biweekly | biweekly is an iCalendar library written in Java

 by   mangstadt Java Version: 0.6.7 License: BSD-2-Clause

kandi X-RAY | biweekly Summary

kandi X-RAY | biweekly Summary

biweekly is a Java library typically used in Utilities applications. biweekly has build file available, it has a Permissive License and it has high support. However biweekly has 16 bugs and it has 5 vulnerabilities. You can download it from GitHub, Maven.

biweekly is an iCalendar library written in Java. The project aims to provide a well documented, easy to use API for reading and writing iCalendar data.
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            kandi-support Support

              biweekly has a highly active ecosystem.
              It has 291 star(s) with 43 fork(s). There are 11 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 7 open issues and 94 have been closed. On average issues are closed in 300 days. There are no pull requests.
              It has a positive sentiment in the developer community.
              The latest version of biweekly is 0.6.7

            kandi-Quality Quality

              OutlinedDot
              biweekly has 16 bugs (2 blocker, 1 critical, 6 major, 7 minor) and 3416 code smells.

            kandi-Security Security

              biweekly has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              OutlinedDot
              biweekly code analysis shows 5 unresolved vulnerabilities (5 blocker, 0 critical, 0 major, 0 minor).
              There are 7 security hotspots that need review.

            kandi-License License

              biweekly is licensed under the BSD-2-Clause License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              biweekly releases are not available. You will need to build from source code and install.
              Deployable package is available in Maven.
              Build file is available. You can build the component from source.
              Installation instructions, examples and code snippets are available.
              biweekly saves you 43862 person hours of effort in developing the same functionality from scratch.
              It has 51737 lines of code, 4571 functions and 466 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed biweekly and discovered the below as its top functions. This is intended to give you an instant insight into biweekly implemented functionality, and help decide if they suit your requirements.
            • Parses the given XML element
            • Parse BYDAY rules
            • Parses the first value
            • Parses WKST
            • Parse the recurrence dates
            • Creates an exception which represents the missing XML elements
            • Writes a date as a java property
            • Parse a duration string
            • Parse a text value
            • Gets the list of free bus properties
            • Writes the data for a calendar
            • Advance to the given date
            • Parse the recipient text
            • Returns a 16 - bit integer representation of this instance
            • Validates this alarm
            • Determines whether this person is equal to or not
            • Writes the data of a recurrenceDates property
            • Encodes the provided data
            • Validates the ICal components
            • Writes the values of a recurrence property
            • Overrides the default values for RSVP
            • Parses a JCalValue
            • Decodes the provided data
            • Checks if this recurrence matches another
            • Validates the given ICal component
            • Parses a text value
            Get all kandi verified functions for this library.

            biweekly Key Features

            No Key Features are available at this moment for biweekly.

            biweekly Examples and Code Snippets

            No Code Snippets are available at this moment for biweekly.

            Community Discussions

            QUESTION

            Group dataframe rows by creating a unique ID column based on the amount of time passed between entries and variable values
            Asked 2021-Jun-10 at 16:18

            I'm trying to group the rows of my dataframe into "courses" when the same variables appear at regular date intervals. When there is a gap in time frequency or when one of variables change I would like to give it a new course ID.

            To give an example, my data looks something like this:

            ...

            ANSWER

            Answered 2021-Jun-10 at 16:18

            Here's a dplyr approach that calculates the gap and rolling avg gap within each Name/Item group, then flags large gaps, and assigns a new group for each large gap or change in Name or Item.

            Source https://stackoverflow.com/questions/67922878

            QUESTION

            Table css is messing up on shrinking the window
            Asked 2021-May-13 at 06:21

            My code is working fine and displaying the tables with css well applied but when I am shrinking the window table is getting messed up with different columns taking up different space (I have attached in screenshot). Basically I want the first column which is without the checkbox to be intact(sticky) and rest columns to take equal space with a scroll enabled when I shrink the window . How do I fix that up, Can anyone please help?

            Is there any way I keep the table container width as it is there in desktop view and just put a scroller in the mobile view with first column fixed and not shrink the tables?

            like in this example https://codepen.io/paulobrien/pen/LBrMxa

            ...

            ANSWER

            Answered 2021-May-12 at 06:33

            You cannot do much only with css as you are trying to make 4 table fit next to each other.

            I would recommand you to use jQuery. After you can add this code in readyand resize event to make sure that the height will be adapted correctly.

            Demo:

            Source https://stackoverflow.com/questions/67399332

            QUESTION

            How can I make my tables vertically aligned in mobile view?
            Asked 2021-May-10 at 05:32

            I have tables which are horizontally aligned side by side on desktop view for both the resolution 1920 and 1280, when i change the screen resolution to Mobile version the tables get cluttered and overlap on each other, I want it to be vertically aligned eg. 1 table on on every row centre aligned. How can that be done ? I have put the code for horizontal aligned in desktop version.

            ...

            ANSWER

            Answered 2021-May-10 at 05:32

            You're already using a valid solution with media queries. Add this for screens less than or equal to 600px.

            Source https://stackoverflow.com/questions/67465150

            QUESTION

            Not Able to Understand how the following code is working
            Asked 2021-May-01 at 19:25

            https://leetcode.com/contest/biweekly-contest-51/problems/replace-all-digits-with-characters/ I tried to solve this question but i was not able to do so so i looked into the discussions and i was able to find the answer but i was still not able to understand how the third line of the code is giving me the ouput.I know this a very basic doubt but i was not able to get it. please help

            ...

            ANSWER

            Answered 2021-May-01 at 19:25

            The task is essentially asking you to replace every digit in the string with shift(s[i-1], s[i]).

            So for every odd index i, you convert s[i] from a character to an integer (by subtracting '0') and adding that to the previous character s[i-1]. Another way to write the third line is like this:

            Source https://stackoverflow.com/questions/67349833

            QUESTION

            Why CSS Media query for width of table-rows not working?
            Asked 2021-Apr-30 at 10:42

            This is my code, I want to reduce the width of all the rows in table (except for first table) when the size of screen is more than 1000px. I tried this but this media query is not seem to be working. And also I want the bottom border of the table to be rounded, with the code I tried except for the left-most all the border-bottom radius is getting rounded Can anyone tell what I am missing? I have read many answers none of them seem to be working

            ...

            ANSWER

            Answered 2021-Apr-30 at 10:42

            You were using .table-container, not .table_container from above. Just tried this and it works as expected. Also make sure to add it to the bottom of the stylesheet.

            Source https://stackoverflow.com/questions/67315607

            QUESTION

            Start date/end date for biweekly payroll frequency - Swift
            Asked 2020-Nov-27 at 02:24

            I have to present time trackings summary for specific payroll frequency periods: monthly, weekly, biweekly. I did find a way to get start date and end date for current week or current month ex.

            ...

            ANSWER

            Answered 2020-Nov-26 at 06:50

            I don't know if there is an easier way to accomplish what you want but this is what I came up with. First I get all days in the same year. Then I create an array with 26 subarrays and group dates for every 2 weeks. Then I create an array of date intervals using the first and last date of each subarray.

            Source https://stackoverflow.com/questions/65014793

            QUESTION

            DateTimeFormatter throwing exception "could not be parsed at index 0"
            Asked 2020-Nov-12 at 02:02

            I keep on getting an error from running this code.

            java.time.format.DateTimeParseException: Text 'Jan 03, 2020' could not be parsed at index 0

            ...

            ANSWER

            Answered 2020-Nov-12 at 02:02

            You should use MMM instead of LLL for month parsing.

            Updated:

            I was wrong about my answer above. It's the half of answer.

            The deal is DateTimeFormatter.ofPattern(myFormat) uses default Locale. For non-US locales, it doesn't work. So you need to specify the locale according to your pattern.

            Source https://stackoverflow.com/questions/64796523

            QUESTION

            regular expression to segregate chat between two person in R
            Asked 2020-Nov-05 at 15:01

            I have a string:

            "mary g: hello dr ydeen how can i help you dany: hi is there a place within the physician portal to see how many vacation and sick hours i currently have thank you so much for your time mary g: yes you can view that in your secure hr page under benefits summary first youll have to enter the last four of your ssn on the right hand side youll be directed to your secure hr page and on the left hand side there will be a list of links select benefits summary mary g: you can also view it on each pay stub biweekly dany: i thought it might be on the paystub i can never seem to find it there : checking out benefits summary now dany: great i see vacation and sick time here to confirm this is how much i have currently accrued mary g: youll have to select the quotprintviewquot option on the paycheck and the accruals are listed under your earnings mary g: great yes thats correct mary g: its your accruals as of the last pay period mary g: so currently its accurate up until dany: perfect thank you so much and noted regarding printview dany: thanks so much for your help mary g: my pleasure anything else i can help you with dany: thats all thanks again mary g: have a great day"

            I want to extract all chat written by mary g, I tried below regex but its only giving first line string

            ...

            ANSWER

            Answered 2020-Nov-05 at 14:54

            In the example data, there are more than 2 whitespace chars before the name and the colon. In that case you can use a positive lookahead assertion to check what follows is either 2 whitespace chars followed by a : with at least a single [A-Za-z] before it, or the end of the string.

            Source https://stackoverflow.com/questions/64699252

            QUESTION

            Mysql group data biweekly
            Asked 2020-Oct-07 at 16:15

            I'm currently using Laravel eloquent for my database logic implementation. I have data that needs to be grouped: weekly, bi-weekly and monthly.

            Eloquent provides convenient methods for grouping data weekly and monthly

            i.e for grouping data weekly, this works perfectly:

            ...

            ANSWER

            Answered 2020-Oct-07 at 16:15
            ->groupBy(\DB::raw('WEEK(created_at) DIV 2'))
            

            Source https://stackoverflow.com/questions/64245346

            QUESTION

            Two similar codes: one throws TLE while the other doesn't. Can't figure out the difference between both
            Asked 2020-Oct-06 at 12:30

            I was solving a problem during the biweekly contest on Leetcode.

            Link: https://leetcode.com/problems/find-servers-that-handled-most-number-of-requests/

            I first tried a brute force but I was sceptical if it would work. And as it turned out, I ended up with a TLE. Later after having solved the question using TreeSet and PQs, I found one submission which was almost a replica of my own brute force attempt. And this one was accepted. I was unable to find any differences. Can anyone point them out to me?

            MY CODE:

            ...

            ANSWER

            Answered 2020-Oct-06 at 12:30

            The only (barely) meaningful difference I can see is that you access arrival[i] and load[i] each time inside your j loop, whereas the accepted solution puts them in variables outside the loop and refers to those variables every time, which means their inner loop is (apparently) slightly faster. Incredibly, for this specific Leetcode problem, this does seem to make the difference between Accepted and Time Limit Exceeded.

            Specifically, I rewrote this loop in your code:

            Source https://stackoverflow.com/questions/64221110

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install biweekly

            biweekly uses Maven as its build tool, and adheres to its convensions. To build the project: mvn compile To run the unit tests: mvn test To build a JAR: mvn package.

            Support

            You have some options:. Please submit bug reports and feature requests to the issue tracker.
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            https://github.com/mangstadt/biweekly.git

          • CLI

            gh repo clone mangstadt/biweekly

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            git@github.com:mangstadt/biweekly.git

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