BRZ | Open platform

 by   maihaoche Java Version: Current License: No License

kandi X-RAY | BRZ Summary

kandi X-RAY | BRZ Summary

BRZ is a Java library. BRZ has no bugs, it has no vulnerabilities, it has build file available and it has low support. You can download it from GitHub.

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            kandi-support Support

              BRZ has a low active ecosystem.
              It has 6 star(s) with 2 fork(s). There are 7 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              BRZ has no issues reported. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of BRZ is current.

            kandi-Quality Quality

              BRZ has 0 bugs and 0 code smells.

            kandi-Security Security

              BRZ has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              BRZ code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              BRZ does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              BRZ releases are not available. You will need to build from source code and install.
              Build file is available. You can build the component from source.
              It has 1544 lines of code, 241 functions and 43 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed BRZ and discovered the below as its top functions. This is intended to give you an instant insight into BRZ implemented functionality, and help decide if they suit your requirements.
            • Search for orders
            • Finds carrier
            • Finds the formal formalities
            • Request an access token
            • Decrypt a ciphertext
            • Calculate a portion of a byte array
            • Create RSA private key
            • Performs an HTTP PUT request
            • Analyze the header and return the response header
            • Sign a captcha
            • Deserialize JSON from JSON
            • Sign an order token
            • Modify a signer
            • Find order
            • Finds aware for a given car IDs
            • Download contract
            • Send a send message
            • Reject an order token
            • Send a captcha for the given access token
            • Find waybill for the given car ids
            • Finds the contract uri
            • Download file
            • Verify data
            • Sign data
            • Encrypt a plaintext
            • Performs a POST to a given URL
            Get all kandi verified functions for this library.

            BRZ Key Features

            No Key Features are available at this moment for BRZ.

            BRZ Examples and Code Snippets

            No Code Snippets are available at this moment for BRZ.

            Community Discussions

            QUESTION

            How to produce dividend and remainder in a little man computer program?
            Asked 2021-Nov-25 at 23:06

            I am trying to write a LMC program that takes two integer inputs, divides them, and produces the quotient and remainder. To start, I broke down the problem into 4 stages:

            1.Divide num1 by num2 to get the quotient, q.

            2.Multiply q and num2 to get the exact multiplied number, and store it in num2.

            3.Subtract num2 from num1, and store the answer in rem.

            4.Output q and rem.

            Here is the code I wrote:

            ...

            ANSWER

            Answered 2021-Nov-25 at 21:50

            Is there a better way to do this?

            Your approach is logical, but probably overkill.  Just doing the division alone, and stopping when you can no longer subtract the divisor from the dividend will produce both the quotient and the remainder together.

            For example, if you want to divide 13 by 4, then subtract 4 from 13 yielding 9, then subtract 4 from 9 yielding 5, then subtract 4 from 5 yielding 1, and now we stop as 4 is greater than 1 (we cannot subtract without going negative).  The quotient is the number of times we were able to subtract 4 (which was 3 times), and the remainder is what's left after stopping, here, 1.

            How can I make it work?

            As far as why your code does infinite loop, it is probably that you're only looking for division that is exact, by using BRZ.  You should consider using BRP instead, which will allow for a non-zero remainder.  You should single step in the LMC debugger to see why it doesn't stop when you'd like it to.

            Source https://stackoverflow.com/questions/70117372

            QUESTION

            How can i compare a password with array of hash passowrds
            Asked 2021-Oct-01 at 17:18
            "previousPasswords": [
                    "$2a$10$.6cY1diu9kkAhQCBxlVb7unBCxHGCblucOHp4g/z6rE9a3/YQEHqq",
                    "$2a$10$T.G1BZ3SCCY4p1H6sXlpz.daJuX6s/YbFReGmQlWIOMCZcwUPIhE6",
                    "$2a$10$ZeW2A6YQw4dI07PDwwql/.vA4tJdvkq9EAcduIEnpFuAzjvXURi5a",
                    "$2a$10$iuHu21hA9J55ai1gWrJ96OKfl7X0sD/FzT7nd0gKzw38NTYOXdiWG",
                    "$2a$10$ID/fYCOJ0KOb010f7OZf1ON7RNQJwcMT1px5dBpQx2.juoBugiEQe",
                    "$2a$10$lIvpPNK6lMs4CpAzBl1wZOjq9HF12lIffs7TybaWqo8v7g76KJ3s2",
                    "$2a$10$Brz/WRZGKBEzLJEpzrFEwuRccVAI1K7KEXfv5GVxFV4H34r9WhMke",
                    "$2a$10$QD/6DDQD2n1KWoYO6PBPtu4rp1HfX2sSy2uBbWj5d0tw.EmaEl/Yy",
                    "$2a$10$sP03DLwC.yPt.c3i.CdD0OmYBS6m6XQpPycuFE49GLPWvHEvjiBXW"
                ],
            
            ...

            ANSWER

            Answered 2021-Oct-01 at 17:18

            I came up with this solution now its working

            Source https://stackoverflow.com/questions/69409314

            QUESTION

            display:none a div on condition if siblings child div is empty
            Asked 2021-Sep-27 at 22:11

            )

            I'm trying to hide the text "Produktgrundpreis (falls vorhanden):" if the siblings child div is empty. That's how the site looks like atm

            Here's the DOM Structure

            ...

            ANSWER

            Answered 2021-Sep-27 at 16:21

            Since empty ('') is falsy value you can use false value check. You can also use trim if you think there can be space (' ')

            Source https://stackoverflow.com/questions/69349836

            QUESTION

            Output and Reset Lists in LMC
            Asked 2021-Jul-18 at 21:25

            I am working at this coding challenge:

            Write a program for the Little Man Computer that allows the user to manage a list of values. It should start with an empty list and then process input as follows:

            If the input is:

            • less than 100: add this value to a list, unless the list already has 10 values, in which case the value is ignored
            • 995: make the list empty
            • 996: output the number of values the list currently has
            • 997: output each value the list currently has, in the order they were added to it
            • 998: output each value the list currently has, in reversed order
            • 999: end the program
            • Any other value is ignored

            The processing of input values continues as long as the input value is not 999.

            I'm having issues getting the code to print the stored list in forward order when 997 is input. I think I may have the ADD and SUB instructions confused. I also can't get the stored list to reset correctly when 995 is input.

            Everything else I was able to program correctly.

            Below is my code:

            ...

            ANSWER

            Answered 2021-Jul-18 at 12:37

            The issues in your program can be categorised in:

            1. Issues related to labels that a good simulator should detect before running your program
            2. Issues related to program logic, that make the program produce the wrong output
            3. Issues related to code style
            1. Labels

            A good simulator should not accept the following errors:

            • PRINTF label is not defined.

              There is a brz printf instruction, but that label is not defined, since --- makes it a comment. Obviously that --- needs to be removed for the label reference to be valid.

            • LDIT label is duplicate:

              The label LDIT is defined twice. This will have unreliable behaviour. A good simulator should give an error message about this, but other simulators will just take one definition and ignore the duplicates. Either way, the intention of the program is that one STA LDIT uses the first LDIT location and the second STA LDIT uses the second LDIT location. If anything, this will not be what happens. So rename one of the two labels, and adjust one of the STA LDIT instructions accordingly.

            • zero label is undefined:

              The code to reset the counter refers to an undefined label zero. Again, good simulators will produce an error when loading the program, but others may silently use mailbox 0 instead, which leads to undesirable behaviour. So define the zero label as

            Source https://stackoverflow.com/questions/68426833

            QUESTION

            Programming arrays in LMC
            Asked 2021-Jul-06 at 13:03

            I am working on this challenge:

            The program needs to accept a sequence of integers. It ends with number 999. The integers (except 999) are placed in a list. The integers must be less than or equal to 99. Any inputs greater than 99 are not placed in the list.

            If the input would have more than ten numbers, only the first ten are stored.

            999 is not part of the output.

            I don't know how to limit the list length to ten (10) numbers. Also I don't know how to output the list in reverse order.

            This is my code:

            ...

            ANSWER

            Answered 2021-Jul-06 at 13:03

            The xx in your program show that you haven't taken the hint from How can I store an unknown number of inputs in different addresses in LMC (little-man-computer)?

            It explains how you can have self-modifying code to walk through an array -- either to store values or to load them.

            In your attempt there is no section that deals with outputting.

            For the start section of the program I would actually suggest to subtract first the 100 and then 899 (which amounts to 999). That way you can keep the (reducing) input in the accumulator without having to restore it.

            Also, due to an ambiguity in the specification of LMC, it is not entirely "safe" to do a BRZ right after a SUB (this is because the content of the accumulator is undefined/unspecified when there is underflow, so in theory it could be 0). You should always first do a BRP before doing a BRZ in the branched code. However, as input cannot be greater than 999, a BRP is enough to detect equality.

            For the self modifying part, you can set an end-marker in your array data section, and define the LDA and STA instructions that would read/store a value at the end of the array. Whenever your code has that exact instruction, you know you have reached the end.

            Here is how it can work:

            Source https://stackoverflow.com/questions/68265100

            QUESTION

            Applying values to a column based on value comparison in other columns across different rows in Pandas
            Asked 2021-Apr-22 at 02:49

            I have already searched the Internet for my problem but nothing quite the same. I am quite new in Pandas.

            I have a huge dataframe, around 800K of rows. Out of 800K of rows, 200K of them are duplicates that indicate an owner who owns multiple cars under the same SSN (may have a different name due to spelling and such). For example, below is my dataframe.

            SSN is the key in determining they are the same person albeit the name might be different (or slightly different) :

            ...

            ANSWER

            Answered 2021-Apr-22 at 02:49

            Hopefully this will help you get started. This should give you the channel column you are looking for.

            Source https://stackoverflow.com/questions/67205700

            QUESTION

            Convert n-bit binary to base 10 number
            Asked 2021-Apr-10 at 11:46

            I am looking at this Little man computer problem:

            • the first input determines the value for n, it is assumed this value will be equal to four, or greater
            • Example: if the first input is eight (8), then eight subsequent inputs are requested. If the subsequent inputs number were 1, 0, 0, 1, 0, 0, 0, 0 then the output would be 9.
            • n input values are provided by the user, one for each bit: The first of these is the least-significant bit. The n’th input is the most-significant bit.

            My attempt:

            ...

            ANSWER

            Answered 2021-Apr-10 at 11:46

            The code you have does not use the first input. Instead it uses FOUR. This is the first thing to change, as you don't want to loop exactly four times, but as many times as your first input is.

            Secondly, you don't need to store each next input in a separate mailbox. Instead you can immediately process the 0/1 input as it decides whether you want to add something to the result or not. So you only need to update the result depending on the input's 0/1 value. You don't need to store that 0/1 value itself -- so no need of A, B, C...etc. Instead put the IN instruction inside the loop.

            Then remains what exactly you should add to the result when an input turns out to be 1. As the input is in reversed order (the least significant bits come first), you should keep track of a power of 2, which you double in each iteration of the loop. That will be the number to add to the result whenever you encounter an input of 1. Because that is how the binary system works. For instance if the input of digits is 1 1 0 1, then the calculation is:

            input digit power of 2 to be added running sum 1 1 yes 1 1 2 yes 3 0 4 no 3 1 8 yes 11

            So here is the script for that. You can run it here: first run the code snippet (which starts the LMC simulator) and then use the controls in the right panel:

            Source https://stackoverflow.com/questions/66992045

            QUESTION

            Want to use Labels to simplify Little Man Computer Program BubbleSort
            Asked 2020-Dec-02 at 19:49

            This code is a Little Man Computer program that Bubblesorts and uses input, output, and sorts itself and then repeats. This is the program but I would like to use Labels for all constants, variables, and branch target locations where the branch would go to to help simplify the code and make it more readable. I'm not sure what label names to use to improve maintainability. Numeric codes are not needed. Only the line number, labels, Mnemonic Data and comments.

            ...

            ANSWER

            Answered 2020-Dec-02 at 19:49

            Just use the comments as inspiration for the labels. Lines that are not the target of any operation can go without labels. So for instance:

            Source https://stackoverflow.com/questions/64848108

            QUESTION

            Little Main Computer program to display quotient followed by remainder
            Asked 2020-Nov-29 at 17:43

            This is what I have so far but I can't get it to work. I need to have it input a dividend and a divisor and output the result along with the remainder. Example: if the input is 33 followed by 6 the output will be 5 followed by 3 since 33/6 is 5 remainder 3.

            ...

            ANSWER

            Answered 2020-Nov-29 at 17:43

            Currently you correctly get the input, calculate the remainder and output it. You just miss the part where you calculate the quotient and output it. The quotient is really the number of times you jump back to the start of the loop. So, increment a counter in each iteration of the loop. Then when you exit the loop you'll have counted one too many, so for the quotient you would output one less than that value.

            Other remarks:

            • It is not necessary to perform LDA RESULT if it immediately follows STA RESULT, since that value is still in the accumulator -- no need to reload it.

            • There is no need to have HLT followed by HLT. That second one will never be executed.

            • It is not useful to say in comments what an LMC instruction does... For instance, "ask the user" is not a useful comment next to INP. Comments should explain something more -- something that is specific to this program. Most of your comments are just saying what someone could look up in a LMC language specification. That is not the purpose of comments.

            So here is your code with the extra counter for getting the quotient, and with the above remarks taken into account. You can run it here.

            Source https://stackoverflow.com/questions/65052851

            QUESTION

            How to print a list of values + max/min
            Asked 2020-Nov-25 at 18:05

            I am looking at this Little man computer problem:

            1. The user will enter first the size of the data, and then the individual numbers.

            2. I have to print (OUT) excatcly what was input, followed by the max and the min of the data values

            Example:
            • First input: 2 // Number of DATA
            • Second input: 5 // First DATA
            • Third input: 7 // Second DATA
            • Output: 2, 5, 7, 5(min), 7(max)

            I have to print everything at the end (when the user finished to enter all the inputs)

            My attempt: ...

            ANSWER

            Answered 2020-Nov-25 at 17:58

            The self-modifying code pattern, that you have used to store the input, can also be used to output it. Instead of modifying the dynamic STO PRG instruction, you would have a dynamic LDA PRG instruction.

            Your attempt shows no code for determining the minimum and maximum value. You can either collect this information during the input loop or during the output loop.

            Please take into consideration these additional remarks:

            • initialise the variables (that are not constants) with code, so that if the LMC is reset (without a complete re-assembly), it still works correctly.
            • use more descriptive labels and variable names. ST and PRG are quite obscure names...

            So it could work like below. This code uses the LMC mnemonics as described on Wikipedia. So STA = STO and INP = IN. You can run the program here:

            Source https://stackoverflow.com/questions/64998410

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install BRZ

            You can download it from GitHub.
            You can use BRZ like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the BRZ component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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