter for getting the quotient, and with the above remarks taken into account. You can run it here.
QUESTION
I am looking at this Little man computer problem:
The user will enter first the size of the data, and then the individual numbers.
I have to print (
OUT
) excatcly what was input, followed by the max and the min of the data values
- First input: 2 // Number of DATA
- Second input: 5 // First DATA
- Third input: 7 // Second DATA
- Output: 2, 5, 7, 5(min), 7(max)
I have to print everything at the end (when the user finished to enter all the inputs)
My attempt: ...ANSWER
Answered 2020-Nov-25 at 17:58The self-modifying code pattern, that you have used to store the input, can also be used to output it. Instead of modifying the dynamic STO PRG
instruction, you would have a dynamic LDA PRG
instruction.
Your attempt shows no code for determining the minimum and maximum value. You can either collect this information during the input loop or during the output loop.
Please take into consideration these additional remarks:
- initialise the variables (that are not constants) with code, so that if the LMC is reset (without a complete re-assembly), it still works correctly.
- use more descriptive labels and variable names.
ST
andPRG
are quite obscure names...
So it could work like below. This code uses the LMC mnemonics as described on Wikipedia. So STA = STO and INP = IN. You can run the program here:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install BRZ
You can use BRZ like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the BRZ component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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